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The basics of derivatives, including the definition, standard results, and rules such as the product rule and quotient rule. It also includes examples of finding derivatives of various functions and calculating the equations of tangents.
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Recall that, the gradient of a straight line in the x, y -plane is constant, and can be obtained from any two points on the line. So,
m = change in y change in x
∆y ∆x
y 2 − y 1 x 2 − x 1
The gradient of a curve at a point P is given by the gradient of the straight line touching the curve at P. This line is called the tangent of the curve.
The gradient of a curve y = f (x) at a point P(a, f (a)) can be estimated with the gradient of a line segment PQ if Q is close to P. So,
gradient at P ≈ gradient of PQ = f (a + ∆x) − f (a) ∆x
The closer Q is to P, the more accurate is the estimate. Eventually, as ∆x → 0, gradient of PQ → gradient at P.
Let y = f (x). Then ∆ ∆yx is the average rate of change of y with respect to x over some interval [x 1 , x 2 ].
As ∆x approaches 0, ∆ ∆yx approaches lim∆x→ 0 ∆ ∆yx (if the limit exists), and is called the instantaneous rate of change of y with respect to x at x 1.
Definition Let f be a function defined on an interval containing a. The derivative of f at a, denoted by f ′(a), is
f ′(a) = lim ∆x→ 0
f (a + ∆x) − f (a) ∆x if the limit exists. Very often, the limit is written as
f ′(a) = (^) xlim→a
f (x) − f (a) x − a
If f ′(a) exists, we say f is differentiable at a. If y = f (x), f ′(a) can also be written as y ′(a), dydx |x=a etc..
Given f (x), it is common to consider the derivative as a function of x, i.e., f ′(x). As we go along, we shall introduce the derivatives of elementary functions.
Standard Result 1. f (x) = c, c constant ⇒ f ′(x) = 0.
Given f (x), it is common to consider the derivative as a function of x, i.e., f ′(x). As we go along, we shall introduce the derivatives of elementary functions.
Standard Result 1. f (x) = c, c constant ⇒ f ′(x) = 0. Proof.
f ′(x) = lim ∆x→ 0
f (x + ∆x) − f (x) ∆x = lim ∆x→ 0
c − c ∆x
Standard Result 2. f (x) = xn, n integer ⇒ f ′(x) = nxn−^1. Proof. We prove the case n > 0. The proof for n < 0 is similar.
f ′(x) = lim t→x
f (t) − f (x) t − x = lim t→x
tn^ − xn t − x = lim t→x
(t − x)(tn−^1 + tn−^2 x + tn−^3 x^2 + · · · + txn−^2 + xn−^1 ) t − x = lim t→x (tn−^1 + tn−^2 x + · · · + xn−^1 ) = nxn−^1
Example Let y = f (x) = x^5. Find f ′( 1 ) and f ′( 2 ), and the equation of the tangent at x = 2.
Theorem If f is differentiable at a, then f is continuous at a.
The converse is NOT true!
Theorem If f ′(x) and g ′(x) exist, then • (f ± g )′(x) = f ′(x) ± g ′(x)