Derivatives and Kinematics: Understanding Function Rates and Motion, Lecture notes of Classical Physics

An overview of derivatives and their application in kinematics. It explains how derivatives represent the rate of change of a function and demonstrates the calculation of derivatives for simple functions. Additionally, it applies these concepts to the motion of bodies with constant acceleration.

Typology: Lecture notes

2011/2012

Uploaded on 08/12/2012

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PHYSICS –PHY101 VU
© Copyright Virtual University of Pakistan
8
Summary of Lecture 3 – KINEMATICS II
1. The concept of the derivative of a function is exceedingly important. The derivative shows
how fast a function changes when its argument is changed. (Remember that for ( ) we
say that is
fx
fa function that depends upon the argument . You should think of as a
machine that gives you the value when you input .)
2. Functions do not always have to be written as ( ). ( ) is also a
xf
fx
fx xt
0
function. It tells
us where a body is at different times .
3. The derivative of ( ) at time is defined as:
lim
t
t
xt t
dx x
dt t
Δ→
Δ
Δ
0
()()
lim .
t
xt t xt
t
Δ→
=
Δ
x
Δ
t
Δ
2
4. Let's see how to calculate the derivative of a simple function like ( ) . We must first
calculate the difference in at two slightly different values, and , while
remembering that
xt t
xttt
=
()
()
22
2
22
0
we choose to be extremely small:
2
2 lim 2
t
t
xt t t
ttttt
xxdx
tt
ttdt
Δ→
Δ
Δ= +Δ
=+Δ +Δ
ΔΔ
+ = =
ΔΔ
1
0
5. In exactly the same way you can show that if ( ) then:
lim
This is an extremely useful result.
n
n
t
xt t
dx x nt
dt t
Δ→
=
Δ
≡=
Δ
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Summary of Lecture 3 – KINEMATICS II

  1. The concept of the derivative of a function is exceedingly important. The derivative shows how fast a function changes when its argument is changed. (Remember that for ( ) we say that is

f x f a function that depends upon the argument. You should think of as a machine that gives you the value when you input .)

  1. Functions do not always have to be written as ( ). ( ) is also a

x f f x

f x x t

0

function. It tells us where a body is at different times.

  1. The derivative of ( ) at time is defined as: lim t

t

x t t dx x dt Δ → t

0 lim (^ )^ ( ). t

x t t x t Δ → t

= + Δ^ −

Δ x

Δ t

  1. Let's see how to calculate the derivative of a simple function like ( ) 2. We must first calculate the difference in at two slightly different values, and , while remembering that

x t t x t t t

(^2 ) 2 2 2

0

we choose to be extremely small:

2 lim t 2

t x t t t t t t t t x (^) t t x dx t Δ → t dt

1 0

  1. In exactly the same way you can show that if ( ) then: lim This is an extremely useful result.

n n t

x t t dx x (^) nt dt t

− Δ →

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0 0 2

  1. Let us apply the above to the function ( ) which represents the distance moved by a body with constant acceleration (see lecture 2): ( ) v 1 2

x t

x t = x + t + at

0 0 0 v 1 (2 ) v 2 This clearly shows that v 0 (acceleration is constant)

  1. A stone dropped from rest increases its speed in the downward direction according to v 9.

dx (^) a t at dt d (^) a a dt

d (^) g dt

= ≈ m/sec. This is true provided we are fairly close to the earth, otherwise the value of g decreases as we go further away from the earth. Also, note that if we measured distances from the ground

2 2 2 2

up, then the acceleration would be negative.

  1. A useful notation: write v. We call the second derivative of with respect to , or the rate of rate of change of

d d dx d x d x dt dt dt dt dt x t x

= ⎛^ ⎞=

with respect to.

  1. It is easy to extend these ideas to a body moving in both the x and y directions. The position and velocity in 2 dimensions are: (

t

r^ G^ = x t )ˆ ( )ˆ v ˆ^ ˆ v ˆ^ v ˆ Here the unit vectors ˆ^ and ˆare fixed, meaning that they do not dep

x y

i y t j dr dx (^) i dyj dt dt dt i j i j

G^ G

end upon time.

  1. The scalar product of two vectors and is defined as:

cos You can think of: ( )( cos )

A B

A B AB

A B A B

G G

G G

G G

(length of ) (projection of on ) OR, ( )( cos ) (length of ) (projection of o

A B A

A B B A

B A

= ×

= ×

G G G

G G

G G

n ). Remember that for unit vectors ˆ ˆ^ ˆ^ ˆ^ 1 and ˆ^ ˆ 0.

B

ii = jj = ij =

G

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