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MCAT FORMULAS 2026 STUDY GUIDE
Typology: Exams
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Distance formula - ANSWER d=vt VAT - ANSWER Vf = V₀ + at VAX - ANSWER Vf² = V₀² + 2a∆x TAX - ANSWER ∆x = v₀t + 1/2at² centripetal motion (2) - ANSWER Ac = V²/ r Fc = mv²/ r Law of gravitation - ANSWER F=GM₁M₂/ r² Newtons second law - ANSWER Fnet = ma Kinetic friction - ANSWER Fk = μkFn Static friction - ANSWER Fs≤ μsFn Torque - ANSWER t = F x r t = Flsinθ (l=length) Hooke's law - ANSWER F = - Kx (K= spring const) Kinetic energy - ANSWER KE = 1/2 mv² Gravitational Potential energy - ANSWER PE = mgh Spring PE - ANSWER PE = 1/2 Kx² power - ANSWER P = W/t (work/ time) work - ANSWER W=Fdcosθ momentum - ANSWER p = mv Conservation of momentum - ANSWER m₁v₁ + m₂v₂ = m₁v₁ + m₂v₂ Ohms law (2) - ANSWER P=IV V=IR (v = volts, I= current, R = resistance, P= power) current - ANSWER I = ∆q/ ∆t (q = charge)
Capacitors in sieres - ANSWER 1/Cs = 1/C₁ + 1/C₂ + etc Capacitors in parallel - ANSWER Cp = C₁ + C₂ + etc Resistors in series - ANSWER Rs = R₁ + R₂ + etc Resistors in parallel - ANSWER 1/Rp = 1/R₁ + 1/R₂ + etc electrostatic force - ANSWER F = Kq₁q₂/ r² electric field - ANSWER E = R/q₀ Capacitance - ANSWER q = VC energy stored by capacitor - ANSWER U = 1/2CV² electric field due to point charge - ANSWER E = Kq/ r² electrical potential - ANSWER ∆V = ∆U/q₀ magnetic force around wire - ANSWER B = μ₀I/ 2πr (I= currant) magnetic force (2)_ - ANSWER F =qvBsinθ F = ILBsinθ electrical potential of point charge - ANSWER V = Kq/r magnetic field at center of wire loop - ANSWER B = μ₀I/ 2r density - ANSWER p = m/V pressure - ANSWER P = F/A specific gravity - ANSWER s.g = psub/ pwater (p = density) osmotic pressure - ANSWER π = MRT buoyant force - ANSWER Fb = pVg total pressure of fluid - ANSWER Ptot = Patm + Pgauge continuity equation - ANSWER A₁V₁ = A₂V₂ termal expansion (2) - ANSWER ∆L = αL∆T ∆V=βV∆T
AX --> A Y + 0 e Z Z- 1 +1 - ANSWER beta-plus decay ideal gas law - ANSWER PV = nRT (R=0.083 Latm/molK) charles law - ANSWER V₁/T₁ = V₂/T₂ pH - ANSWER pH = - log [H] electromotive force - ANSWER EMF = E⁰red + E⁰ox Dilution equation - ANSWER M₁V₁ = M₂V₂ EMF equation - ANSWER Ecell = Ecathode - Eanode Boyles law - ANSWER P₁V₁ = P₂V₂ Avogadros law - ANSWER n₁/V₁ = n₂/V₂ Hardy-wienbery equations (2) - ANSWER p+q = 1 P² + 2pq + q² = 1