Atomic Size, Ionization Energy, and Electronegativity: Trends and Bonding, Lecture notes of Chemistry

Announcements and lecture notes for a chemistry class, covering topics such as atomic size, ionization energy, electronegativity, and bonding. how atomic size and ionization energy are related, and discusses trends for isoelectronic species. It also introduces the concept of electronegativity and explains how it can be used to predict the type of bonding between atoms.

Typology: Lecture notes

2021/2022

Uploaded on 09/27/2022

arien
arien 🇺🇸

4.8

(24)

309 documents

1 / 38

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Announcements
Lon-capa HW 6 Type 1 due Monday
(11/26) and Type 2 due Wednesday
(11/28) by 7pm
Lab 5: Modern Atomic Theory write-
up due tomorrow in discussion (and
text homework)
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19
pf1a
pf1b
pf1c
pf1d
pf1e
pf1f
pf20
pf21
pf22
pf23
pf24
pf25
pf26

Partial preview of the text

Download Atomic Size, Ionization Energy, and Electronegativity: Trends and Bonding and more Lecture notes Chemistry in PDF only on Docsity!

Announcements

 Lon-capa HW 6 – Type 1 due Monday

(11/26) and Type 2 due Wednesday

(11/28) by 7pm

 “Lab 5: Modern Atomic Theory” write-

up due tomorrow in discussion (and

text homework)

Announcements

 All previous lectures are posted on

course website (“Lectures” link in left

menu)

 Final exam is cumulative so you should

start reviewing material soon!

 Last textbook homework assignment

will be given this Friday (due November

30 th)

Ionization and atomic size

 When an element becomes an ion, how is

size and ionization energy affected?

 When electron is pulled off, there is still the same number of protons; larger positive charge pulls remaining electrons in tighter

Ionization and atomic size

 When an element becomes an ion, how is

size and ionization energy affected?

 When electron is added, there is still the same number of protons; larger negative charge means electrons are bound less tightly

Trends in Isoelectronic Species

 Which is larger, Na+^ or Ne?

 Isoelectronic (both contain 10 electrons)

 Have to look at number of protons:

 Na+: 11 protons; Ne: 10 protons

 Since Na+^ has 11 protons, it will pull in its

electrons tighter

 Therefore Ne will be larger

Trends in Isoelectronic Species

 Which has a higher ionization energy, Na+^ or

Ne?

 Isoelectronic (both contain 10 electrons)

 Already established that Ne is larger

 Since Na+^ is smaller, electrons are pulled in

tighter -> harder to remove an electron

 Therefore, Na+^ has the higher ionization

energy

Trends in Isoelectronic Species

 Which has a higher ionization energy, Cl-^ or

Ar?

 Isoelectronic (both contain 10 electrons)

 Already established that Cl-^ is larger

 Since Ar is smaller, electrons are pulled in

tighter -> harder to remove an electron

 Therefore, Ar has the higher ionization

energy

Clicker

 Rank the following isoelectronic species in order from highest to lowest ionization energy.

 Ba2+, Cs+, I-, Te2-, Xe

A) Xe > I-^ > Te2-^ > Ba2+^ > Cs+

B) Ba2+^ > Xe > Cs+^ > Te2-^ > I-

C) Cs+^ > Ba2+^ > Te2-^ > I-^ > Xe

D) Te2-^ > I-^ > Xe > Cs+^ > Ba2+

E) Ba2+^ > Cs+^ > Xe > I-^ > Te2-

Chemical Bonding: Ionic

 Contain ionic bonding between a metal and non-metal

 Electrons are transferred, and ions are

electrostatically held together

Chemical Bonding: Ionic

 Notice that valence shells are filled and that

there are no unpaired electrons in product

 Transferring electrons requires energy (endothermic)

 Example: ionization of magnesium

 Mg  Mg+^  Mg2+  First ionization energy: 737 kJ/mol  Second ionization energy: 1451 kJ/mol

 Takes more energy to remove second electron because atom is now more positively charged (so it holds electrons even tighter)

 If it requires so much energy, then how do ionic compounds form?

 Example: magnesium chloride

 Mg2+^ + 2Cl-^  MgCl 2  Heat released in forming MgCl 2 : 592 kJ/mol

 Energy is released when MgCl 2 forms because the electrostatic interaction between Mg2+^ and Cl-^ ions causes them to become more stable (lower energy)

Bonding: Covalent

 What about bonding in H 2? Is it ionic?

 Not likely; in order to do that, one H atom

would need to lose an electron and one

would need to gain one, then electrostatically

bond

H H H+^ H-

e-

Bonding: Covalent

 So why does H 2 form?  Because we get covalent bonding (sharing of valence electrons)

 Valence electrons spend majority of time in between the two atoms so both hydrogen atoms have a noble gas configuration ( not the cause of bonding, just a way to remember)

 This sharing of electrons lowers the energy between the two nuclei