Kinematic Equations - General Physics - Solved Exam, Exams of Physics

This is the Solved Exam of General Physics which includes Orbital Acceleration, Component of Ball’s Velocity, Horizontal Component, Smallest Acceleration, Order of Magnitude, Gravitational Potential Energy, Kinetic Energy etc. Key important points are: Kinematic Equations, Accelerometer, Speedometer, Odometer, One-Second Interval, Arithmetic Use, Decimal Point, Centimeters Per Inch, Horizontal Distance, Total Displacement, Total Distance Traveled

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2012/2013

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Physics 202A FIRST EXAM Chapters 1 - 3 Fall 2012
1
Name:_Answer Key
Solve the following problems in the space provided. Use the back of the page if needed. Each problem is
worth 20 points. You must show your work in a logical fashion starting with the correctly applied
physical principles. The equations you need are on the equation sheet. Your score will be maximized if
your work is easy to follow because partial credit will be awarded.
1. A baseball containing accelerometer,
speedometer and odometer is tossed straight
upward with an initial speed of 30m/s. Write in the
position, velocity, and acceleration reading that you
would expect at the end of each one-second
interval. Use coordinates where upward is positive.
To simplify the arithmetic use g=10m/s2. Notice
the decimal point before the last digit and the blue
boxes that contain a sign (±). If you want some
partial credit in the event that you make an
arithmetic mistake, explain how you are getting
your answers in the space below.
According to the Rule of Falling Bodies, the
acceleration remains a constant -10.0m/s2.
Therefore, the velocity will drop 10m/s every
second.
Using the definition of average speed, the distance
travelled is the average speed from t=0 until the
current time multiplied by the time.
a
x
v
a
x
v
a
x
v
a
x
v
a
x
v
a
x
v
t = 0s
t = 3s
t = 6s
t = 1s
t = 5s
t = 2s
t = 4s
a
x
v
+
1
0
0
0
0
0
0
3
+
-
+
4
5
0
2
0
0
-
0
0
+
1
2
-
0
1
0
-
0
1
0
-
0
1
0
-
0
1
0
-
0
1
0
-
0
0
+
2
0
+
1
0
+
0
0
1
0
0
-
-
5
0
+
2
5
0
4
0
0
+
4
0
+
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Name:_Answer Key

Solve the following problems in the space provided. Use the back of the page if needed. Each problem is

worth 20 points. You must show your work in a logical fashion starting with the correctly applied

physical principles. The equations you need are on the equation sheet. Your score will be maximized if

your work is easy to follow because partial credit will be awarded.

  1. A baseball containing accelerometer,

speedometer and odometer is tossed straight

upward with an initial speed of 30m/s. Write in the

position, velocity, and acceleration reading that you

would expect at the end of each one-second

interval. Use coordinates where upward is positive.

To simplify the arithmetic use g=10m/s

2

. Notice

the decimal point before the last digit and the blue

boxes that contain a sign (±). If you want some

partial credit in the event that you make an

arithmetic mistake, explain how you are getting

your answers in the space below.

According to the Rule of Falling Bodies, the

acceleration remains a constant - 10.0m/s

2

.

Therefore, the velocity will drop 10m/s every

second.

Using the definition of average speed, the distance

travelled is the average speed from t=0 until the

current time multiplied by the time.

a

x

v

a

x

v

a

x

v

a

x

v

a

x

v

a

x

v

t = 0s

t = 3s

t = 6s

t = 1s t = 5s

t = 2s t = 4s

a

x

v

+ 4 0 0 +^4 0

  1. Convert (a)one-year into seconds and (b)one meter into inches using the fact that there are 2.

centimeters per inch.

Use the multiply-by-one method.

(a) 1 yr

365 days

yr

24 hr

day

60 min

hr

60 s

min

⇒ 1 yr^ =^ 3.15 x^10

7

s (^).

(b) 1 m

100 cm

m

1 in

2.54 cm

⇒ 1 m = 39.4 in.

  1. A squirrel running along a horizontal limb of an oak tree at 1.50m/s accidentally releases the acorn it

was carrying. It strikes the ground 2.00s later. Find (a)the horizontal distance it traveled during the fall

and (b)the height from which it was dropped. (c)Explain why you can use the kinematic equations to

solve this problem.

Given: x o

= 0, v ox

= 1.50m/s, a x

= 0, t = 2.00s,

y = 0, v oy

= 0, and a y

= - 9.80m/s

2

.

Find: x =? and y o

(a)Use the kinematic equation,

x = x o

  • v ox

t +

1

2

a x

t

2

= 0 + (1.5)( 2 ) + 0 ⇒ x^ =^ 3.00 m^.

(b)Use the kinematic equation,

y = y o

  • v oy

t +

1

2

a y

t

2

⇒ 0 = y o

1

2

a y

t

2

y o

1

2

a y

t

2

Plugging in the numbers, y o

1

2

2

y o

= 19.6 m (^).

(c)The kinematic equations can be used because the accelerations along x and along y are both constant.

y

x

v ox

x x o

y o

y