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This is the Solved Exam of General Physics which includes Orbital Acceleration, Component of Ball’s Velocity, Horizontal Component, Smallest Acceleration, Order of Magnitude, Gravitational Potential Energy, Kinetic Energy etc. Key important points are: Kinematic Equations, Accelerometer, Speedometer, Odometer, One-Second Interval, Arithmetic Use, Decimal Point, Centimeters Per Inch, Horizontal Distance, Total Displacement, Total Distance Traveled
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Name:_Answer Key
Solve the following problems in the space provided. Use the back of the page if needed. Each problem is
worth 20 points. You must show your work in a logical fashion starting with the correctly applied
physical principles. The equations you need are on the equation sheet. Your score will be maximized if
your work is easy to follow because partial credit will be awarded.
speedometer and odometer is tossed straight
upward with an initial speed of 30m/s. Write in the
position, velocity, and acceleration reading that you
would expect at the end of each one-second
interval. Use coordinates where upward is positive.
To simplify the arithmetic use g=10m/s
2
. Notice
the decimal point before the last digit and the blue
boxes that contain a sign (±). If you want some
partial credit in the event that you make an
arithmetic mistake, explain how you are getting
your answers in the space below.
According to the Rule of Falling Bodies, the
acceleration remains a constant - 10.0m/s
2
.
Therefore, the velocity will drop 10m/s every
second.
Using the definition of average speed, the distance
travelled is the average speed from t=0 until the
current time multiplied by the time.
a
x
v
a
x
v
a
x
v
a
x
v
a
x
v
a
x
v
t = 0s
t = 3s
t = 6s
t = 1s t = 5s
t = 2s t = 4s
a
x
v
centimeters per inch.
Use the multiply-by-one method.
(a) 1 yr
365 days
yr
24 hr
day
60 min
hr
60 s
min
⇒ 1 yr^ =^ 3.15 x^10
7
s (^).
(b) 1 m
100 cm
m
1 in
2.54 cm
⇒ 1 m = 39.4 in.
was carrying. It strikes the ground 2.00s later. Find (a)the horizontal distance it traveled during the fall
and (b)the height from which it was dropped. (c)Explain why you can use the kinematic equations to
solve this problem.
Given: x o
= 0, v ox
= 1.50m/s, a x
= 0, t = 2.00s,
y = 0, v oy
= 0, and a y
= - 9.80m/s
2
.
Find: x =? and y o
(a)Use the kinematic equation,
x = x o
t +
1
2
a x
t
2
= 0 + (1.5)( 2 ) + 0 ⇒ x^ =^ 3.00 m^.
(b)Use the kinematic equation,
y = y o
t +
1
2
a y
t
2
⇒ 0 = y o
1
2
a y
t
2
⇒ y o
1
2
a y
t
2
Plugging in the numbers, y o
1
2
2
⇒ y o
= 19.6 m (^).
(c)The kinematic equations can be used because the accelerations along x and along y are both constant.
y
x
v ox
x x o
y o
y