Maxwell Theorem - General Physcis - Lecture Slides, Slides of Physics

This course covers Force, acceleration, gauss law, ideal law, polarization, newton laws, pendulum, reflection and refraction equations, kinetic energy, RC circuits, fusion and many other topics. Key points of this lecture are: Maxwell theorem, Em Waves, Four Laws of Electromagnetism, Ambiguity in Ampere’S Law, Maxwell’S Equations, Maxwell’S Equations in Vacuum, Electromagnetic Waves, Plane Electromagnetic Wave, Gauss’S Laws, Faraday’S Law

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Short Version : 29. Maxwell’s Equations & EM Waves
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Download Maxwell Theorem - General Physcis - Lecture Slides and more Slides Physics in PDF only on Docsity!

Short Version :

29. Maxwell’s Equations & EM Waves

29.1. The Four Laws of Electromagnetism Law

Mathematical

Statement

PhysicalMeaning

Gauss for

E

q^0

d

^

E

A

How

q

produces

E

;

E

lines begin & end on q’s.

Gauss for

B

Faraday

Ampere (Steady

I^

only)

4 Laws of EM (incomplete)

d^

^

B

A

B

d

d^

d t

^

E

r

0

d^

I

 

^

B

r

No magnetic monopole; B

lines form loops. Changing

B^

gives emf.

Moving charges give

B

.

Note

E

  • B

asymmetry between the Faraday & Ampere laws.

29.3. Maxwell’s Equations

Law

Mathematical

Statement

PhysicalMeaning

Gauss for

E

q^0

d

^

E

A

How

q

produces

E

;

E

lines begin & end on q’s.

Gauss for

B

FaradayAmpere-Maxwell

d^

^

B

A

B

d

d^

d t

^

E

r

No magnetic monopole; B

lines form loops. Changing

B^

gives emf.

Moving charges &changing

E^

give

B

.

0

0

0

E d

d^

I^

d t

^

^

^

^

B

r

Maxwell’s Eqs (1864).Classical electromagnetism.

Maxwell’s Equations in Vacuum

Gauss for

E

d^

^

E

A

Gauss for

B

Faraday Ampere-Maxwell

d^

^

B

A

B

d

d^

d t

^

E

r

0

0

E d

d^

d t

^

^

B

r

Plane Electromagnetic Wave

EM wave in vacuum is transverse:

E

B

k

(direction of propagation)

For uniqueness, see Prob 46

Sinusoidal plane waves going in

x

-direction:

^

^

^

^

,^

y

x t

E

x t

E

j

^

^

^

^

,^

z

x t

B

x t

B

k

ˆ^

k

E

B

^

Right-hand rule

^

^

sin p E

kx

t

^

^

j

^

^

sin p B

kx

t

^

k

Gauss’s Laws

^

^

sin p E

kx

t

^

j

Both

E

&

B

field lines are straightlines,

so their flux over any closed surfaces vanish identically.Hence the Gauss’s laws are satisfied.

Plane wave :

^

^

^

^

,^

y

x t

E

x t

E

j

^

^

^

^

,^

z

x t

B

x t

B

k^

^

^

sin p B

kx

t

^

^

k

Ampere-Maxwell Law

0

0

E

C

d

d^

d t

^

^

B

r

^

^

^

C^

d^

B

x^

h^

B

x^

dx

h

^

^

B

r

I^

For loop at

x

of height

h

& width

dx

^

^

^

,^

,^

B

B

x t

h^

B

x t

d x

h

x

^

^

^

^

B

d x

h

x ^

^

^

E^

E h dx

E d^

E

h dx

d t

t

Ampere-Maxwell Law :

0

0

B

E

x^

t

^

^

^

Ampere-Maxwell law expressed as a differential eq :

0

0

t

^

^

E 

B

in vacuum

B

B

z ˆ EE

y

0

0

y

z^

E

B x

t

^

 Docsity.com

Conditions on Wave Fields

Faraday’s Law :

E

B

x^

t

^

^

Ampere-Maxwell Law :

0

0

B

E

x^

t

^

^

For

E

E

( x,t

)^

j^

B

B

( x,t

)^

k

For a plane wave

^

^

^

^

,^

sin p

x t

E

kx

t

^

E

j^

^

^

^

^

,^

sin p

x t

B

kx

t

B

k

^

^

^

cos

cos

p^

p

k E

k x

t^

B

k x

t

Faraday’s Law :

p^

p

k E

B

Ampere-Maxwell Law :

^

^

^

0

0

cos

cos

p^

p

k B

k x

t^

E

k x

t

^

^

0

0

p^

p

k B

E

^

x^

y^

z

x^

y^

z

V

V

V

^

^

^

^

^

i^

j^

k

V

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Example 29.2. Laser Light

A laser beam with wavelength 633 nm is propagating through air in the +z direction.Its electric field is parallel to the

x

axis and has magnitude 6.0 kV/m.

Find

(a) the wave frequency,(b) the amplitude of the magnetic field, and(c) the direction of the magnetic field.

c

f

(a)

8

9

m

s m

14

H

z

^

E

B

c

(b) (c)

y axis.

3 8

V

m m

s

5

T

T

Docsity.com

Polarization

Polarization

E

Radiation from antennas are polarized.E.g., radio, TV, ….Light from hot sources are unpolarized.E.g., sun, light bulb, …

Reflection from surfaces polarizes.E.g., light reflecting off car hoods is partially polarized inhorizontal direction.Transmission through crystal / some plastics polarizes.E.g., Polaroid sunglasses, …

Law of Malus :

Only component of

E

// preferred direction

e

is transmitted.

2

2

2 cos

trans

inc

E

E

^

ˆ^ 

trans

inc

^

E

E

ε^

ε^

cos inc E

ε

^

= angle between

E

inc

&

. 2 cos

trans

inc

S^

S

or

ˆ^

ε^

j^ ˆ ˆ^

ε^

k

Conceptual Example 29.1. Crossed Polarizers

Unpolarized light shines on a pair of polarizers with their transmissionaxes perpendicular, so no light gets through the combination.What happens when a third polarizer is sandwiched in between, with itstransmission axes at 45

^

to the others?

st^

& middle polarizers not

so some light passes through.

Passed light’s polarization not

to axis of last polarizer so

some light passes through.

Making the Connection

How does the intensity of light emerging from this polarizer “sandwich”compare with the intensity of the incident unpolarized light?

2 cos

trans

inc

S^

S

Intensity of light emerging from 1

st^

polarizer :

2

2

1

0 1

cos

inc

S^

S^

d

^

^

^

inc S

^

( polarized along axis of 1

st^

polarizer )

Intensity of light emerging from middle polarizer :

2

2

1

cos 45

S^

S

^

^

1 1 2

S

^

inc S

Intensity of light emerging from ensemble :

2

3

2

cos 45

S^

S

^

^

2 1 2

S

^

inc S

( polarized along axis of middle polarizer.)( polarized along axis of 3

rd^

polarizer.)

29.7. Producing Electromagetic Waves

Any changing

E

or

B

will create EM waves.

Any accelerated charge produces radiation.Radio transmitter: e’s oscillate in antenna driven by

LC

circuit.

X-ray tube: accelerated e’s slammed into target.MW magnetron tube: e’s circle in

B

.

EM wave : f^

=^

f^ of

q

motion

Most efficient:

^

~ dimension of emitter / reciever

Waves emit / receive

axis of dipole.

Sourcereplenishesradiatedenergy

LC oscillatordrives

I^

in

antenna

OutgoingEM waves

29.8. Energy & Momentum in Electromagetic Waves

Consider box of thickness

dx

, & face

A

k

of EM wave.

2 0 1 2

E u

E

Energy densities:

2 0 1 2

u^ B

B

Energy in box:

^

E^

B

dU

u^

u^

A dx

^

2

2

0

0

A

dx

^

^

^

^

E

B

Rate of energy moving through box:

dU

d U

d t

dx

c

2

2

0

0

A

c

^

^

^

^

E

B

Intensity

S

= rate of energy flow per unit area

2

2

0

0

S^

c

^

^

^

^

^

E

B

Plane waves:

E

B

c

0

0

S^

c^

E B c

c

^

^

^

^

^

2

0

0

0 1

c^

E B

^

E

B