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An introduction to differential equations, focusing on modeling, solving, and applications. Topics covered include exponential growth models, per capita growth rate, separable equations, first-order linear differential equations, and second-order linear differential equations. The document also includes examples and solutions for various types of differential equations.
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Lê Xuân Trường
Exponential growth model
N(t) is the population size at time t The rate of growth of the population is proportional to the pop- ulation dN dt
= kN(t) (eq1)
In the initial time we have N( 0 ) = N 0
How we can determine N(t)?
The equation is a first-order differential equation
Height of a Moving Baseball A baseball is thrown upward from a height of 3 meters above Earth’s surface with an initial velocity of 10m/s, and the only force acting on it is gravity. The ball has a mass of 0.15kg at Earth’s surface.
Find the position x (t) of the baseball at time t.
Modelling
The force acting on a baseball is the force of gravity
F = mg
Using Newton’s second law of motion we obtain
mg = mx′′(t) or x′′(t) = g
Cauchy problem for second-order differential equation
x′′(t) = g , x ( 0 ) = 3 , x′( 0 ) = 10.
Examples
dy dx = 6 y 2 x.
y ′^ =
xy 3 √ 1 + x^2
, y ( 0 ) = − 1.
Definition General form: a(x)y’ + b(x)y = c(x) Standard form: y’ + p(x)y = q(x)
q(x ) = 0: Homogeneous equation q(x ) 6 = 0: Nonhomogeneous equation
Examples
xy ′^ − 2 y = x^2
Definition
General form:
a(x )y ′′^ + b(x )y ′^ + c(x )y = d (x )
Standard form:
y ′′^ + p(x )y ′^ + q(x )y = f (x )
f (x ) = 0: Homogeneous equations f (x ) 6 = 0: Nonhomogeneous equations
In this course we only study the case of constants coefficients
Examples Find the general solutions of following equations
y ′′^ + 2 y ′^ − 3 y = 0 y ′′^ + 4 y ′^ + 4 y = 0 y ′′^ + y = 0
Solving nonhomogeneous equations
y” + py’ + qy = f(x)
y (x ) = ypar (x ) + y 0 (x )
y 0 is the general solution of the homogeneous equation
y” + py’ + qy = 0
ypar is a particular solution of the nonhomogeneous equa- tions
How to find the particular solution
Case 2: (where Pn and Qm are polynomial of degree n and m)
f (x ) = [Pn(x ) cos β x + Qm(x ) sin β x (^) ] exp(αx )
ypar (x ) = xλ^
Ps (x ) cos β x + Q̂ s (x ) sin β x
exp(αx )
where
λ =
0 , α ± iβ are not solutions of the characteristic equation 1 , α ± iβ are solutions of the characteristic equation
P̂ s and Q̂ s are polynomial of degree s = max{m, n}
Examples Solve the following equations
y ′′^ + 4 y ′^ − 5 y = x exp(x ) y ′′^ − 6 y ′^ + 9 y = cos(x )