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The solutions to quiz 10 for math 106a,b - calculus ii, winter 2008. It includes the calculation of the interval of convergence for a given series and the derivation of the power series representation of arctan x. The document also shows how to use the power series representation to evaluate the limit of arctan x as x approaches 0.
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QUIZ 10
Show ALL your work CAREFULLY.
(a) Find the interval of convergence of the following infinite series [Do not forget to check the endpoints!]. โ^ โ k=
(4x)k k^2
Consider
k^ limโโ
| 4 x|k+ (k + 1)^2
k^2 | 4 x|k^ = (^) klimโโ | 4 x|
k k + 1
= | 4 x| (^) klimโโ
k k + 1
= | 4 x|.
By the Ratio Test, the series converges if | 4 x| < 1 , i.e., โ 1 < 4 x < 1 or โ 14 < x < 14. When x = 14 , the series becomes
k^2 which is known to converge. When^ x^ =^ โ^ 1 โ 4 , the series becomes (โ1)k k^2 which converges since the associated series of absolute values^
k^2 converges. Hence, the interval of convergence is [โ 14 , 14 ].
(b) Recall that 1 1 โ t = 1 + t + t^2 + t^3 + t^4 + ... for |t| < 1.
Use this to obtain a power series representation of arctan x. [What is the derivative of arctan x?]
By letting t = โx^2 , we have 1 1 + x^2 = 1^ โ^ x
(^2) + x (^4) โ x (^6) + ... for |x| < 1.
It follows that
arctan x =
1 + x^2 dx = x โ x^3 3
x^5 5
x^7 7
n=
(โ1)n+1x^2 nโ^1 2 n โ 1 for^ |x|^ <^1.
(c) Use (b) to evaluate limxโ 0 arctanx x.
Using the power series representation of arctan x from (b), we have
x^ limโ 0
arctan x x = lim xโ 0
x
x โ x^3 3
x^5 5
x^7 7
= lim xโ 0
1 โ x
2 3
4 5 โ x
6 7
Date: April 4, 2008. 1