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Livestock Breeding and Genetics Final Exam Questions and Answers (Latest 2026).
Typology: Exams
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No dominance (Codominance) - neither allele is dominant in heterozygotes - will be average of teh two homozygotes. i.e RR = red, Rr = roan, rr = white Over dominance - a heterozygous individual performs better than both homozygous individuals (parents) i.e. hh = 100 lbs, HH =120 lbs, Hh = 140 lbs
our cells would not know what genes should or should not be transcribed. RNA Polymerase II alone is not sufficient for initiation of transcription.
Non-Random Mating: Assortative mating, linebreeding, inbreeding, or crossbreeding
C. Yes because the only information we have is the genetic info of the sire and dam D. No because of the randomness of genetic inheritance
G = 2-3 = -1 piglet C. PA = BV + GCV + Ep PA = 2-3-1 = -2 piglets D. PD/TA = 1/2 X BV PD/TA = 1/2 X 2 = +1 piglet E. E = Ep + Et E = -1 + 4 = + 3 piglets
(transmitting ability)? - Correct Answers ✅PD = 1/2 BV or TA = 1/2 BV PD/TA is half of BV
Selection Intensity - how "choosy" you are when selecting animals Genetic Variation - standard deviation of BV in herd/population Generation Interval - average age of parents in the herd
A. Calculate weaning weight EPD and accuracy for "Sure Thing". B. Calculate weaning weight EPD and accuracy for "Long Shot". C. Which sire would you expect to sire the heaviest calves in the future? Why? - Correct Answers ✅A. EPD = 8.65 lbs B. EPD = 6 lbs C. Sure Thing because he has the largest EPD for weaning weight