MARK SCHEME, Lecture notes of Mathematics

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General Certificate of Secondary Education 2019

11935.01 F

MARK

SCHEME

Mathematics

M

Calculator Paper

Higher Tier

[GMC31]

TUESDAY 21 MAY, MORNING

GCSE MATHEMATICS

Introduction

The mark scheme normally provides the most popular solution to each question. Other solutions given by candidates are evaluated and credit given as appropriate; these alternative methods are not usually illustrated in the published mark scheme.

The marks awarded for each question are shown in the right hand column and they are prefixed by the letters M , W and MW as appropriate. The key to the mark scheme is given below:

M indicates marks for correct method.

W indicates marks for working.

MW indicates marks for combined method and working.

The solution to a question gains marks for correct method and marks for an accurate working based on this method. Where the method is not correct no marks can be given.

A later part of a question may require a candidate to use an answer obtained from an earlier part of the same question. A candidate who gets the wrong answer to the earlier part and goes on to the later part is naturally unaware that the wrong data is being used and is actually undertaking the solution of a parallel problem from the point at which the error occurred. If such a candidate continues to apply correct method, then the candidate’s individual working must be followed through from the error. If no further errors are made, then the candidate is penalised only for the initial error. Solutions containing two or more working or transcription errors are treated in the same way. This process is usually referred to as “follow-through marking” and allows a candidate to gain credit for that part of a solution which follows a working or transcription error.

Positive marking:

It is our intention to reward candidates for any demonstration of relevant knowledge, skills or understanding. For this reason we adopt a policy of following through their answers, that is, having penalised a candidate for an error, we mark the succeeding parts of the question using the candidate’s value or answers and award marks accordingly.

Some common examples of this occur in the following cases:

(a) a numerical error in one entry in a table of values might lead to several answers being incorrect, but these might not be essentially separate errors;

(b) readings taken from candidates’ inaccurate graphs may not agree with the answers expected but might be consistent with the graphs drawn.

When the candidate misreads a question in such a way as to make the question easier only a proportion of the marks will be available (based on the professional judgement of the examining team).

AVAILABLE

7 70% , 64% , 68% M1A

No (must also have a reason) _ ` a

A

Her best mark was in Geography

Alternative No because Geography 70% is higher than English 68% M1 A1 A1 3

8 (a) 8% of £840 = £67.20 MA

£840 + £67.20 = £907.20 MA

£75.60 A

(b) 5% of £840 = £42 and £840 – £42 = £798 MA

£907.20 – £798 = £109.20 A1 5

9 One card must be 5 to allow mode to be 5 A Total of cards 5 × 6 = 30 MA Last card = 30 – (3 + 5 + 8 + 5) = 9 MA Range = 9 – 3 = 6 MA1 4

10 (a) 4(2 b + 3) A

(b) t ( t – 1) A1 2

4 +^

6 MA

= 125 A

8 A

Yes 8 > 5 so enough in C to fill A and B A1 4

12 35 in overlap MA (95 – 35 =) 60 in French only MA (75 – 35 =) 40 in German only MA 200 – (35 + 60 + 40) = 65 A1 4

13 QSP = 110 MA

TUP = 50 so QPU = 50 (alternate) MA PQS = 180 – (50 + 110) = 20, x = 180 – 20 = 160 MA1 3

14 (a) 5 < t # 10 A

(b) 2.5 × 7 + 7.5 × 8 +12.5 × 5 + 17.5 × 5 + 22.5 × 4 + 27.5 × 1 (= 345) M1 A 345 30 MA =11.5 A1 5

AVAILABLE MARKS

24 y = 3 x + c ( c = any numerical value, c  5) M1 A1 2

25 (a) Cumulative frequency graph and scale M1 A

(b) 160 – (reading from 55 on their graph) A2 5 (correct reading approx. 160 – 72 = 88) Allow A1 for reading at 55

26 107.5% = 29455 MA

(100%) = 29455 ÷ 107.5 × 100 MA

= £27400 A

Alternative Solution

(100%) = 29455 ÷ 1.075 M1 A = £27400 A1 3

Total 100

11935.01 F 77

AVAILABLE MARKS