Logarithm Rules: Product, Quotient, and Power Rule with Examples, Slides of Algebra

An in-depth explanation of the product, quotient, and power rules of logarithms, along with examples to help illustrate the concepts. Students can use this document as a study aid for understanding these important rules and how to apply them.

Typology: Slides

2012/2013

Uploaded on 04/30/2013

suneeta
suneeta 🇮🇳

4.8

(9)

81 documents

1 / 29

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
§9.4a
Logarithm Rules
Docsity.com
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19
pf1a
pf1b
pf1c
pf1d

Partial preview of the text

Download Logarithm Rules: Product, Quotient, and Power Rule with Examples and more Slides Algebra in PDF only on Docsity!

§9.4a

Logarithm Rules

Review §

 Any QUESTIONS About

  • §9.3 → Common & Natural Logs

 Any QUESTIONS About HomeWork

• §9.3 → HW-

9.3 MTH 55

Quotient Rule for Logarithms

  • Let M , N , and a be positive real numbers with a ≠ 1, and let r be any real number. Then the QUOTIENT Rule

 That is, The logarithm of the quotient of two (or more) numbers is the difference of the logarithms of the numbers

log a

M

N

 =^ log a M^ −^ log a N

Power Rule for Logarithms

  • Let M , N , and a be positive real numbers with a ≠ 1, and let r be any real number. Then the POWER Rule

 That is, The logarithm of a number to the power r is r times the logarithm of the number.

log a M

r = r log a M

Example  Product Rule

  • Express as an equivalent expression that is a single logarithm: log a 6 + log a 7
  • Solution

= log a (42). Using the productrule for logarithms

log a 6 + log a 7 = log a (6·7)

Example  Quotient Rule

  • Express as an equivalent expression that is a single logarithm: log 3 (9/ y )
  • Solution

log 3 (9 /y ) = log 3 9 – log 3 y. Using the quotientrule for logarithms

Example  Power Rule

  • Use the power rule to write an equivalent expression that is a product: a) log a 6 −^3 b) log 4 x.

 Solution

= log 4 x 1/

Using the power a) log a (^6) rule for logarithms − (^3) = −3log a 6

b) log 4 x

= ½ log 4 x Using the powerrule for logarithms

Example  Use The Rules

  • Given that log 5 z = 3 and log 5 y = 2, evaluate each expression. a. log (^5) ( yz ) b. log (^5) ( 125 y^7 )

c. log (^5)

z y

d. log 5 z

1  (^30) y 5 

a. log 5 ( yz ) = log 5 y + log 5 z = 2 + 3 = 5

 Solution

Example  Use The Rules

  • Soln

d. log 5 z

1

 30 y 5

= log 5 z

1

30 + log 5 y^5

log 5 z + 5 log 5 y

( )^3 +^ 5 2( )

Example  Use The Rules

  • Express as an equivalent expression using individual logarithms of x , y , & z

 Soln a)

3 a) log 4 x^ b) log b^3 xy 7 yz (^) z

= log 4 x^3 – log 4 yz = 3log 4 x – log 4 yz = 3log 4 x – (log 4 y + log 4 z )

= 3log 4 x –log 4 y – log 4 z

3 log (^4) x yz

Caveat on Log Rules

  • Because the product and quotient rules

replace one term with two, it is often

best to use the rules within parentheses,

as in the previous example

( )

1 log log 7log 3

= (^) b x + (^) b yb z

7

(^1) log 3 b

xy z

= ⋅

Example  Expand by Log Rules

  • Write the expressions in expanded form

a. log (^2)

x^2 ( x − (^1) )^3 (^2 x^ +^1 )^4

b. log c x^3 y^2 z^5

 Solution a)

log (^2)

x^2 ( x − (^1) )^3 (^2 x^ +^1 )^4

= log 2 x^2 ( x − (^1) )^3 − log (^2) ( 2 x + (^1) )^4

= log 2 x^2 + log (^2) ( x − (^1) )^3 − log (^2) ( 2 x + (^1) )^4 = 2 log 2 x + 3log (^2) ( x − (^1) ) − 4 log (^2) ( 2 x + (^1) )

Example  Condense Logs

  • Write the expressions in condensed form

a. log 3 x − log 4 y

b. 2 ln x +

ln (^) ( x 2 + (^1) )

c. 2 log 2 5 + log 2 9 − log 2 75

d.

 ln x + ln (^) ( x + (^1) ) − ln (^) ( x 2 + (^1) )

Example  Condense Logs

  • Solution a) log 3 x − log 4 y = log

3 x 4 y

 

 

 Solution b)

2 log x +

1 2

ln (^) ( x 2 + (^1) )= ln x^2 + ln (^) ( x 2 + (^1) )

1 2

= ln (^) ( x 2 x^2 + (^1) )