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limiting reactant practice answers, Lecture notes of Chemistry

European International UniversityChemistry

What is the limiting reactant if 2.2 g of Mg is reacted with 4.5 L of oxygen at STP? ... Magnesium is limiting and oxygen is in excess.

Typology: Lecture notes

2021/2022

Uploaded on 08/05/2022

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1
Chemistry Name ________________
Limiting Reactant Date ________________
1. 2 Mg + O2(g) ! 2 MgO
What is the limiting reactant if 2.2 g of Mg is reacted with 4.5 L of oxygen at STP?
Both of the following give you the same answer. In the first case, you need to do one or the other. In
the second set, you need to do both to determine which reactant makes the least amount of the
product.
2.2!𝑔!𝑀𝑔
1
!𝑥!
1!𝑚𝑜𝑙𝑒!𝑀𝑔
24.305!𝑔!𝑀𝑔
!𝑥!
1!𝑚𝑜𝑙𝑒!𝑂!
2!𝑚𝑜𝑙𝑒!𝑀𝑔
!𝑥!
22.4!𝐿!𝑂!
1!𝑚𝑜𝑙𝑒!𝑂!
=1.0!𝐿!𝑂!
4.5!𝐿!𝑂!
1
!𝑥!
1!𝑚𝑜𝑙𝑒!𝑂!
22.4!𝐿!𝑂!
!𝑥!
2!𝑚𝑜𝑙𝑒!𝑀𝑔
1!𝑚𝑜𝑙𝑒!𝑂!
!𝑥!
24.305!𝑔!𝑀𝑔
1!𝑚𝑜𝑙𝑒!𝑀𝑔
=9.8!𝑔!𝑀𝑔!
Magnesium is limiting and oxygen is in excess
2.2!𝑔!𝑀𝑔
1
!𝑥!
1!𝑚𝑜𝑙𝑒!𝑀𝑔
24.305!𝑔!𝑀𝑔
!𝑥!
2!𝑚𝑜𝑙𝑒!𝑀𝑔𝑂
2!𝑚𝑜𝑙𝑒!𝑀𝑔
=0.0905!𝑚𝑜𝑙𝑒!𝑀𝑔𝑂
4.5!𝐿!𝑂!
1
!𝑥!
1!𝑚𝑜𝑙𝑒!𝑂!
22.4!𝐿!𝑂!
!𝑥!
2!𝑚𝑜𝑙𝑒!𝑀𝑔𝑂
1!𝑚𝑜𝑙𝑒!𝑂!
=0.401!𝑚𝑜𝑙𝑒!𝑀𝑔𝑂
Magnesium is limiting and oxygen is in excess
2. CH4 + 2 H2O ! 4 H2(g) + CO2(g)
How many liters of hydrogen can be produced from the reaction of 80.0 g of CH4 and 16.3 g of
water? What is the limiting reactant?
Can use either of the following to determine the limiting reactant.
Determine how much one of the reactant needs of the other.
80.0!𝑔!𝐶𝐻!
1
!𝑥!
1!𝑚𝑜𝑙𝑒!𝐶𝐻!
16.033!𝑔!𝐶𝐻!
!𝑥!
2!𝑚𝑜𝑙𝑒𝑠!𝐻!𝑂
1!𝑚𝑜𝑙𝑒!𝐶𝐻!
!𝑥!
18.015!𝑔!𝐻!𝑂
1!𝑚𝑜𝑙𝑒!𝐻!𝑂
=180.𝑔!𝐻!𝑂!
16.3!𝑔!𝐻!𝑂
1
!𝑥!
1!𝑚𝑜𝑙𝑒!𝐻!𝑂
18.015!𝑔!𝐻!𝑂
!𝑥!
1!𝑚𝑜𝑙𝑒!𝐶𝐻!
2!𝑚𝑜𝑙𝑒𝑠!𝐻!𝑂
!𝑥!
16.033!𝑔!𝐶𝐻!
1!𝑚𝑜𝑙𝑒!𝐶𝐻!
=7.25!𝑔!𝐶𝐻!
Need more water than you have so not enough water (limiting reactant) and too much carbon
tetrahydride (excess reactant).
OR
80.0!𝑔!𝐶𝐻!
1
!𝑥!
1!𝑚𝑜𝑙𝑒!𝐶𝐻!
16.033!𝑔!𝐶𝐻!
!𝑥!
4!𝑚𝑜𝑙𝑒𝑠!𝐻!
1!𝑚𝑜𝑙𝑒!𝐶𝐻!
!𝑥!
22.4!𝐿!𝐻!
1!𝑚𝑜𝑙𝑒!𝐻!
=447!𝐿!𝐻!!
16.3!𝑔!𝐻!𝑂
1
!𝑥!
1!𝑚𝑜𝑙𝑒!𝐻!𝑂
18.015!𝑔!𝐻!𝑂
!𝑥!
4!𝑚𝑜𝑙𝑒𝑠!𝐻!
2!𝑚𝑜𝑙𝑒𝑠!𝐻!𝑂
!𝑥!
22.4!𝐿!𝐻!
1!𝑚𝑜𝑙𝑒!𝐻!
=40.5!𝐿!𝐻!
pf3

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Download limiting reactant practice answers and more Lecture notes Chemistry in PDF only on Docsity!

Chemistry Name ________________ Limiting Reactant Date ________________

  1. 2 Mg + O2(g)! 2 MgO What is the limiting reactant if 2.2 g of Mg is reacted with 4.5 L of oxygen at STP? Both of the following give you the same answer. In the first case, you need to do one or the other. In the second set, you need to do both to determine which reactant makes the least amount of the product.
  2. 2 𝑔 𝑀𝑔 1

Magnesium is limiting and oxygen is in excess

  1. 2 𝑔 𝑀𝑔 1

Magnesium is limiting and oxygen is in excess

  1. CH 4 + 2 H 2 O! 4 H2(g) + CO2(g) How many liters of hydrogen can be produced from the reaction of 80.0 g of CH 4 and 16.3 g of water? What is the limiting reactant? Can use either of the following to determine the limiting reactant. Determine how much one of the reactant needs of the other.
  2. 0 𝑔 𝐶𝐻! 1

Need more water than you have so not enough water (limiting reactant) and too much carbon tetrahydride (excess reactant). OR

  1. 0 𝑔 𝐶𝐻! 1

Can make a LOT more hydrogen with the carbon tetrahydride, so the carbon tetrahydride is in excess and the water is limiting. You make 40.5 L Hydrogen.

  1. 2 NaCl + Pb(NO 3 ) 2! 2 NaNO 3 + PbCl 2 How many grams of lead II chloride are produced from the reaction of 15.3 g of NaCl and 60.8 g of Pb(NO 3 ) 2? What is the limiting reactant? How much excess is left over? Can use either of the following to determine the limiting reactant. Determine how much one of the reactant needs of the other.
  2. 3 𝑔 𝑁𝑎𝐶𝑙 1

There is plenty of Lead II Nitrate. Lead II Nitrate is in excess and Sodium Chloride is limiting. OR Determine how much product each reactant can produce.

  1. 3 𝑔 𝑁𝑎𝐶𝑙 1

Same result – Sodium Chloride is limiting (it makes the least amount of the product) and Lead II Nitrate is in excess (it can make the most amount of the product). 36.4 g PbCl 2 is produced Determine how much Lead II Nitrate is needed to fully react the 15.3 g of sodium chloride (the limiting reactant).

  1. 3 𝑔 𝑁𝑎𝐶𝑙 1

Sodium Chloride is limiting Lead II Nitrate is in excess 36.4 g PbCl 2 is produced 17.4 g Pb(NO 3 ) 2 will be left over