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A qualifying exam in analysis from august 2010, covering various topics such as l1 spaces, vitali convergence theorem, dominated convergence theorem, convergence in measure, radon measures, uniform integrability, mollifiers, riemann-lebesgue lemma, points of density, maximal functions, and lebesgue measure. The exam consists of problems that require understanding and applying advanced theorems and concepts related to real analysis and measure theory.
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Qualifying Exam In Analysis August 2010 Pick three of the following. Identify which ones you are doing.
A
f dμ =
A
E (f |G) dμ
lim n→∞ μ([x ∈ Ω : |f (x) − fn(x)| ≥ ε]) = 0
for each fixed ε > 0. Show that there exists a subsequence {fnk } such that fnk converges pointwise to 0 off a set of measure zero.
λX (E) = P ([X ∈ E]).
Part of this is to show that [X ∈ E] is in F whenever E is Borel.
Pick 7 of the following Identify which ones you are doing
lim y→ 0
Rn
|f (x) − f (x − y)|p^ dx
) 1 /p = 0
Your proof should be based on standard facts about Lebesgue measure and advanced calculus.
φn = 1, φn is infinitely differentiable, and the support of φn is contained in B ( 0 ,an) where limn→∞ an = 0. Show that if f ∈ Lp^ (Rn) , then
lim n→∞ ||f − f ∗ φn||Lp(Rn) = 0
(The measure is ordinary Lebesgue measure). Also show that f ∗ φn is infinitely differentiable. Your argument should be based on standard theorems about the Lebesgue integral and Lebesgue measure.
0
e−stf (t) dt = 0
for each s sufficiently large, then f (t) = 0 for all t.
lim r→∞
R
sin (ru) f (u) du = 0
lim r→ 0
mn(E ∩ B(x, r)) mn(B(x, r))
Show that a.e. point of E is a point of density. Hint: The numerator of the above quotient is
B(x,r) XE^ (x)^ dm. Now consider the fundamental theorem of calculus.
Fr (x) ≡
mn (B (x, r))
B(x,r)
|f (x)| dmn
Argue Fr is continuous.
f (x) if |f (x)| > α/2, 0 if |f (x)| ≤ α/2. Argue [M f (x) > α] ⊆ [M f 1 (x) > α/2]. Then use the distribution function. Recall why ∫ (M f )pdx =
0
pαp−^1 m([M f > α])dα
0
pαp−^1 m([M f 1 > α/2])dα.
Now use the fundamental estimate satisfied by the maximal function and Fubini’s Theorem as needed.
E − E ≡ {x − y : x ∈ E and y ∈ E}
must contain an interval of the form (−δ, δ). State clearly all theorems used to show this.