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Material Type: Notes; Class: Linear Programming and Network Flows; Subject: MATHEMATICAL SCIENCES; University: Northern Illinois University; Term: Unknown 1989;
Typology: Study notes
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Consider a real-valued function f :C → R defined on some set C. Let g :C → R be given by g (^ x )^ = − f (^ x). If xˆ ∈ C is a maximizer of f , then xˆ is a minimizer of g. To see this, observe that g ( xˆ ) = −f ( xˆ ) ≤ −f (^ x )^ =g (^ x) for all x ∈ C.
Exercise Show that if ˆx ∈ C is a minimizer of f :C → R , then ˆx is a maximizer of g :C → R , where g is given by g (^ x )^ = −f (^ x).
Inequalities of the form ax ≥ b are converted to the standard form by multiplying both sides by − 1.
Exercise First convert the standard dual problem to a standard primal problem. Next take the dual of the converted problem. Do you recognize this problem?
Equalities of the form Dx = e split into a pair Dx ≤ e and Dx ≥ e. In the primal problem this pair appears as Dx e Dx e
It is of course possible to use the system Dx = e and solve for some of the variables xi in terms of the others and then replace the xi throughout the problem.
The restriction that all variables are non-negative is possible to circumvent by increasing the number of variables. Suppose that xi is allowed to be both positive and negative. Introduce pi ≥ 0 and ni ≥ 0. Replace xi throughout the problem with xi = pi − ni. Observe how the linearity is retained. In this way each converted unrestricted variable increases the dimension by
Exercise Consider the problem
1 1 2 2 1
max 2 when 5 0
x x x x x
Convert this problem to a standard primal problem.