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Interpretations of probability
Kolmogorov’s axioms
Midterm
• 22 nd^ Mar, F2~F3, MMW LT
• Bring calculator and blank papers.
• Close-book and close-note exam.
• No make-up exam
• Coverage:
– Lecture 1 to 15.
– Tutorial 1 to 7.
– Homework 1 to 3.
Last week: Conditional probability
- If we are given an addition information that the outcome is in event B, then we can update the likelihood to |AB|/ |B|.
- If Pr(B) is nonzero, then we define the conditional probability of A given B by Pr(A|B) = Pr(AB)/Pr(B).
A B
At the beginning, the probability of event A is |A| / ||, assuming that all outcomes in are equally likely.
Disjoint events and independent
events
• If two events E and F are disjoint, i.e., EF=,
– then they cannot occur at the same time.
– Pr(E F) = Pr(E) + Pr(F)
– Pr(E F) = 0
• If two event A and B are statistically
independent, then
– Pr(AB) = Pr(A)Pr(B),
– AB is in general not empty.
a E
F
a A
B
The Bayes’ rule
• Let A and B be two events. Suppose that the
probability of B is nonzero.
• Probability of A given B can be computed from
the probability of B given A by
Example: The paradox of HIV test
• There is a test for AIDS.
– If a person is infected, the test will be positive 99%
of the time.
– If a person is not infect, the test will be negative
98% of the time.
• Suppose person A take the test, and the result
is positive. Person A comes from a population
with infection rate 0.5%. What is the chance
that A is infected? This is called a priori probability
INTERPRETATIONS OF PROBABILITY
Classical interpretation
• Usually credited to Laplace.
• All outcomes in the sample space have the
same probability.
• Pr(E) = |E| / | |
• It requires that the sample space is a finite set.
• Calculation of probability reduces to counting.
• The classical interpretation cannot model biased
coin, loaded dice, etc.
Subjective interpretation
• Probabilities are defined by personal
preference, or personal belief.
• Example: “2013年 3 月 1 日 14:47 長遠房屋策略督導委員會
• Used in social science, decision making, etc.
Example of subjective probability
• There are two suspects X and Y in a murder case.
Both of them are on the run. Initially, X and Y
have the same evidence.
• After more detailed investigation, it is known that
the murderer has blood type B.
• We also know that suspect X has blood type B,
but we do not know the blood type of suspect Y.
• It is also known that 10% of the population has
blood type B.
• What is the probability that Y is the murderer
given the new information?
Geometric probability
• A.k.a. “stochastic geometry”
• The sample space is a geometric object, like a
line segment, circle, square, sphere, etc.
• Pick a point randomly in the sample space.
The probability that the chosen point falls
within a certain region is directly proportional
to the area/volume of the region.
– This is the uniform distribution on the geometric
object.
Example
• Pick a point at random on a circle of radius 1.
• For 0<r<1, this point falls within a circle of
radius r with probability r^2 / .
• The probability of picking
particular point is zero,
because a point as zero area.
Circle of radius 1
Probability measure
- Regardless of the interpretations, the calculations of
probabilities must satisfy some basic rules.
- Three of the very basic rules are identified by Russian
mathematician Kolmogorov as the axioms of probability.
- In Kolmogorov’s formulation, we assign a real number to an
event. A probability measure is a function which accepts an event as an input and output a real number.
- As we saw in the example of geometric probability, it is sometime more convenient to assign probabilities to events instead of points in the sample space.
- We construct a probability model after assigning probability
to sufficiently large number of basic events. The other probability events can be computed by union, intersection, and complements of the basic events.
Kolmogorov’s axioms
• Let be a sample space, which may be finite or
infinite.
• A probability measure assigns real numbers to
some events in, satisfying the following
axioms:
Pr(E) is a real number between 0 and 1.
Pr() = 1
For any sequence of pairwise disjoint event E 1 , E 2 , E 3 , …, we have
Pr (E 1 E 2 E 3 …) = Pr(E 1 ) + Pr(E 2 ) + Pr(E 3 ) + …