Vector Calculus: Gradient of Scalar and Vector Fields, Lecture notes of Mathematics

A chapter from a textbook on multivariable calculus, specifically focusing on the concepts of scalar and vector fields, and the gradient of scalar and vector functions. It includes definitions, examples, and theorems to help understand these concepts.

Typology: Lecture notes

2021/2022

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MAT3100: MULTIVARIABLECALCULUS
MWALEDavid
2020
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Download Vector Calculus: Gradient of Scalar and Vector Fields and more Lecture notes Mathematics in PDF only on Docsity!

MAT3100: MULTIVARIABLE CALCULUS

MWALE David

Contents

  • 1 FUNCTIONS OF SEVERAL VARIABLES
  • 2 Further Differential Calculus
  • 3 Surfaces
  • 4 Multiple Integration
  • 5 Vector Analysis
    • 5.1 Scalar and Vector fields
  • Bibliography

Chapter 2

Further Differential Calculus

Chapter 3

Surfaces

Chapter 5

Vector Analysis

5.1 Scalar and Vector fields

Definition 5.1.1. If every point p(x; y; z) of a region R of space has associated with it a scalar quantity say φ(x; y; z); then φ(x; y; z) is a scalar function and a scalar field is said to exist in the region R: Temperature is an example of a scalar field.

Definition 5.1.2. Definition: Let M and N be functions of two variables x and y defined on a plane region R: Then the function F defined by

F(x; y) = M(x; y) i + N(x; y) j

is called a vector field over R:

In a similar fashion, if M; N and P are functions of three variables x; y and z defined on a solid region π in space, then the function

F(x; y; z) = M(x; y; z) i + N(x; y; z) j + P(x; y; z) k

is called a vector field over π: We have already met one example of a vector field, that of the gradient. If

z = f(x; y) is differentiable at a point (x 0 ; y 0 ); then the gradient of f at (x 0 ; y 0 ) denoted by f is given by

f(x 0 ; y 0 ) = fx(x 0 ; y 0 ) i + fy (x 0 ; y 0 ) j :

We define the gradient of the function of three variables in a similar way.

Example 5.1.3. Let f(x; y) = sin xy^2 + ex^2 y^3 : Calculate f(1; 1): Solution From f(x; y) = sin xy^2 + ex^2 y^3 ; it is easy to show that fx(x; y) = y^2 cos xy^2 + 2xy^3 ex^2 y^3 and fy (x; y) = 2xy cos xy^2 + 3x^2 y^2 ex^2 y^3 : Consequently,

f(x; y) = (y^2 cos xy^2 + 2xy^3 ex^2 y^3 ) i + (2xy cos xy^2 + 3x^2 y^2 ex^2 y^3 ) j ;

so that f(1; 1) = (cos 1 + 2e) i + (2 cos 1 + 3e) j :

Example 5.1.4. Find the gradient vector of f(x,y,z)=zxy^ at the point (2; 2 ; 2): Solution Homework.

Theorem 5.1.5. 1. If F(x; y) = M(x; y) i + N(x; y) j is a continuously differ- entiable vector field in an open disc D centered at (x; y); then in D; F is the gradient of some function f(x; y) if and only if

My (x; y) = Nx(x; y):

In this case we say that the vector field is exact.

2. Let F(x; y; z) = P(x; y; z) i + Q(x; y; z) j + R(x; y; z) k be a continuously differentiable function on an open region R in R^3 ; then F is the gradient of some function f(x; y; z) if and only if

Py (x; y; z) = Qx(x; y; z); Pz(x; y; z) = Rx(x; y; z); Qz(x; y; z) = Ry (x; y; z):

Bibliography

Prescribed Readings

  1. Grossman S.T., (1996) Multivariable Calculus, Linear Algebra and Differential Equations, 3rd ed. HBL Publishers. ISBN: 0 155 64751 2 Recommended Readings
  2. Stewart J., (2009) Calculus 6th ed. Brooks/Cole Cengage Learning, ISBN: 0 495 38362 8
  3. Wylie R.C. and Barret L.C. (1995). Advanced Engineering Mathematics. McGraw-Hill. Company. ISBN: 0 070 72206 4
  4. Kreyzig E. (2011). Advanced Engineering Mathematics. 10th Ed. John Willey and Sons. ISBN: 0 470 45836 5