Lecture notes for structural analysis, Lecture notes of Civil Engineering

Contents show an example of double integration along with graphs for deflection and slope.

Typology: Lecture notes

2020/2021

Uploaded on 02/03/2021

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Analysis of a statically determinate beam by the Double Integration method
The load is distributed linearly:
2
0 0
1 1
( ) ( )
2 2 2
w x w x
V x x w x x L L
  
3
0 0
1
( ) 2 3 6
w x w x
x
M x x L L

0
( ) w x
w x L

The shear force and the bending moment in section x are:
The boundary conditions:
(0) 0
(0) 0
V
M
( ) 0
( ) 0
L
y L
We have found V(x) and M(x); therefore the boundary conditions
at x = 0 are already satisfied.
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Analysis of a statically determinate beam by the Double Integration method

The load is distributed linearly:

2

0 0

w x w x

V x x w x x

L L

3

0 0

w x x w x

M x x

L L

0

w x

w x

L

The shear force and the bending moment in section x are:

The boundary conditions:

(0) 0

(0) 0

V

M

( ) 0

( ) 0

L

y L

 

We have found V(x) and M(x); therefore the boundary conditions

at x = 0 are already satisfied.

Analysis of a statically determinate beam by the Double Integration method

0

w x

w x

L

(0) 0

(0) 0

V

M

( ) 0

( ) 0

L

y L

 

The boundary conditions:

The load is distributed linearly:

The shear force and the bending moment in section x are:

2

0 0

w x w x

V x x w x x

L L

3

0 0

w x x w x

M x x

L L

To find the slope and deflection , we need to use integration:

4

0

1

w x

EI x M x dx C

L

Since q ( L ) = 0,

4 3

4 4 0 0 0

1 1

w L w L w

C C EI x L x

L L

We have found V(x) and M(x); therefore the boundary conditions

at x = 0 are already satisfied.

5

4 4 4 0 0

2

w w x

EIy x x dx L x dx L x C

L L

The last boundary condition: y ( L ) = 0.

5 4

4 5 0 0 0

2 2 2

w L w w L

L L C L C C

L L