maths past year solution, Exams of Mathematics

maths parta past year solutions

Typology: Exams

2023/2024

Uploaded on 03/05/2024

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Part - A
Answer all the questions. Each question carries 5 marks.
1. Can you logically replace (p q)with (pq)(¬p ¬q)? Ex-
plain your answer. [Where p and q are the atomic statements]
2. Does {n+1n}
1converge to 0? Explain your answer.
3. Let E={0} {1
n|nN}.f(x)is defined as follows:
f(x) = (n
n+1if x=1
n,n=1, 2, 3, ....
1 if x=0
Using ϵδdefinition, show that fis a continuous function on E
Part - A Solutions (These are not the only ways to solve the problems.)
1. Can you logically replace (p q)with (pq)(¬p ¬q)? Explain
your answer. [Where p and q are the atomic statements]
Answer (Hints):
p q (pq)
T T T
T F F
F T F
F F T
p q (pq)(¬p¬q)
T T T
T F F
F T F
F F T
Yes. We can.
2. Does {n+1n}
1converge to 0? Explain your answer.
Answer (Hints): Use the identity: xy=x2y2
x+y.
Therefore, |(n+1n)|=1
(n+1+n)<1
2n;
1
pf2

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Part - A

Answer all the questions. Each question carries 5 marks.

1. Can you logically replace (p ⇐⇒ q) with (p ∧ q) ∨ (¬p ∧ ¬q)? Ex-

plain your answer. [Where p and q are the atomic statements]

2. Does {

n + 1 −

n}∞ 1 converge to 0? Explain your answer.

3. Let E = { 0 } ∪ { n^1 |n ∈ N}. f (x) is defined as follows:

f (x) =

n

n+ 1 if^ x^ =^

1

n ,^ n^ =^ 1, 2, 3, ....

1 if x = 0

Using ϵ − δ definition, show that f is a continuous function on E

Part - A Solutions (These are not the only ways to solve the problems.)

1. Can you logically replace (p ⇐⇒ q) with (p ∧ q) ∨ (¬p ∧ ¬q)? Explain

your answer. [Where p and q are the atomic statements] Answer (Hints):

p q ( p ↔ q )

T T T

T F F

F T F

F F T

p q ( p ∧ q ) ∨ (¬ p ∧ ¬ q )

T T T

T F F

F T F

F F T

Yes. We can.

2. Does {

n + 1 −

n}∞ 1 converge to 0? Explain your answer.

Answer (Hints): Use the identity: x − y = x

(^2) −y 2 x+y.

Therefore, |(

n + 1 −

n)| = (√n+^11 +√n) < 2 √^1 n ;

1

given ϵ > 0, 2 √^1 n < ϵ if 41 n < ϵ^2 , i.e., if n > 41 ϵ 2

3. Let E = { 0 } ∪ { n^1 |n ∈ N}. f (x) is defined as follows:

f (x) =

n

n+ 1 if^ x^ =^

1

n ,^ n^ =^ 1, 2, 3, ....

1 if x = 0

Using ϵ − δ definition, show that f is a continuous function on E

Answer (Hints): Just check the continuity at x=0. For any ϵ > 0, take δ = ϵ.

Then for any x ∈ E ∪ (− δ , δ ), we have x = n^1 for some n > 1 δ = 1 ϵ. We have

then

| f (x) − f ( 0 )| = n+^11 < n^1 < ϵ

2