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It is a pdf consistent what logarithm is and its fundamentals properties and it also represent the connection with exponents
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1 · What is a Logarithm?
Exponent Form Logarithm Form What it means
23 = 8 log 2 (8) = 3 2 raised to 3 gives 8
102 = 100 log 10 (100) = 2 10 raised to 2 gives 100
50 = 1 log 5 (1) = 0 Any base raised to 0 gives 1
3 -1^ = 1/3 log 3 (1/3) = − 1 Negative exponent → fraction
e^1 ≈ 2.718 ln(e) = 1 Natural log base e
Key insight: every logarithm statement hides an exponent statement. Always translate between the two forms to build intuition.
2 · Special Bases: Common & Natural Logarithms
Notation Base Name Example
log(x) 10 Common log log(1000) = 3 since 10^3 = 1000
ln(x) e ≈ 2.71828 Natural log ln(e^4 ) = 4
log 2 (x) 2 Binary log log 2 (32) = 5 since 2^5 = 32
3 · Properties of Logarithms (with Exponent Proofs)
Let logb(M) = p and logb(N) = q, so M = bp^ and N = bq. Then M·N = bp·bq^ = bp+q^ (exponent addition law). Taking logb of both sides gives logb(M·N) = p
Using M = bp^ and N = bq, we get M/N = bp/bq^ = bp−q^ (exponent subtraction law). Therefore logb(M/N) = p − q. Example: log 10 (1000/10) = log 10 (100) = 2 = 3 − 1.
With M = bp, we have Mn^ = (bp)n^ = bpn^ (exponent multiplication law). So logb(Mn) = pn = n·logb(M). Example: log 2 (8^2 ) = log 2 (64) = 6 = 2 × 3.
Because b^0 = 1 for any valid base b, it follows that logb(1) = 0. The exponent needed to turn the base into 1 is always zero. Example: log 7 (1) = 0 because 7^0 = 1.
Because b^1 = b for any base, the exponent needed to produce b from base b is 1. Example: log 5 (5) = 1 because 5^1 = 5.
These are the cancellation properties showing that exponentiation and logarithm are exact inverses of each other. Applying one then the other always returns the original value. Examples: 10 log(7)^ = 7 ; ln(e^3 ) = 3.
Identity logb(b) = 1 b^1 = b
Inverse blogbx^ = x Definition of inverse
Reciprocal logb(1/x) = −logb(x) x−^1 exponent rule
Change of Base logb(x) = ln(x)/ln(b) Derived from definition
Remember: every logarithm is secretly an exponent. When in doubt, rewrite logb(x) = y as by^ = x and use exponent laws.