Lewis Structures and Valence Shell Electron Pair Repulsion Theory, Schemes and Mind Maps of Geometry

LEWIS STRUCTURES. A molecule achieves its structure by arranging its valence electrons into a particular com- bination of bonds and lone pairs which gives ...

Typology: Schemes and Mind Maps

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LEWIS STRUCTURES
A molecule achieves its structure by arranging its valence electrons into a particular com-
bination of bonds and lone pairs which gives the molecule the lowest energy. The Lewis proce-
dure is a method for how to dole out the valence electrons to bonds and to lone pairs. Valence
Shell Electron Pair Repulsion uses the concept of number of electron pairs to ascribe an elec-
tronic geometry to the Lewis structures. Both procedures condense the rigorous (and difficult!)
quantum mechanics to a set of simple rules.
To draw a Lewis structures make sure that you always determine the number of valence
electrons (VAL below). If there are many electrons and you run into difficulty trying to use the
rules on p. 526 of our text you may try using steps 2 - 6 below.
1. VAL (total number of valence electrons) = sum of the valence electrons of each element (sum
of the group numbers, GN) - charge (if an ion).
2. STAB (stable noble gas configuration) = sum of the electrons in the noble gas configuration
for each element (2 for H, 8 for C and beyond). Since an atom achieves its greatest stability
and lowest energy when it has a filled shell, the noble gas configuration, we assume that an
atom in a molecule or ion will also be most stable when it has its noble gas complement of
electrons around it - the ubiquitous "octet" rule.
3. BOND (total number of bonding electrons) = STAB - VAL and BP (number of bond pairs) =
BOND/2. Since electrons are shared between atoms that are bonded together the "octet"
around each atom over counts the actual number of electrons involved. The amount of over
counting is the number of bonding electrons.
4. LONE (total number of lone pair electrons) = VAL - BOND and LP (number of lone pairs) =
LONE/2. Valence electrons are of two varieties: they are either bonding electrons (BOND)
or nonbonding, lone electrons (LONE).
5. Draw the Lewis structure using your calculated BP and LP. Remember that nature likes sym-
metry, put the odd atom in the center. The central atom will generally be the less electroneg-
ative (more electropositive) element.
6. FC (formal charge on atom) = GN - LONE - BOND/2. The sum of the formal charges on all
atoms is equal to the charge on the molecule or ion.
Exceptions to the octet rule:
1. molecules or ions with an odd number of electrons
2. molecules with electron deficient atoms which are stable with less than eight electrons about
them (such as B and Al with 6 or Be with 4)
3. some molecules or ions containing an element beyond the second period - these must be
treated by a valence shell expansion
Valence Shell Expansion (VSE)
Occasionally the octet rule is violated allowing more than eight electrons to surround an
atom. The simplest case of this occurs when you are trying to attach more atoms to some central
atom than you have bonds determined via calculation with octets. The other common situation
arises when the Lewis structure drawn with octets exhibits charge separation (positive and neg-
ative FC in the same structure) and the VSE structure is more stable. In either case VSE is never
done for first or second period elements.
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LEWIS STRUCTURES

A molecule achieves its structure by arranging its valence electrons into a particular com- bination of bonds and lone pairs which gives the molecule the lowest energy. The Lewis proce- dure is a method for how to dole out the valence electrons to bonds and to lone pairs. V alence S hell E lectron P air R epulsion uses the concept of number of electron pairs to ascribe an elec- tronic geometry to the Lewis structures. Both procedures condense the rigorous (and difficult!) quantum mechanics to a set of simple rules.

To draw a Lewis structures make sure that you always determine the number of valence electrons (VAL below). If there are many electrons and you run into difficulty trying to use the rules on p. 52 6 of our text you may try using steps 2 - 6 below.

  1. VAL (total number of valence electrons) = sum of the valence electrons of each element (sum of the group numbers, GN) - charge (if an ion).
  2. STAB (stable noble gas configuration) = sum of the electrons in the noble gas configuration for each element (2 for H, 8 for C and beyond). Since an atom achieves its greatest stability and lowest energy when it has a filled shell, the noble gas configuration, we assume that an atom in a molecule or ion will also be most stable when it has its noble gas complement of electrons around it - the ubiquitous "octet" rule.
  3. BOND (total number of bonding electrons) = STAB - VAL and BP (number of bond pairs) = BOND/2. Since electrons are shared between atoms that are bonded together the "octet" around each atom over counts the actual number of electrons involved. The amount of over counting is the number of bonding electrons.
  4. LONE (total number of lone pair electrons) = VAL - BOND and LP (number of lone pairs) = LONE/2. Valence electrons are of two varieties: they are either bonding electrons (BOND) or nonbonding, lone electrons (LONE).
  5. Draw the Lewis structure using your calculated BP and LP. Remember that nature likes sym- metry, put the odd atom in the center. The central atom will generally be the less electroneg- ative (more electropositive) element.
  6. FC (formal charge on atom) = GN - LONE - BOND/2. The sum of the formal charges on all atoms is equal to the charge on the molecule or ion.

Exceptions to the octet rule:

  1. molecules or ions with an odd number of electrons
  2. molecules with electron deficient atoms which are stable with less than eight electrons about them (such as B and Al with 6 or Be with 4)
  3. some molecules or ions containing an element beyond the second period - these must be treated by a valence shell expansion

Valence Shell Expansion (VSE)

Occasionally the octet rule is violated allowing more than eight electrons to surround an atom. The simplest case of this occurs when you are trying to attach more atoms to some central atom than you have bonds determined via calculation with octets. The other common situation arises when the Lewis structure drawn with octets exhibits charge separation (positive and neg- ative FC in the same structure) and the VSE structure is more stable. In either case VSE is never done for first or second period elements.

1) SnBr�-

vAL= 4 +6(7) +2= 48

BOND= 56 - 48= 8/2= 4 BP

STAB= 7(8)= 56

LONE= 48 - 8= 40/2= 20 LP

6 Br=> 6 BP, 18 LP (expand twice to 12, gain 1 BP and lose 1 LP per each expansion)

Sn STAB= 12 Br J.-

FC(Sn)= 4 - 12 /2= -2 (^) e,_. (^) I � B /Sn/ r I Sr

2) PCls VAL= 5 +5(7)= 40

BOND= 48 - 40= 8/2= 4 BP

5 Cl=> 5 BP, 15 LP (one expansion)

P STAB= 10

3) Xe� VAL= 8 +3(7) - 1= 28

BOND= 32 - 28= 4/2= 2 BP

3 F=> 3 BP, 11 LP (one expansion)

Xe STAB= 10 F^ ]t

- .,,, X:c.. - f I

.;<1 l

VAL= 8 +4(7)= 36

BOND= 32 - 28= 4/2= 2 BP

4 F=> 4 BP, 14 LP (two expansions)

••

Kr STAB= 12

••

5) RnC1 2 VAL= 8 +2(7)= 22

BOND= 24 - 22= 2/2= 1 BP

2 Cl=> 2 BP, 9 LP (one expansion)

Rn STAB= 10 tt,

I

  • ,,, (^0) • </''"'n - • •, I

<!t

VSEPR: octahedral

STAB= 6(8)= 48

LONE= 40 -8= 32/2= 16 LP

VSEPR: trigonal bipyramidal

STAB= 4(8)= 32

LONE= 28 - 4= 24/2= 12 LP

VSEPR: T-shaped

STAB= 5(8)= 40

LONE= 28 - 4= 24/2= 12 LP

VSEPR: square planar

STAB= 3(8)= 24

LONE= 22 - 2= 20/2= 10 LP

VSEPR: linear

Now to examine some examples where it may not be obvious that a VSE need be done;

sufficient bonds exist from just assuming the normal octets. Here the idea of a stable Lewis

structure will predominate. If possible always try to reduce the formal charge separation. The

only time this may be problematic is when a FC reduction also leads to a loss of resonance struc

tures. Since it is difficult to unambiguously say which is more important, reducing charge sepa

ration or possessing resonance, when such an option arises we will take the route of simplest is

best and not expand.

VAL=3(6)= 18

BOND=24-18=612=3BP

STAB=3(8)= 24

LONE= 18-6= 12/2=6LP

S STAB=

FC(O)=6-6-2/2=-

FC(S)=6 - 2 - 6/2= 1

.. ,....S � .• .r ;- � ·-

- ..o. 'II, • (^) ·- 0

VSEPR: bent

s -· �-+' '· (^0) .. (^) .o. -..

two resonance structures good but FC separation=> 4BP, 5LP (one expansion)

S STAB= 10 ••

••? s� •• (^0) .. (^). 0 ..

The loss of charge separation is good but the concurrent loss of resonance is not. We would con

clude that nothing is gained overall by doing a VSE. Simplest, in this case, is best so stay with

the octet. Experimentally it is observed that the SO bonds in S0 2 are equivalent and intermedi

ate between a single bond, S -0, and a double bond S = 0, in length. Our decision best accords

with experiment.

VAL=4(6)=

BOND=32 - 24=8/2=4BP

S STAB=

FC(O)=6-6-2/2=-

FC(S)=6 812=

:o:

11 ... ;^ ia '. "'

- .o. .. (^) .o· -. ..

STAB=4(8)=

LONE=24-8= 16/2 8LP

VSEPR: trigonal planar

.. - �o: I�.. .. - s � ·. --�o. ,.. .o.

.. - :o: I ;:L+ s .. ,::,, '. (^0) .. .o.. -

three resonance structures excellent but charge separation=> 5BP, 7LP (one expansion)

S STAB= 10 ;o!

l\

s"'" ,. / ,,.

  • .o.. (^) .. .o. ,

..^ - :o�

/, s .. ::,- �. o .. (^) .o·

retained resonance but still charge separation=> 6BP, 6LP (two expansions)

S STAB= 12

: o·. ,, ..-: s^ 4- •:"' 7 V ' (^) 0• - •. (^) .. ..

Now all resonance has been lost. As with S0 2 ,^ nothing has been gained overall by this last

expansion so stay with ten electrons about sulfur (STAB= 10). Experimental data on S0 3 shows

that all three SO bonds are equivalent and intermediate between a double and single bond.

VAL= 4(6) + 2= 26 STAB= 4(8)= 32

BOND= 32 - 26= 6/2= 3 BP LONE= 26 - 6= 20/2 = 10 LP

S STAB= 8

l .. � .. -ii-

VSEPR= trigonal pyramidal

FC(O) = 6 - 6 - 2/2 = -

FC(S) = 6 - 2 - 6/2 = 1

�o -s ...,o: • • t •• :o: .. -

charge separation=> 4 BP, 9 LP (one expansion)

S STAB= 10 �. .. ..^ -1:l.-

o::. -s - o:

  • l^ ••^ I:::-) :o:

.. - l .... ··11-

0-s�oI• • I I (^) :o:

... [ •• •• •• ] 1.-

:o - s- o:

. • ll • • :o:

VAL= 5(6) + 2= 32 STAB= 5(8) = 40

BOND= 40 - 32= 8/2= 4 BP LONE= 32 - 8 = 24/2= 12 LP

.. -

S STAB= 8 VSEPR: tetrahedral

••^ • :t.+ •• - :o -.. S - 0:. (^).

:o: ..

charge separation=> 5 BP, 11 LP (one expansion)

S STAB= 10 -., lL ,,-:o: j�- 0-l 0 0

4 I

;o-st.o: 1::::-) -o-s:::o (^) t...-r o-s-t-0- 1::-

  • • I ., •

'-t -

O=S-

'0, l^ II

  • •. � (^0 )

charge separation=> 6 BP, 10 LP (two expansions)

SSTAB�

t

:O: r

.. ,, .. : 0 -5 =- "' O ,. I:-")

�o:.. -

0^0

II ,, o-s-o �)^ D=S- ll (^) • (^0 )

best - no charge separation and six resonance structures

C> I

t:-'7 o-s=^ o

ll

I 0

0 I �) (^) o=-s�o (^) &- l 0

I O=-S- 0 ll 0