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theorem one point three from book
Typology: Exercises
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Thm 1. (PF) Let a, b, and c ∈ ℤ and 𝑎|𝑏 𝑎𝑛𝑑 𝑎|𝑐. We need to show 𝑎|𝑏𝑐. By definition of divisibility, ∃ 𝑘, 𝑙 ∈ ℤ 𝑠. 𝑡. 𝑏 = 𝑎𝑘 𝑎𝑛𝑑 𝑐 = 𝑎𝑙. Now, 𝑏𝑐 = (𝑎𝑘)(𝑎𝑙) by substitution = 𝑎(𝑎𝑘𝑙) by algebra Note that 𝑎𝑘𝑙 ∈ ℤ, 𝑠𝑖𝑛𝑐𝑒 𝑎, 𝑘, 𝑙 ∈ ℤ 𝑎𝑛𝑑 ℤ 𝑖𝑠 𝑐𝑙𝑜𝑠𝑒𝑑 𝑢𝑛𝑑𝑒𝑟 𝑚𝑢𝑙𝑡𝑖𝑝𝑙𝑖𝑐𝑎𝑡𝑖𝑜𝑛. ∴ 𝑎|𝑏𝑐 by definition of divisibility, which is what was to be proven. ∎