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Mathematical Models, Quantum Mechanics, Symbolic Math Program, Energy Levels of Hydrogen, Radial Wavefunctions, Hamiltonian, Radial Orbits for Electron, Radial Function, Atomic Units. Before every lecture in Physical Chemistry, we received a lecture handout from lecturer. In end, we got all of them in soft form too. This is soft copy I am sharing with you. Enjoy.
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Goals:
Reference: Your textbook presents some background on pages 103-104.
In the pre-lab discussion, we saw how the hydrogen atom is understood to have only certain allowed radial orbits for the electron. Each orbit corresponds to a different energy level. Transitions between these particular energy levels and no others have been observed, thus demonstrating the hydrogen atom is a quantum mechanical entity.
We wish to explore a mathematical model (an equation if you will) that will have these allowed energies and orbits (and no others) to emerge naturally. We will replace the circular orbits of Bohr theory with the radial wavefunctions , R(r). R is the function that depends on r, the distance between the nucleus and the electron. These R(r) will be solutions to a differential equation called the Hamiltonian.
H ˆ^ ⋅ R ( r )= E ⋅ R ( r )
We read this as “ H ˆ^ works on R ( r )to yield E times R ( r ).” E is the energy.
In other words, the Hamiltonian works on the radial function to give the function back except for a factor out in front (the energy).
The Hamiltonian for the radial solutions to the hydrogen atom can be expressed most easily in atomic units:
2
2 (^2) dr r Rr r Rr E Rr
dRr r dr
d r
ll
There are only three variables in this equation:
Now, here is the fun part. The equation can be solved to find the R(r) radial functions. Only certain R(r) will work. These are like the “allowed orbits” from the Bohr model. Each is associated with a particular energy. For instance, the R(r) for the 1s orbital ( n=1 l =0 ) is:
r R (^) s r e ( )= 2 ⋅ − 1
At this point you might try using MathCad to prove that this is a solution to the equation and that it gives the energy that you already know is the energy of a hydrogen atom at the 1s level. But hold on just a minute, we should define some useful quantities first:
Probability of observing the electron a distance r from the nucleus:
P ( r )= R ( r )⋅ R ( r )⋅ r^2
Normalization Condition must be true (electron must be somewhere):
0
P ( r ) dr 1
Integration of the Hamiltonian gives the Energy. This can be used for any R(r) – not just ones that are solutions to the differential equation.
∞ ⋅ ⋅ ⋅ = 0
R ( r ) H ˆ R ( r ) r^2 dr E
Dividing by R(r) also gives the Energy. This will only work if the R(r) is a solution (or eigenfunction) of the Hamiltonian.
E Rr
Ok, I will walk you through how to construct a MathCad document that uses all of these expressions to prove that the radial wavefunction given above for the 1s orbital is a solution and does yield the correct energy.
Hydrogen 1s Radial Wavefunction
R r ( ) 2 e r l 0
P r ( ) R r ( ) R r ( ) r^2
0 1 2 3 4 5 0
P r ( )
r
Show normalization:
0
∞ P r ( ) r
d 1
H r ( ) 1 2 r 2 r
r^2 r
dR r ( ) d
d d
l ( l 1 ) 2 r^2
R r ( ) 1 r
R r ( )
This is how to evaluate the energy of an electron in any Radial Wavefunction:
0
∞ R r ( ) H r ( ) r^2 r
d 1 2
This is how to show that a particular Radial Wavefunction is an eigenfunction of the Hamiltonian. Must have a real number result that equals the result from integration. This result is called the eigenvalue.
H r ( ) R r ( )
simplify 1 2