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General Comments and Advice: The student should regard this review sheet only as a sample of potential test problems, and not an end-all-be-all guide to its ...
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General Comments and Advice: The student should regard this review sheet only as a sample of potential test problems, and not an end-all-be-all guide to its content. Anything and everything which we have discussed in class is fair game for the test. The test will cover Sections 1.1, 2.1, 2.2, 2.3, 2.5, 2.7, and 3.1. Don’t limit your studying to this sheet; if you feel you don’t fully understand a particular topic or technique, then do more problems out of your textbook!
Major Facts About the Test: (1) There will be four problems, although some may have multiple parts. This gives you 15 minutes per problem. The problems are worth 15 points each for a total of a 60 point exam. (2) Calculators, cell phones, computers, tablets, notes, and books are not allowed on the exam. I will provide a handout with descriptions of important techniques for your use during the exam. The handout is included at the end of this document.
(b) y′^ + x cos^2 y = 0
(c) y′^ =
1 + 2x y^2 + y^2 x^2
(d) y′^ = x^2 y − y + x^2 − 1
(e) y′^ +
6 t^5 t^6 + 1
y = t
(f) 3y′^ − y = (3e−t^ sin t)y^4
(g) t^3 + y^3 − ty^2 y′^ = 0, t > 0
Also look at: 2.1 #1–12; 2.2 #1–16, 25–31; 2.4 #23–
2 MATH 241 (ORDINARY DIFFERENTIAL EQUATIONS) TEST 1 PRACTICE PROBLEMS (COHEN)
where V (t) is the volume of liquid in the tank at time t. This function V is modelled by the ODE
Suppose S 1 = 0.5, R 1 = 4, and R 2 = 8. In addition, suppose the tank initially holds 400 gallons of liquid and 0 pounds of salt. (a) Find the amount of salt contained in the tank at any time. (b) How long til 25 pounds of salt accumulate? (c) Will 75 pounds of salt accumulate before the tank has emptied? Also look at: 2.3 #1, 2, 3, 5, 6, 7, 9, 12
(b) Find the unique solution to the ODE which satisfies the initial conditions y(0) = 5, y′(0) = −2.
Also look at: 3.1 #1–
Answer Key (alert me if you find errors) 1.a. y = Kex
8 b. y = arctan(− 12 x^2 + C) c. y = √ (^3) 3 arctan x + 3 ln(1 + x (^2) ) + C d. y = −1 + Ke 13 x (^3) −x (^) e. y = t (^8) +4t (^2) +C t^6 +1 f.^ y^ =^
3
et 3 cos t+C g.^ y^ = t 3
3 ln t + C 2.a. y = (^10) e ex 8 b. y = arctan(− 12 x^2 + 1) c. y = 3
3 arctan x + 3 ln(1 + x^2 ) + 27 d. y = −1 + e (^13) x (^3) −x e. y = t
(^8) +4t (^2) − 207 t^6 +1 f.^ y^ =^ 3
et 3 cos t+eπ/^2 g.^ y^ =^ t^
√ (^3) 3 ln t − 2