MATH 3150 Midterm Test 2: Solutions for PDEs in Engineering, Exams of Mathematics

The solutions for midterm test 2 of math 3150: pdes for engineers. Topics covered include d'alembert's solution for the wave equation, the heat equation, rescaling operators, and the laplace equation. Students are expected to understand concepts related to partial differential equations, wave propagation, heat transfer, and fourier series.

Typology: Exams

Pre 2010

Uploaded on 08/31/2009

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MATH 3150: PDE FOR ENGINEERS
MIDTERM TEST #2
Name:
Work out everything as far as you can before making decimal approximations.
1. Consider d’Alembert’s solution
u(x, t) = 1
2(f(xct) + f(x+ct)) + 1
2cZx+ct
xct
g(s)ds
of the wave equation for a vibrating string, where f(x) is the odd function with
period 2Lwhich on the interval 0 xLgives the initial position of the string,
and similarly g(x) gives the initial velocity on 0 xLand is odd and 2Lperiodic.
Suppose that
f(x) = sin πx
g(x) = 0
with L= 1 and c=1
π. What is the first positive time tthat the string returns to
its original shape?
Date: October 26, 2000.
1
pf3
pf4
pf5

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MATH 3150: PDE FOR ENGINEERS

MIDTERM TEST

Name:

Work out everything as far as you can before making decimal approximations.

  1. Consider d’Alembert’s solution

u(x, t) =

(f (x − ct) + f (x + ct)) +

2 c

∫ (^) x+ct

x−ct

g(s) ds

of the wave equation for a vibrating string, where f (x) is the odd function with period 2L which on the interval 0 ≤ x ≤ L gives the initial position of the string, and similarly g(x) gives the initial velocity on 0 ≤ x ≤ L and is odd and 2L periodic. Suppose that f (x) = sin πx g(x) = 0

with L = 1 and c = (^) π^1. What is the first positive time t that the string returns to its original shape?

Date: October 26, 2000. 1

  1. Use separation of variables to find the general solution of the heat equation in a rectangular plate with edges of lengths a and b, and with all edges insulated.
  1. Show that the function

un(r, θ) =

( (^) r R

)n (an cos(nθ) + bn sin(nθ))

satisfies the Laplace equation ∇^2 u = 0 on the disk of radius R, where in polar coordinates

∇^2 u = ∂^2 u ∂r^2

r

∂u ∂r

r^2

∂^2 u ∂θ^2

Now adding these together, why does the function

u(r, θ) = a 0 +

∑^ ∞

n=

( (^) r R

)n (an cos (nθ) + bn sin (nθ))

satisfy the Laplace equation? Moreover show that if we pick these a 0 , am and bm according to

a 0 =

2 π

∫ (^2) π

0

f (θ) dθ

am =

π

∫ (^2) π

0

f (θ) cos(nθ) dθ

bm =^1 π

∫ (^2) π

0

f (θ) sin(nθ) dθ

(as Fourier amplitudes of f (θ)) then

u(R, θ) = f (θ)

so that this is the steady state of the heat equation in the disk with boundary held fixed at temperature u(R, θ) = f (θ).

0 –0.5 – 1 0.5 x

–0. 0 0. 1

y

1

Figure 1. A round peak

  1. Looking at the wave equation ∂^2 u ∂t^2 =^ c

2

∂^2 u ∂x^2 +^

∂^2 u ∂y^2

and recalling second derivatives from calculus, explain why a round peak in the graph of u (as in figure 1) will be accelerated downward.