Electricity Exercises: Mains Electricity, Circuits, and Calculations, Exercises of Mathematics

A series of exercises and problems related to basic electricity, focusing on mains electricity parameters, circuit components, and calculations. it includes questions on the frequency and potential difference of mains electricity, the function of live and neutral wires, and calculations involving power and resistance. The exercises are designed to test understanding of fundamental electrical concepts and problem-solving skills. the document also includes a mark scheme, providing answers and explanations for each question. This makes it suitable for self-assessment and learning.

Typology: Exercises

2023/2024

Uploaded on 05/27/2025

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Download Electricity Exercises: Mains Electricity, Circuits, and Calculations and more Exercises Mathematics in PDF only on Docsity!

© Exampro 2017 Page 1

6 - 2 Electricity – Trilogy

1 .0 Most domestic appliances are connected to the mains electricity.

1.1 What is the frequency of mains electricity?

Tick one box

[1 mark]

1.05 A

50 Hz

230 V

1.2 What is the potential difference of mains electricity?

Tick one box

[1 mark]

1.05 A

50 Hz

230 V

1.3 Most domestic appliances are connected to the mains electricity with a plug.

Explain why a plug needs a live and a neutral wire.

[2 marks]

_____________________________________________________________________

_____________________________________________________________________

1.4 The law specifies the colour that mains wires should be for all domestic electrical

circuits.

It is important that the live wire is easy to identify to reduce the risk of an electric shock.

Explain how an electric shock can be caused by a person touching the live wire.

[2 marks]

_____________________________________________________________________

_____________________________________________________________________

The live wire carries current to the appliance and the

neutral wire is needed to complete the circuit bringing

any current back to the plug.

The live wire has current flowing through it and has a

high potential difference at 230V compared to a human

at around 0v this means charge can flow from the live

wire to the human causing an electric shock.

© Exampro 2017 Page 2

1.5 An iron is supplied with a current of 3 A from the mains. The resistance of the iron is

Calculate the power of the iron.

[2 marks]

Power = ______________ W

2 .0 A student wants to investigate how the current through a filament lamp affects its resistance.

2.1 Use the circuit symbols in Figure 1 to draw a circuit diagram that he could use.

[2 marks]

Figure 1

12 V battery variable

resistor

filament

lamp

voltmeter ammeter

2.2 Describe how the student could use her circuit to investigate how the current through a

filament lamp affects its resistance.

[4 marks]

_____________________________________________________________________

_____________________________________________________________________

_____________________________________________________________________

_____________________________________________________________________

First, measure the initial current and potential

difference in the series circuit after you have the

reading take out the battery.Then increase the

resistance using the variable resistor to get positive

values and switch battery to get negative values for

it.Next, plot these values on a graph.The graph

should have a S shape.

© Exampro 2017 Page 4

4. 0 A student investigated how current varies with potential difference for two different

lamps of the same type.

Her results are shown in the Figure 3 below.

Figure 3

4.1 Draw the circuit diagram for the circuit that the student could have used to obtain the

results shown in the figure above.

[3 marks]

4.2 The student made the following conclusion,

‘Lamp A is twice a bright as lamp B’.

Use data from Figure 3 to explain why the student’s conclusion is correct.

[3 marks]

_____________________________________________________________________

____________________________________________________________________

_____________________________________________________________________

At all potential differences current was double in lamp

A compared to lamp B, for example at 6V current was

0.3 amps in lamp B compared to 0.6 in lamp A and so

a higher current means an increase in light intensity.

© Exampro 2017 Page 7

MARK SCHEME

Qu No. Extra Information Marks 1.1 50 Hz 1 1.2 230 V 1 1.3 Live wire carries the (alternating) potential difference/voltage (from the supply) Neutral wire completes the circuit

1.4 connection is made to earth charge can flow through the body. or large potential difference across the body Accept answer in terms of a complete circuit or establishing a path (for charge to flow)

  1. 5 P = (3)^2 x 100 900 (W) Allow one mark for P=I^2 V if substitution incorrect. Allow 900 (W) with no working for 2 marks

Qu No. Extra Information Marks 2.1 battery, lamp and ammeter connected in series with variable resistor voltmeter in parallel with (filament) lamp

Level 2: (^) A detailed and coherent description of the experiment. The response provides a logical sequence.

Level 1: Simple description of the experiment with some steps missing. The response may not be in a logical sequence and may not lead to the collection of valid results.

Level 0: No relevant content. 0 Indicative content

  • ammeter used to measure current
  • voltmeter used to measure potential difference
  • resistance of variable resistor altered to change current in circuit or change potential difference (across filament lamp)
  • resistance (of filament lamp) calculated or R=V / I statement resistance calculated for a large enough range of different currents that would allow a valid conclusion about the relationship to be made

© Exampro 2017 Page 8

Qu No. Extra Information Marks 3 .1 V = 0.025 × 75 1.9 (V) Allow 1.9 (V) with no working for 2 marks

3 .2 total resistance = 6 / 0. R = 240 - 225 = 15 (Ω)

3 .3 resistance decreases current increases

Qu No. Extra Information Marks 4 .1 battery in series with bulb and ammeter voltmeter in parallel with the bulb variable resistor or variable power supply

4 .2 correct pair of current readings at the same pd therefore current in lamp A is twice the current in lamp B so lamp A is twice as powerful and lamp B (hence is twice as bright) eg at 10 V, IA = 0.74A and IB = 0.37A must refer to power/rate of energy transfer

4 .3 R = V / I

lowest R = 0.6 / 0. R = 6 Ω Highest R = 10 / 0. R = 13.5 Ω Difference = 13.5 – 6 = 7.5 Ω allow R= 1.0 / 0. R = 6.25 Ω (other values may be acceptable but the values from the graph must be when V ≤ 1V and the lamp can reasonably be assumed to be ohmic) allow 7.25 Ω if consistent