Math solution for DE, Study notes of Differential Equations

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Let: Q = amount of salt in the mixture 100 + (3 — 2)t = 100 + t = volume of mixture at any time t Q = concentration of salt 100+t gQ rate of gain — rate of loss 2 -9-of Q dt 100+t dQ dt ee c Fe---Fitost* InQ=-2In(100+t)+C InQ=-In(100+t)?+C 1 General solution when t = 0; Q = 50 kg. In 50 = - In (100+ 1)°+C C = 13.12236 when t = 60 min; Q =? In Q =- In (100 + 60)? + 13.12236 In Q = 2.972 Q = 19.53 kg. www.PinoyBIxX.com