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Math Math Statistics Business Statistics
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statistics formulas
are listed
the (^) chart below:
Mean
Standard
If n^ is odd,
()
th
even, thnen
(G)titerm-+(+1)term
2
The (^) value which
OCCurs (^) most
frequently
S(-)?
S=oVn
X
Observations
n= (^) Total
number
n=
Total
X=
n= (^) Total
X =
given
n=
Total
0O
300+Centres
I 140+ Cities
Mean Deviation
Formula
Mean Deviation
Formula
Click to chat on^ Whatsapp 9
The
deviation is^ lso known
the
the
of the absolute deviations of the
which
mnay
median
or the mode.
The formula to calculate Mean deviation is
stated below:
Mean Deviation from Mean
Here,
Mean Deviation (^) from Median
represents (^) the summation.
X =Observations
= Mean
N= The number of observations
M= Median
S Vo)^
4G
For (^) frequency distribution,
LTE
==
M.
Díahut
median)
=
When the
deviation is^ calculated
M
Mean Absolute
Deviation Fornmula
Average absolute deviation of the collected
data set is^ the
average of absolute
deviations (^) froma
centre (^) point of the (^) data
set. (^) Abbreviated as^ MAD,^ Mean absolute
deviation has four^
types (^) of deviations (^) that
are derived
by central
tendency, mean
median and mode and standard deviation.
Mean (^) absolute deviation is,^ however, (^) best
used
as it is more^ accurate and
easy (^) to use
in real-life situations.
The formula for Mean Absolute Deviation
(MAD) (^) is as (^) follows:
Where
X;= (^) Input data values
= Mean value for a^ given^ set of data,
n= (^) Number of^ data values
To (^) find MAD, you need
to (^) follow below steps:
Calculate the
mean for the
given set of^ data.
Find the difference between each value
present (^) in the data set and the
mean that
gives you^ the absolute value.
the difference between the data set and the
mean that
gives the
mean absolute
deviation
(MAD).
Question: Find the
absolute deviation
of the
following data
set:
26, (^) 46, 56, (^) 45,19, 22,
Solution:
1.e
Given set of data is:
26, 46, 56, 45,
19, (^) 22, 24
= 34
Mean
=
(
19 +^ 22
24)/
=
238/
= 34
26 -8^8
Mean Absolute
Deviation Formula
Average absolute deviation^
of the collected
data
set is the
average of absolute
deviations froma
centre point^ of the data
set. Abbreviated
as MAD, Mean (^) absolute
deviation has four^
types of deviations (^) that
are derived by^ central tendency,^
mean
median and mode and standard deviation.
Mean absolute deviation^
best
used
as it is more^ accurate and
easy (^) to use
in real-life situations.
The formula for Mean Absolute Deviation
(MAD) (^) is as
MAD =)
X;= (^) Input data values
=
a (^) given set of data,
n=
data
values
To find
you
need
to (^) follow below steps:
Calculate the
mean
the
data.
mean
you the (^) absolute
Find the
average of all the absolute values of
mean
gives
mean
Population
Mean
Formula
is
a
ifthe
A
be found^
= Sum of (^) the values
Solved (^) Example
followingnumbers
1, 2, 3,4, 5.
3, 4, 5
X;
4
5
= 15
N=
N
15
5
N
Population
Margin of^
Error
Formula
is a^ statistic
amount of (^) random sampling
in
It
a
close
the number
one
if the
whole population (^) had been queried.
In
the
is the
denoted
byE and the
= z^ x
n=
o=
Standard Deviation
Z =Z SCore
Solved (^) Examples
A
random sample^
students
has
average yearly earnings of^2450 and
a
standard deviation^
of 587. Find (^) the margin
=
0.95?
Standard Deviation=^587
o
= 587
At (^) 95%
confidence
z =
= z x
=
x
=
x
=
Sample
Size
Formula
The sample size (^) formula helps
us find (^) the
accurate sample size through (^) the difference
between the population^ and the sample.^
To
recall, (^) the number of^ observation
in a (^) given
sample population is^ known as^ sample (^) size.
Since it^ not^ possible to^
survey the whole
population,
we take
a sample (^) from the
population (^) and then conduct
a survey or
research. The^ sample^ size
is denoted
by (^) "n"
or "N". Here, it^ is (^) written as^ "SS".
Learn More:^ Confidence Interval Formula
and
Population
We (^) should know that the sample size that
we are taking from^ the population,
will not
hold good^ for (^) the whole sample. (^) We have
a
level of (^) confidence and
margin (^) of error^ to
calculate that the
sample size is^ accurate or
not. Confidence level^ helps^ describe how
sure you are that the^ results^
of the
survey
hold true
or accurate.
The (^) sample size for
an infinite (^) (unknown)
population and for^
a finite (known)
population is^ given
as:
Formulas for (^) Sample Size (ss)
For (^) Infinite Sample Size
ss
= (2²p
c
For Finite (^) Sample Size
Where,
Z= (^) Given
Z
value
Pop
= Population
ss/ [1+{(ss^
Check:
Z Score Table
Sample Size^ Formula
Example
Question: Find the sample^ size for
a finite
and infinite^ population when the
percentage of (^4300) population is 5,
confidence (^) level 99 and confidence (^) interval
is 0.01?
x0.05x
(1-0.05)
14316–I
4300
Quartile Formula
Quartile Formula
A
4
parts. (^) The
the first
or
Lower Quartile
is written
Similarly,
the value of mid
termn that lies between the
last term^ and the median
is known
the
third
quartile
is
Second
Quartile is
is (^) written
ascending (^) order,
percentile
is (^) given
as:
is given as:
or
or
is given
as:
n+
th
3(n
th
Term
th
Term
The (^) Upper quartile is (^) given by rounding to
if
is
coming
in (^) decimal number. The^ major
it helps
in
given. The dispersion is (^) also
inter quartile
quartile.
=
To (^) find
we first
in (^) ascending order. Then
we
to put
to
use. Let's (^) solve
you:
Solved example
Question:
the median,^
lower (^) quartile,
upper quartile and
inter-quartile
range
the
following data
set of
scores: (^) 19, 21,
23, (^) 27,25, 24, 31?
Solution:
First, lets
arrange
the values
in an
ascending order:
31
Now (^) let's calculate the
Median,
Q2= ()"Term
Q2=()"Term
th
=5th Term
=
Q1=("Term
=
()*
Term 2.5th^ Term
Upper
30
Qs=()
Term
th
th
Term
7.5th Term
Average of (^) 2nd and
3rd terms
(
Quartile
Average of 7th and 8th^
terms
(
27)/
Upper (^) Quartile
Upper quartile
Lower (^) quartile
Score Formula
Z-scores
are (^) expressed in terms of
deviations from their
a
distribution with^
score
is given
below:
Formula for^
Z
Score
Where,
•X= Standardized (^) random variable
=
Mean
•g= Standard deviation.
Also Check: Z-Score Table
z Score
=
the few^
problems
on Z
sCore:
Example
1: How (^) well did Ram perform^ in her
English (^) coursework compared to
(^50) students?
To answer this question,^
be re-phrase^
it
higher
First,
Ram (^) scored 70 out^ of l00, (^) the
was
was 15.
English
Coursework
= (
15
= 10/
=
Score
Z Score
= (x
)/o
(x)
70
Mean
(3)
60
Standard
Deviation (o)
15
The z-score^ is 0.67 (^) (to 2 decimal places),
but
now we need to^ work out the
of students that
scored
higher and lower^ than Ram.
Example 2: A
first
quiz,
scored 75. The mean^ and standard
quiz
15
respectively, while (^) the
mean and (^) standard
quiz are^
12
the normal
can you conclude about
the student's result^
z
Scores?
Mean, X=
standard deviation^
15
Formula for^
Z
Score
=
(x-)/o
=
(80-
Population (^) standard deviation
Formula for^
Z
Score
=
(x-)/o
=
(75-54)
=
Since
quiz is
that
it (^) is concluded that
in
Central
Limit
Theorenm Formula
a
data
An
Limit
if you
average
standard deviations^
in
your sample,
you (^) will
the actualstandard deviation^
your
population.
same (^) as
population.
The
of
size.
is
a
formula for^ central limit^ theorem
be
stated as^ follows:
and
Vn
standard deviation
=
Sample
=
Sample
Sample
size
Solved Example
Question: The^ record of^ weights^ of^ the male
population follows (^) the normal distribution.
Its
mean and
standard deviations^
are 70 kg and
15 kg
respectively.
If (^) a
researcher considers the records
of 50 males, then what would^ be the
mean
and
standard deviation^
of the chosen sample?
Solution:
Mean
of
the
population (^) =
kg
Standard deviation^
of the population^
= 15 kg
sample
size
50
Mean of the
sample is^ given by:
=
70 kg
Standard deviation^
of the sample^
given by:
=
kg (approx)