Quantum Optics Lecture 27: Quantum Field Theory of Light and Photon Tricks - Prof. Charles, Study notes of Optics

A portion of lecture notes from a university-level physics course on quantum optics. The lecture, titled 'quantum field theory', discusses the application of quantum theory to the behavior of light and photons. The professor outlines the intuition behind treating the electromagnetic field as a quantum field, the problem of handling an infinite number of photons, and the solution through mode expansion. The lecture also covers the concept of quantum states of light, including coherent and fock states, and the phenomenon of entangled field modes.

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Phys 531 Lecture 27 1 December 2005
Quantum Optics
Last time, discussed photon optics
Light energy comes in units of ~ω
particles called photons
observable with good detector
One consequence: light is intrinsically noisy
Today: introduce proper quantum theory
Quantum field theory of light
Note, this work recognized with 2005 Nobel prize
1
Outline:
Quantum fields
Mode expansion
Quantum states of light
Photon tricks
Do need some QM for this
Material won’t be on final
Warning: derivations today not rigorous,
some definitions simplified
Consult Scully and Zubairy for real deal
Next time: review . . . bring questions!
2
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
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pf12

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Phys 531 Lecture 27 1 December 2005

Quantum Optics

Last time, discussed photon optics

Light energy comes in units of ℏω particles called photons observable with good detector

One consequence: light is intrinsically noisy

Today: introduce proper quantum theory Quantum field theory of light

Note, this work recognized with 2005 Nobel prize 1

Outline:

  • Quantum fields
  • Mode expansion
  • Quantum states of light
  • Photon tricks

Do need some QM for this Material won’t be on final

Warning: derivations today not rigorous, some definitions simplified Consult Scully and Zubairy for real deal

Next time: review... bring questions!

Quantum Field Theory

Want proper quantum theory for photon

From last time, expect E(r) ∼ wave function ψ(r)

Since:

  • Probability ∝ |E|^2
  • Polarization analogous to spin
  • E exhibits interference like ψ
  • Wave equation ∼ Schrodinger equation

3

Intuition is right, but one problem

Number of photons is indefinite: photons easy to create and destroy

“Normal” QM assumes fixed N N = number of particles

Problem not just that N is unknown:

Can have quantum system in superposition

|ψ〉 =

√^1

( |atom + photon〉 + |excited atom〉

)

Photon in superposition of existing or not!

Could measure this state with polarizer along x

Imagine sending repeated pulses: each pulse in state Ψ

Each time get either 100% or 0% transmission unpredictable per pulse

Works even if EX and EY are classical states with many photons Simple version of Schrodinger’s cat

Could also have superpositions of beam position, frequency, etc.

7

Mode Expansion

Still have problem that E = E(r)

How to handle Ψ[E(r))]?

Solve by decomposing field into modes Usually, mode = plane wave

Easier to work inside a box, volume V

Then only discrete values of k allowed Get sums instead of integrals

Main advantage: makes normalization easier

Can write any E(r, t) as

E(r, t) =

∑ k

Akei(k·r−ωkt)

so state of field uniquely specified by {Ak}’s

Each mode k = independent degree of freedom Do QM on each independently

Treat each Ak as independent quantum variable Now a simple variable like X for a particle

9

But still one issue: Ak is complex

Really

E(r, t) =

∑ k

Re [Ak] cos (k · r − ωkt)

− Im[Ak] sin (k · r − ωkt)

Real and imaginary part of Ak both needed really two quantum variables per mode

Define

qk =

√  0 V 2 ℏωk

Re Ak pk =

√  0 V 2 ℏωk

ImAk

Two main results:

(1) Energy eigenstates are En = ℏω(n + 12 ) for integer n

⇒ photons!

(2) q and p don’t commute: [q, p] =

i 2 for our scale factors

Then can’t know q and p simultaneously:

∆q∆p ≥ 1 4 13

What do q and p correspond to physically?

Have A ∝ q + ip = amplitude of mode

Field ∝ q cos(k · r − ωt) − p sin(k · r − ωt)

So q is amplitude of wave ∼ cos() p is amplitude of wave ∼ sin()

Call components “quadratures” of wave

Of course, arbitrary which is which usually imagine a “reference oscillator” ∼ cos Define modes relative to it

Quantum States of Light

Since ∆q∆p ≥ 1 /4, amplitudes can’t have definite values

Draw picture: Say 〈q〉 large, 〈p〉 = 0 and ∆q  ∆p

E

t Amplitude of wave is uncertain

15

Or, if 〈q〉 large but ∆q  ∆p:

E

t

Amplitude well-defined, but phase uncertain

Question: What if 〈p〉 and ∆q were large, and 〈q〉 and ∆p were small? Would the phase or amplitude be more certain?

What is uncertainty in N?

Have N ' q^2 + p^2

So ∆N '

 

( ∂N ∂q

) 2 ∆q^2 +

( ∂N ∂p

) 2 ∆p^2

 

1 / 2

[ (2q)^2 ∆q^2 + (2p)^2 ∆p^2

] 1 / 2

( q^2 + p^2

) 1 / 2

' N 1 /^2

since ∆q = ∆p = 1/ 2

Same quantum noise from last time!

19

If ∆q 6 = ∆p, called “squeezed state” Generally don’t have ∆N = N 1 /^2

Useful for precision interferometry:

  • reduce noise in component measured
  • increase noise in component not measured

Generate squeezed states in nonlinear crystals Rather difficult to achieve

Local expert: Olivier Pfister

Can have coherent state with α = 0

Then 〈N 〉 = 0: no photons present Called vacuum state

Electric field also zero on average But still have fluctuations ∆q = ∆p = 1/2:

E

t

Fluctuations called vacuum noise Help explain spontaneous emission 21

Another possible state: Fock state

Has definite energy (N + 1/2)ℏω → mode contains N photons

Both ∆q and ∆p large, = (^12)

2 N + 1

E

t

Note vacuum state is also a Fock state

Most common nonclassical source: “Parametric down conversion”

Use special crystal with nonlinear interactions

Can “split” one photon into two: ω 0 → ω 1 + ω 2 with ω 0 = ω 1 + ω 2 (conserve energy) k 0 = k 1 + k 2 (conserve momentum) k 1

k 2

k 0

25

Input pulse (ω 0 ) in coherent state

Produces output pulse of form

Ψout =

∑ n

cnΨn(k 1 )Ψn(k 2 )

where Ψn(k) is Fock state for mode k

Typically operate with c 0 ≈ 1, c 1 small, higher c’s negligible

Then usually get nothing, but sometimes get pair of single photons

Polarization depends on crystal setup

possible to produce state √^1 2

(X 1 Y 2 + Y 1 X 2 )

One way:

k 1 k 0

k 2

X Y

Y X

Crystals thin, can’t tell where photons emitted

27

Then say modes are entangled quantum states not separable

Gives interesting effects:

  • Detect one photon, know that other is present Acts ≈ like perfect 1-photon source (don’t need entanglement)
  • Violate Bell’s inequality
  • Send messages immune to eavesdropping (quantum cryptography)
  • Transfer arbitrary quantum state (quantum teleportation)

Before measurement, total field state is

√^1 2

(aX 1 Y 2 X 3 + aY 1 X 2 X 3 + bX 1 Y 2 X 3 + bY 1 X 2 Y 3 )

Rewrite by adding and subtracting many terms:

1 23 /^2

( aY 1 X 2 X 3 + aY 1 Y 2 Y 3 + bX 1 X 2 X 3 + bX 1 Y 2 Y 3 +aY 1 X 2 X 3 − aY 1 Y 2 Y 3 − bX 1 X 2 X 3 + bX 1 Y 2 Y 3

+aX 1 X 2 Y 3 + aX 1 Y 2 X 3 + bX 1 X 2 Y 3 + bY 1 Y 2 X 3

−aX 1 X 2 Y 3 + aX 1 Y 2 X 3 + bX 1 X 2 Y 3 − bY 1 Y 2 X 3

)

31

This factors into

1 23 /^2

[ (aY 1 + bX 1 )(X 2 X 3 + Y 2 Y 3 ) +(aY 1 − bX 1 )(X 2 X 3 − Y 2 Y 3 )

+(aX 1 + bY 1 )(X 2 Y 3 + Y 2 X 3 )

−(aX 1 − bY 1 )(X 2 Y 3 − Y 2 X 3 )

]

or 1 2

[ (aY 1 + bX 1 )ΨA + (aY 1 − bX 1 )ΨB

  • (aX 1 + bY 1 )ΨC − (aX 1 − bY 1 )ΨD

]

When Bob makes measurement, wavefunction collapses

Then Alice’s photon in state related to Υ

Bob knows result of his measurement

Calls Alice on phone and tells her how to change her state to Υ (easy using λ/2 and λ/4 plates)

Now Alice has state Υ indistinguishable from original photon 3 33

If we could do this with 10^23 atoms instead of one photon, could teleport a mouse

Teleportation theory: C. H. Bennett et al. Phys. Rev. Lett. 70 1895 (1993)

Some experiments: D. Bouwmeester et al. Nature 390 575 (1997) T. C. Zhang et al. Phys. Rev. A 67 033802 (2003) M. D. Barrett et al. Nature 429 737 (2004)