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Material Type: Notes; Class: College Physics: E&M & Modern; Subject: Physics; University: University of Illinois - Urbana-Champaign; Term: Spring 2009;
Typology: Study notes
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d
Path length difference 1-
θ
θ
L
= d sin
θ
d
Path length difference 1-3 = 2d sin
θ
d
1 2
3
Path length difference 1-4 = 3d sin
θ =λ
=2λ
=3λ
4
N slits with spacing d
Constructive Interference Maxima are at:
θ
Same as for Young’s
Double Slit!
For many slits, maxima are still at
Region between maxima gets suppressed moreand more as no. of slits increases – bright fringesbecome narrower and brighter.
10 slits (N=10)
d sin
θ
intensity
λ
2λ
0
2 slits (N=2)
d sin
θ
intensity
λ
2λ
0
Peak location
depends onwavelength!
Constructive interference:
in NaCl
For
λ
=.017nm
X-ray
d
1
st
maximum will be at 10
0
Crystal solid such
as sodium
θ
θ
W
w^2
sin
θ
θ
θ
θ
W
2
1 1
′
Rays 2 and 2
′
also start W/2 apart and have
the same path length difference.
2
2
′
1
st
minimum
at:
When
rays 1 and 1
′
interfere destructively.
w^2
sin
θ =
λ 2
Under this condition, every ray originating in top half ofslit interferes destructively with the corresponding rayoriginating in bottom half.
w
Rays 2 and 2
′
also start w/4 apart and have
the same path length difference.
2
nd
minimum at:
Under this condition, every ray originating in top quarter ofslit interferes destructively with the corresponding rayoriginating in second quarter.
4 w
θ
1 1
′
)
sin(
4 w
θ
2
2
′
When
rays 1 and 1
′
will interfere destructively.
2
)
sin(
4 w
λ
θ
=
A laser is shone at a screen through a very small hole. Ifyou make the hole even smaller, the spot on the screenwill get:
(1) Larger
(2) Smaller
Which drawing correctly depicts the pattern of light onthe screen?
(1)
(2)
(3)
(4)
Maxima and minima will be a series of bright anddark rings on screen
Central
maximum
1
st
diffraction
minimum
θ
Diameter D
light
First diffraction minimum is at:
These objects are
Two objects are just resolved when the maximum ofone is at the minimum of the other.
Physics 102: Lecture 21, Slide
objects
min
θ
min
θ
objects
Improve resolution by increasing
θ
objects
or decreasing
θ
min
θ
objects
is angle between
objects and aperture:
tan
θ
objects
≈
d/y
sin
θ
min
≈ θ
min
= 1.
λ
/D
θ
min
is minimum angular separation
that aperture can resolve:
D
d
y
min
min
How does the maximum resolving power of your eyechange when the brightness of the room is decreased.1) Increases
Constant
Decreases
Coherent waves
Each point on wave front acts as
coherent source and can interfere.
Max from 1 at Min from 2
opposite!