Differential Equations Exam 1 Review Problems: Math 2552, Fall 2015, Exercises of Differential Equations

Math 2552 - Differential Equations. Sections F1 – F4; L1 – L4. Georgia Institute of Technology, Fall 2015. Techniques of Integration. Review Worksheet.

Typology: Exercises

2022/2023

Uploaded on 05/11/2023

pierc
pierc 🇺🇸

4.3

(4)

220 documents

1 / 1

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Math 2552 - Differential Equations
Sections F1 F4; L1 L4
Georgia Institute of Technology, Fall 2015
Exam 1 Review Problems
Solve the ODEs below. If they are IVPs, give the largest interval where your solution is valid.
1. ydy
dx = (x+xy2)ex2.
2. x2+2y
xdx = (3 ln x2)dy.
3. dy
dx =x
y+y
x+ 1.
4. 2xyy0+y2= 2x2.
5. y
x2
dy
dx +e2x3+y2= 0.
6. xyy0+y2= 2x.
7. y dx +x dy = 0.
8. dy
dx =1
yx.
9. ex+ydy dx = 0.
10. (x2
1) dy
dx + 2y= (x+ 1)2.
11. dy
dx =yx
y+x.
12. x dy =yln y dx;y(2) = e.
13. 1 + ln x+y
xdx = (1 ln x)dy.
14. xy0+y=ex;y(1) = 2.
15. dy sin x(y+ 2) dx = 0; y(π/2) = 1.
16. dy
dx =xy + 3xy3
xy 2x+ 4y8.
17. yln y
x+ 1dx x dy = 0.
18. dy
dx =2 ln x
xy
19. dy
dx +1
xy=25x2ln x
2y.
20. dy
dx +2e2x
1 + e2xy=1
e2x1.
21. dy
dx =sin y+ycos x+ 1
1xcos ysin x.
22. (ln(xy) + 1) dx +x
y+ 2ydy = 0.
23. dy
dx x2y=yx2.
24. 2x(ln x)y0
y=9x3y3ln x.
25. e2x+ydy exydx = 0.
26. y0+ysin x= sin x.
27. y0+y(tan x+ysin x) = 0.
28. dy
dx =x2
x2y2+y
x.
29. (3x2+ 2xy2)dx + (2x2y)dy = 0.
30. xy0
2y= 2x2ln x.
31. (y2+ 3xy +x2)dx x2dy = 0.
32. y0
x1y=x1px2y2;x > 0.
33. (1 + x)y0=y(2 + x).
34. (yex)dx +dy = 0.

Partial preview of the text

Download Differential Equations Exam 1 Review Problems: Math 2552, Fall 2015 and more Exercises Differential Equations in PDF only on Docsity!

Math 2552 - Differential Equations Sections F1 – F4; L1 – L Georgia Institute of Technology, Fall 2015

Exam 1 Review Problems

Solve the ODEs below. If they are IVPs, give the largest interval where your solution is valid.

  1. y dy dx

= (x + xy^2 )ex

2 .

x^2 +

2 y x

dx = (3 − ln x^2 ) dy.

  1. dy dx

= x y

  • y x
  1. 2 xyy′^ + y^2 = 2x^2.
  2. y x^2

dy dx

  • e^2 x

(^3) +y 2 = 0.

  1. xyy′^ + y^2 = 2x.

  2. y dx + x dy = 0.

dy dx

y − x

  1. ex+y^ dy − dx = 0.
  2. (x^2 − 1) dy dx
  • 2y = (x + 1)^2.
  1. dy dx

= y^ −^ x y + x

  1. x dy = y ln y dx; y(2) = e.

1 + ln x +

y x

dx = (1 − ln x) dy.

  1. xy′^ + y = ex; y(1) = 2.

  2. dy − sin x(y + 2) dx = 0; y(π/2) = 1.

dy dx

xy + 3x − y − 3 xy − 2 x + 4y − 8

  1. y

ln

( (^) y x

dx − x dy = 0.

  1. dy dx

= 2 ln^ x xy

dy dx

x

y =

25 x^2 ln x 2 y

dy dx

2 e^2 x 1 + e^2 x^

y =

e^2 x^ − 1

  1. dy dx

= sin^ y^ +^ y^ cos^ x^ + 1 1 − x cos y − sin x

  1. (ln(xy) + 1) dx +

x y

  • 2y

dy = 0.

dy dx

− x^2 y =

yx^2.

  1. 2 x(ln x)y′^ − y = − 9 x^3 y^3 ln x.

  2. e^2 x+y^ dy − ex−y^ dx = 0.

  3. y′^ + y sin x = sin x.

  4. y′^ + y(tan x + y sin x) = 0.

dy dx =^

x^2 x^2 − y^2 +^

y x.

  1. (3x^2 + 2xy^2 ) dx + (2x^2 y) dy = 0.
  2. xy′^ − 2 y = 2x^2 ln x.
  3. (y^2 + 3xy + x^2 ) dx − x^2 dy = 0.
  4. y′^ − x−^1 y = x−^1

x^2 − y^2 ; x > 0.

  1. (1 + x)y′^ = y(2 + x).
  2. (y − ex) dx + dy = 0.