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Document is of sample paper class 10th mathematics basic including set of questions to boost your thought process in examination
Typology: Exams
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14-430(B) Page 1 P.T.O.
Candidates must write the Q.P. Code on the title page of the answer-book.
àíZ - nÌ H$moS> amob Z§. Q.P. Code Roll No.
ZmoQ> / NOTE : (i) (^) H¥$n`m Om±M H$a b| {H$ Bg àíZ-nÌ _o§ _w{ÐV n¥ð> 23 h¢ & Please check that this question paper contains 23 printed pages.
(ii) (^) H¥$nm Om±M H$a b| {H$ Bg àíZ-nÌ _| > 38 àíZ h¢ & Please check that this question paper contains 38 questions. (iii) (^) àíZ-nÌ _| Xm{hZo hmW H$s Amoa {XE JE àíZ- nÌ H$moS H$mo narjmWu CÎma - nwpñVH$m Ho$ _wI - n¥ð> na {bI| & Q.P. Code given on the right hand side of the question paper should be written on the title page of the answer-book by the candidate. (iv) (^) H¥$nm àíZ H$m CÎma {bIZm ewê$ H$aZo go nhbo, CÎma - nwpñVH$m _| àíZ H$m H«$_m§H$ Adí{bI| & Please write down the serial number of the question in the answer-book before attempting it. (v) (^) Bg àíZ-nÌ H$mo n‹T>Zo Ho$ {bE 15 {_ZQ >H$m g_ {Xm Jm h¡ & àíZ-nÌ H$m {dVaU nydm©• _| 10.15 ~Oo {H$`m OmEJm & 10.15 ~Oo go 10.30 ~Oo VH$ N>mÌ Ho$db àíZ-nÌ H$mo n‹T>|Jo Am¡a Bg Ad{Y Ho$ Xm¡amZ do CÎma- nwpñVH$m na H$moB© CÎma Zht {bI|Jo & 15 minute time has been allotted to read this question paper. The question paper will be distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the question paper only and will not write any answer on the answer-book during this period.
MATHEMATICS (BASIC) ( FOR VISUALLY IMPAIRED CANDIDATES ONLY) {ZYm©[aV g_` : 3 KÊQ>o A{YH$V_ A§H$ : 80 Time allowed : 3 hours Maximum Marks : 80
14-430(B) Page 2
gm_mÝ` {ZX}e :
{ZåZ{b{IV {ZX}em| H$mo ~hþV gmdYmZr go n{‹T>E Am¡a CZH$m g™Vr go nmbZ H$s{OE :
(i) Bg àíZ - nÌ _| 38 àíZ h¢ & g^r àíZ A{Zdm`© h¢ &
(ii) `h àíZ- nÌ nm±M IÊS>m| _| {d^m{OV h¡ – H$, I, J, K Ed§ L> &
(iii) IÊS> H$ _| àíZ g§»m 1 go 18 VH$ ~hþ{dH$ënr (MCQ) VWm àíZ g§»`m 19 Ed§
20 A{^H$WZ Ed§ VH©$ AmYm[aV 1 A§H$ Ho$ àíZ h¢ &
(iv) IÊS> I _| àíZ g§»m 21 go 25 VH$ A{V bKw - CÎmar (VSA) àH$ma Ho$ 2 A§H$m| Ho$
àíZ h¢ &
(v) IÊS> J _| àíZ g§»m 26 go 31 VH$ bKw - CÎmar (SA) àH$ma Ho$ 3 A§H$m| Ho$ àíZ h¢ &
(vi) IÊS> K _| àíZ g§»m 32 go 35 VH$ XrK© - CÎmar (LA) àH$ma Ho$ 5 A§H$m| Ho$ àíZ h¢ &
(vii) IÊS> L> _| àíZ g§»`m 36 go 38 VH$ àH$aU AÜ``Z AmYm[aV 4 A§H$m| Ho$ àíZ h¢ &
àËoH$ àH$aU AÜ``Z _| Am§V[aH$ {dH$ën 2 A§H$m| Ho$ àíZ _| {Xm J`m h¡ &
(viii) àíZ- nÌ _| g_J« {dH$ën Zht {Xm Jm h¡ & `Ú{n, IÊS> I Ho$ 2 àíZm| _|, IÊS> J
Ho$ 2 àíZm| _|, IÊS> K Ho$ 2 àíZm| _| VWm IÊS> L> Ho$ 3 àíZm| _| Am§V[aH$ {dH$ën H$m àmdYmZ {Xm Jm h¡ &
(ix) Ohm± Amdí`H$ hmo p = 7
(^22) br{OE, {X AÝWm Z {Xm Jm hmo &
(x) H¡$ëHw$boQ>a H$m Cn`moJ d{O©V h¡ &
IÊS> H$
Bg IÊS> _| ~hþ{dH$ënràíZ h¢, {OZ_| àËoH$ àíZ 1 A§H$ H$m h¡ &
14-430(B) Page 4
(A) 5 (B) 3 (C) – 3 (D) – 5
ì`wËH«$_ h¡, Vmo ‘k’ H$m _mZ h¡ : (A) 3 (B) 5 (C) – 5 (D) – 3
Ûmam {Zê${nV aoImE± nañna g§nmVr h¢, h¡ : (A) 3 (B) – 3 (C) 6 (D) – 6
_yë₹ 2100 h¡, Vmo EH$ Hw$gu H$m _yë h¡ : (A) ₹ 100 (B) ₹ 110 (C) ₹ 150 (D) ₹ 450
14-430(B) Page 5 P.T.O.
(A) 5 (B) 3 (C) – 3 (D) – 5
the other, then the value of ‘k’ is : (A) 3 (B) 5 (C) – 5 (D) – 3
equations 3x + 5y = 2 and 9x + 15y = 2k coincide, is : (A) 3 (B) – 3 (C) 6 (D) – 6
₹ 2100, then the cost of one chair is : (A) ₹ 100 (B) ₹ 110 (C) ₹ 150
(D) ₹ 450
14-430(B) Page 7 P.T.O.
is : (A) 100 (B) 92 (C) – 92 (D) 96
(A) 87 (B) 77 (C) – 77 (D) – 87
(A) 6 (B) 8 (C) 4 (D) 2
A(– 7, 7) and B(– 3, 5), then the value of ‘a’ is : (A) 5 (B) – 4 (C) 2 (D) – 5
(A) 3 units (B) 5 units (C) – 5 units (D) 34 units
14-430(B) Page 8
{ÌÁm >5 cm h¡, H$s ñne© aoIm h¡ & ~mø d¥Îm H$s {ÌÁm h¡ :
(A) 13 cm
(B) 26 cm
(C) 601 cm
(D) 551 cm
2 2
q q – p
(B) q p
q^2 – p^2 q
(D) 2 2
p q – p
(A) 1
(B) – 1 2
(C) 1 2
(D) – 1
14-430(B) Page 10
dJ© A§Vamb (^1) – 10 11 – 20 21 – 30 31 – 40 41 – 50
~ma§~maVm (^10 12 20 5 )
(A) 1 6
(B) 1 3
(C) 1 2 (D) 0
(A) 1 7
(B) 2 7
(C) 3 7
(D) 4 7
14-430(B) Page 11 P.T.O.
Frequency 10 12 20 5 3
(A) 21 (B) 30· (C) 21· (D) 20·
greater than 3 is :
(A) 1 6
(B) 1 3
(C) 1 2 (D) 0
contain 53 Tuesdays is :
(A) 1 7
(B) 2 7
(C) 3 7
(D) 4 7
14-430(B) Page 13 P.T.O.
ratio of their surface areas is :
(A) 5 : 4 (B) 25 : 16
(C) 125 : 64
(D) 16 : 5
a cuboid. The total surface area of the resulting cuboid is :
(A) 192 cm 2
(B) 160 cm 2 (C) 128 cm 2
(D) 176 cm 2
Questions number 19 and 20 are Assertion and Reason based
questions. Two statements are given, one labelled as Assertion (A)
and the other is labelled as Reason (R). Select the correct answer to
these questions from the codes (A), (B), (C) and (D) as given below.
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
(C) Assertion (A) is true, but Reason (R) is false.
(D) Assertion (A) is false, but Reason (R) is true.
14-430(B) Page 14
616 cm^3 h¡ &
VH©$ (R) : {ÌÁm r VWm D±$MmB© h dmbo EH$ e§Hw$ H$m AmVZ 1 3
pr^2 h
hmoVm h¡ &
àm{`H$Vm 1 2
h¡ &
VH©$ (R) : EH$ nmgo H$mo |$H$Zo na Hw$b g§^m{dV n[aUm_m| H$s g§»m 6 h¡ VWm g_ g§»mE± 2, 4 d 6 h¢ &
IÊS> I
Bg IÊS> _| A{V bKw - CÎmar(VSA) àH$ma Ho$ àíZ h¢, {OZ_| àËoH$ àíZ 2 A§H$m| H$m h¡ &
2x – 3y – 17 = 0 Am¡a 4x + y – 13 = 0
^mÁhmoZo H$s àm{H$Vm kmV H$s{OE &
AWdm
(b) {gÕ H$s{OE {H$ cos^4 A – sin^4 A = 2 cos^2 A – 1.
àH$ma H$mQ>Vr h¡ {H$ LM ½½ QR h¡ & `{X PQ = 12 cm, PR = 10 cm VWm PL = 7·2 cm h¢, Vmo PM H$s b§~mB© kmV H$s{OE &
14-430(B) Page 16
(LCM) kmV H$s{OE & AWdm
(b) {H$gr Iob Ho$ _¡XmZ Ho$ Mmam| Amoa EH$ d¥ÎmmH$ma nW h¡ & Bg _¡XmZ H$m EH$ MŠH$a bJmZo _| VrZ gmB{H$b gdmam| H$mo H«$_e: 30 {_ZQ>, 40 {_ZQ> VWm 48 {_ZQ> bJVo h¢ & {X do VrZm| EH$ hr ñWmZ go Am¡a EH$ hr g_ na àma§^ H$aHo$ EH$ hr {Xem | OmVo h¢, Vmo {H$VZo g` ~mX do nwZ: àma§{^H$ ñWmZ na {_b|Jo? IÊS> J
Bg IÊS> _| bKw - CÎmar(SA) àH$ma Ho$ àíZ h¢, {OZ_| àËoH$ Ho$ 3 A§H$ h¢ &
VWm B(–^ 8, 9)^ H$mo {_bmZo dmbo aoImIÊS> H$mo {d^m{OV H$aVm h¡ & y^ H$m _mZ ^r kmV H$s{OE & AWdm (b) `{X A(2, – 2), B(7, 3), C(11, – 1) VWm D(6, – 6) EH$ MVw^w©O ABCD Ho$ erf© h¢ Vmo kmV H$s{OE {H$ ABCD H¡$gm MVw^w©O h¡ &
EH$ An[a_og§»m h¡ &
cos q – sin q = 2 sin q. AWdm
(b) {gÕ H$s{OE : (^) t
t a
an (^) + cot = 1 + tan + cot 1 – c to 1 – n
14-430(B) Page 17 P.T.O.
SECTION C
This section comprises Short Answer (SA) type questions of 3 marks each.
(b) Prove that t
t a
an cot
14-430(B) Page 19 P.T.O.
This section comprises Long Answer (LA) type questions of 5 marks each.
14-430(B) Page 20
IÊS> L>
Bg IÊS> | 3 àH$aU AÜ``Z AmYm[aV àíZ h¢ {OZ| àË`oH$ àíZ 4 A§H$m| H$m h¡ &
àH$aU AÜ``Z – 1
Ho$ {bE `h ~moQ> D$na (Ymam Ho$ à{VHy$b) OmZo _|, ZrMo (Ymam Ho$ gmW) OmZo go 40 {_ZQ> A{YH$ boVr h¡ &
Cn`w©º$ Ho$ AmYma na, {ZåZ{b{IV àíZm| Ho$ CÎma Xr{OE :
(i) {X Ymam H$s Mmb x km/h h¡, Vmo x Ho$ nXm| _| _moQ>a ~moQ> Ho$ D$na H$s {Xem _| OmZo H$s J{V ìº$ H$s{OE & 1
(ii) Cnw©º$ pñW{V H$mo x Ho$ ê$n _| {ÛKmV g_rH$aU _| ìº$ H$s{OE & 1
(iii) (a) Ymam H$s Mmb kmV H$s{OE & 2 AWdm
(b) {X Ymam H$s Mmb^ 10 km/h h¡, Vmo^ 40 km D$na H$s {Xem _| OmZo _| ~moQ> {H$VZm g_ boJr? 2
àH$aU AÜ``Z – 2
BbmHo$ Ho$ EH$ ñHy$b _| Hw$N> nm¡Yo bJmH$a Bgo gw§Xa ~ZmZo H$m {ZU©{bm & {d{^Þ Kam| Ûmam {XE JE nm¡Ym| H$s g§»`m {ZåZ gmaUr _| Xr JB© h¡ :
{XE JE nm¡Ym| H$s g§»m 1 –^4 4 –^7 7 –^10 10 –^13 13 –^16 16 –^19 Kam| H$s g§»m 10 8 9 7 12 4
(i) _mÜ`H$ dJ© {b{IE & 1
(ii) ~hþbH$ dJ© {b{IE & 1