Midterm 3 with Solution - Calculus I | MATH 1210, Exams of Mathematics

Material Type: Exam; Professor: Wills; Class: SI Calculus I; Subject: Math; University: Weber State University; Term: Unknown 2006;

Typology: Exams

Pre 2010

Uploaded on 07/22/2009

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Mathematics 1210
Autumn 2006
Instructor: Mike Wills
Practice Midterm 3 Solutions
Problem #1 (5 points):
Let f(x) = 2 cos xsin x. Find the indefinite integral of f.
Solution
By the half angle formula,
(1) Z2 cos xsin xdx =Zsin(2x)dx =cos(2x)
2+C
where Cis an arbitrary constant.
Problem #2 (5 points):
It costs Cut-Me-Own-Throat Dibbler 4 + 3x+x2Ankh-Morpork
dollars to procure 100xsausage-inna-buns. Find Dibbler’s average cost
and marginal cost. What procurement level will minimize the average
cost?
Let C(x) = 4 + 3x+x2. Then the average cost is given by A(x) =
C(x)
x=4
x+ 3 + x. The marginal cost will be given by c(x) = C0(x) =
3+2x. The minimum cost occurs when
c(x) = A(x)
3+2x=4
x+3+x
x=4
x
x2= 4.
(2)
Since x0 we conclude that x= 2. Thus, when Dibbler procures 200
sausage-inna-buns, his cost is minimized.
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Mathematics 1210 Autumn 2006 Instructor: Mike Wills

Practice Midterm 3 Solutions Problem #1 (5 points):

Let f (x) = 2 cos x sin x. Find the indefinite integral of f. Solution By the half angle formula,

(1)

2 cos x sin xdx =

sin(2x)dx = −

cos(2x) 2

+ C

where C is an arbitrary constant.

Problem #2 (5 points):

It costs Cut-Me-Own-Throat Dibbler 4 + 3x + x^2 Ankh-Morpork dollars to procure 100x sausage-inna-buns. Find Dibbler’s average cost and marginal cost. What procurement level will minimize the average cost?

Let C(x) = 4 + 3x + x^2. Then the average cost is given by A(x) = C(x) x =^

4 x + 3 +^ x. The marginal cost will be given by^ c(x) =^ C

′(x) =

3 + 2x. The minimum cost occurs when

c(x) = A(x)

3 + 2x =

x

  • 3 + x

x =

x x^2 = 4.

Since x ≥ 0 we conclude that x = 2. Thus, when Dibbler procures 200 sausage-inna-buns, his cost is minimized.

Problem #3 (5 points): Carefully define what it means for the function f to be integrable on the interval [a, b].

Solution Let n ∈ N. Let ∆x = b−n a. For i = 0, 1 ,... , n, define xi = a + i∆x.

For i = 1,... , n, let x∗ i ∈ [xi− 1 , xi]. Let Sn =

∑^ n

i=

f (x∗ i )∆x. We say

that f is integrable if lim n→∞

Sn exists.

Problem #4 (5 points):

Compute

1 (x

(^3) − √x)dx.

Solution We compute: ∫ (^4)

1

(x^3 − x

1 (^2) )dx = x

4 4

2 x

(^32)

3

4 1

=