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Light and reflection. Marc Levoy. Computer Science Department. Stanford University. CS 178, Spring 2014. Begun 5/20/14, finished 5/22 ...
Typology: Exams
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Computer Science Department Stanford University
Begun 5/20/14, finished 5/
Outline
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Relationship to tristimulus theory
4
(ρ,γ , β) = L (^) e ( λ) 400 nm
700 nm ∫ ρ^ (^ λ)^ d^ λ,^ L^ e^ (^ λ) 400 nm
700 nm ∫ γ^ (^ λ)^ d^ λ,^ L^ e^ (^ λ) 400 nm
700 nm ∫ β^ (^ λ)^ d^ λ
V ( λ) = ρ ( λ) + γ ( λ) + β ( λ)
400 nm
700 nm ∫ d^ λ
luminance radiance (Stone)
V(λ), or luminous efficiency curve
S is actually much lower than M or L
Luminous intensity of a point light
lumens steradian
(Reinhard)
Luminous intensity of a point light
lumens steradian
Pierre Bouguer (1698-1758) As I mentioned in class, if the (incandescent) light bulb were 100% efficient (i.e. no energy wasted as heat outside the visible spectrum), it would give off 683 lumens per watt of input power, instead of 17.6 lumens per watt. That’s a big difference, and it explains the increasing popularity of compact fluorescent light bulbs, which give off up to 75 lumens per watt.
Photography by candlelight
(digital-photography-school.com)
Luminance leaving an area light
lumens steradian m 2
Luminance arriving on a surface
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lumens steradian m 2
Luminance from sun → reflection from surface (contents of whiteboard)
✦ Q. Why is the sun 160,000 candelas/cm^2 but its reflection by a diffuse white surface is only 1.6 cd/cm^2? ✦ A. the sun doesn’t occupy the entire sky, but diffuse reflection does. ✦ luminance arrives from the sun through 0.001% of the celestial hemisphere (0.00006 sr), hence the amount arriving is 160,000 cd/cm^2 = 160,000 lumens/sr cm^2 × 0.00006 sr = 10 lumens/cm^2 ✦ if we assume a diffuse white surface reflects all the light it receives, then it reflects these 10 lumens/cm^2 into 100% of hemisphere (2π sr), hence the surface’s outgoing luminance is 10 lumens/cm^2 ÷ 2π sr = 1.6 lumens/sr cm^2 13 or 1.6 cd/cm^2
you won’t be asked to perform calculations like this on your final exam (whew!)
Illuminance on a surface
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lumens m 2
(Reinhard)
To help yourself remember the difference bet ween luminous intensity, luminance, and illuminance, keep your eye on the units of each. The luminous intensity of a point light source is given in power per unit solid angle (lumens/sr); the luminance of an area light source (or the luminance arriving at an extended surface) is given in power per unit solid angle per unit area on the surface (lumens/(sr m given in power per unit area (lumens/m^2 ); the illuminance accumulating on a surface is (^2) ). Note that each of these three concepts has different units.
The effect of distance to the subject
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Q. How does illuminance change with distance from an area light?
(Thomson)
Georges de La Tour The Carpenter, 1640
✦ assume the light is a diffuse surface of infinite extent (at right in drawings) ✦ assume the receiver (at left) is a camera or light meter (or human eye), having a given lens (or iris) diameter and a pixel (or retinal cell) width ✦ the solid angle captured by the lens from each point on the light source falls as d^2 (left drawing) ✦ but the number of source points seen by the pixel rises as d^2 (right drawing) ✦ these effects cancel, so the illuminance at a pixel is independent of d 17
Recap
✦ to convert radiometric measures of light into photometric measures, multiply the spectral power distribution as measured by a spectroradiometer wavelength-by-wavelength by the human luminous efficiency curve V(λ) ✦ useful measures of light are the^ luminous^ intensity^ emitted by a point source (power per solid angle), the luminance emitted by (or arriving at) an area source (power per solid angle per unit area), and the illuminance accumulating on a surface (power per unit area) ✦ bright objects (like the sun) may be more luminous (measured in lumens/sr cm^2 ) than darker objects (like the blue sky), but typically cover a smaller fraction of the incoming hemisphere ✦ outdoor shadows are 1/5 as bright as lit areas (2.2 f/stops)
19 Que s t ions?
Outline
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