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Math 116 — Practice for Exam 2. Generated October 21, 2018. Name: Instructor: Section Number: 1. This exam has 7 questions. Note that the problems are not ...
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Semester Exam Problem Name Points Score Winter 2018 2 5 class time 12 Winter 2018 2 10 10 Fall 2013 2 5 pneumonia 10 Fall 2012 2 8 internet cafe 14 Fall 2013 2 9 coffee 7 Fall 2017 3 9 psych experiment 6 Fall 2017 3 3 11 Total 70
Recommended time (based on points): 68 minutes
Yennifer’s Introductory Thermodynamics of Muck course is supposed to start at 9: am, but her instructor does not consistently start on time. Let p(x) be the probability density function for the amount of time x, in minutes, between when the instructor is supposed to start the class and when they actually start class.
For parts a.-c., you do not need to justify your answer.
a. [2 points] Yennifer is coming from another class and therefore always arrives at 9:06, exactly 4 minutes before class is supposed to start. Find the probability that class starts before Yennifer arrives.
Answer:
Note that:
y = p(x)
x
y
b. [3 points] Which of the following statements is best supported by the equation p(12) = 0.02? Circle the one best answer.
i. The probability that the instructor will start class at 9:22 is 2%. ii. The probability that the instructor will start class between 9:21 and 9:23 is about 2%. iii. The probability that the instructor will start class between 9:21 and 9:23 is about 4%. iv. The probability that the instructor has started class by 9:22 is about 2%. v. The probability that the instructor has started class by 9:22 is about 48%.
c. [3 points] Let P (x) be the cumulative distribution function for p(x). Which of the following could be the formula for P (x) on the interval − 2 < x < 8? Circle all answers that could be correct.
i. P (x) = 0 ii. P (x) = 1
iii. P (x) = 0. 06 x iv. P (x) = 0.06(x + 2)
v. P (x) = 0.06(x+2)+0. 3 vi. P (x) = 0. 1 − 0 .06(x−8)
d. [4 points] Find the median value of x. Show your work, and write your answer in exact form.
Answer:
University of Michigan Department of Mathematics Winter, 2018 Math 116 Exam 2 Problem 5 (class time)
Math 116 / Exam 2 (November 13, 2013) page 7
f (t) =
(1 + at)^2 , for t > 0 ,
for some positive constant a.
a. [2 points] Give a practical interpretation of the quantity
3
f (t)dt. You do not need to compute the integral.
b. [5 points] Find a formula for the cumulative distribution function F (t) of f (t) for t > 0. Show all your work. Your answer may include a. Your final answer should not include any integrals.
c. [3 points] Determine the value of a. Show all your work.
University of Michigan Department of Mathematics Fall, 2013 Math 116 Exam 2 Problem 5 (pneumonia)
Math 116 / Exam 2 (November 14 , 2012) page 10
at
1 − t^2 0 ≤ t ≤ 1. 0 otherwise. where a is a constant. a. [4 points] For what value of a is p(t) a probability density function? Find its value without using your calculator.
b. [4 points] Find the cumulative distribution function P (t) of p(t). Make sure to indicate the value of P (t) for all values of −∞ < t < ∞. Your final answer should not contain any integrals.
University of Michigan Department of Mathematics Fall, 2012 Math 116 Exam 2 Problem 8 (internet cafe)
Math 116 / Exam 2 (November 13, 2013) page 12
p(c) =
3 20 c
(^2) for 0 ≤ c ≤ 2
3 5 for 2^ ≤^ c^ ≤^3
0 otherwise.
p H c L
1 2 3 c
a. [4 points] Find the mean of the amount of coffee drunk in one day. Include units. Show all your work.
b. [3 points] Find the median of the amount of coffee drunk in one day. Include units. Show all your work.
University of Michigan Department of Mathematics Fall, 2013 Math 116 Exam 2 Problem 9 (coffee)
− 4
g(x) dx
in the context of this problem.
b. [3 points] Note that g(1) = √ 21 eπ ≈ 0 .24. Which of the following is the best practical interpretation of the mathematical statement g(1) ≈ 0 .24? Circle the one best option.
i. The fraction of the population having experimental score equal to 1 is approximately 24 percent.
ii. The fraction of the population having experimental score equal to 0.24 is approximately 1 percent.
iii. The fraction of the population having experimental score between 0.9 and 1.1 is approximately 4.8 percent.
iv. The fraction of the population having experimental score between 0.23 and 0.25 is approximately 20 percent.
v. The fraction of the population having experimental score above 1 is approximately 76 percent.
vi. The fraction of the population having experimental score above 0.24 is approximately 1 percent.
University of Michigan Department of Mathematics Fall, 2017 Math 116 Exam 3 Problem 9 (psych experiment)