Stoichiometry Review Guide: Answers to Chapter 9 Chemistry Questions, Exercises of Stoichiometry

The answers to the questions related to stoichiometry concepts covered in chapter 9 of a high school chemistry textbook. It includes questions on balanced equations, molar quantities, and mass-mass relationships.

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Chemistry Name ________________________
Mr. Reger
Review Guide Ch. 9 - Stoichiometry Date ______________ Period _____
2 Cu (s) + O2(g) 2 CuO (s)
1. The balanced equation above tells us that 1 mol of copper
a) reacts with 1 mol of O2(g)
b) produces 1 mol of CuO
c) must react with 32g O2(g)
d) cannot react with oxygen
e) produces 2 mol of CuO
2. A 3.0-mol sample of KClO3 was decomposed according to the equation below.
2 KClO3(s) 2 KCl(s) + 3 O2(g)
How many moles of O2(g) are expected to form?
a) 2.0 mol
b) 2.5 mol
c) 3.0 mol
d) 4.0 mol
e) 4.5 mol
3. Excess Al is reacted with 6.0 mol Br2 according to the equation below.
2 Al + 3 Br2 2 AlBr3
How many moles of AlBr3 are expected to form?
a) 2.0
b) 3.0
c) 4.0
d) 6.0
e) 8.0
4. Using the chemical equation below, determine how many moles of NH3 will be produced if
100.g of N2 is reacted with excess H2.
__ N2(g) + __ H2(g) __ NH3(g)
a) 2.00 mol
b) 3.57 mol
c) 7.14 mol
d) 33.3 mol
e) none of the above
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Chemistry Name ________________________ Mr. Reger Review Guide – Ch. 9 - Stoichiometry Date ______________ Period _____

2 Cu (s) + O 2 (g)  2 CuO (s)

1. The balanced equation above tells us that 1 mol of copper a) reacts with 1 mol of O 2 (g) b) produces 1 mol of CuO c) must react with 32g O 2 (g) d) cannot react with oxygen e) produces 2 mol of CuO 2. A 3.0-mol sample of KClO 3 was decomposed according to the equation below. 2 KClO 3 (s) 2 KCl(s) + 3 O 2 (g) How many moles of O 2 (g) are expected to form? a) 2.0 mol b) 2.5 mol c) 3.0 mol d) 4.0 mol e) 4.5 mol 3. Excess Al is reacted with 6.0 mol Br 2 according to the equation below. 2 Al + 3 Br 2  2 AlBr 3 How many moles of AlBr 3 are expected to form? a) 2. b) 3. c) 4. d) 6. e) 8. 4. Using the chemical equation below, determine how many moles of NH 3 will be produced if 100.g of N 2 is reacted with excess H 2.

__ N 2 (g) + __ H 2 (g)  __ NH 3 (g) a) 2.00 mol b) 3.57 mol c) 7.14 mol d) 33.3 mol e) none of the above

5. Using the equation below, determine what mass of O 2 (g) is required to react completely with 25.0g of C 6 H 14 (l). 2 C 6 H 14 (l) + 19 O 2 (g)  12 CO 2 (g) + 14 H 2 O(l) a) 9.28 g b) 16.0 g c) 32.0 g d) 88.2 g e) 608 g 6. Using the reaction in question #5, what mass of CO 2 (g) can be produced from 25.0 g C 6 H 14 and excess O 2? a) 12.8 g b) 44.0 g c) 76.6 g d) 264 g e) 528 g 7. Using the reaction below, determine how many moles of O 2 are needed to react with 11.2g of C 8 H 18. 2 C 8 H 18 (g) + 25 O 2 (g)  16 CO 2 (g) + 18 H 2 O(l) a) 2.46 mol b) 1.23 mol c) 0.615 mol d) 140. mol e) 3.15 mol 8. Using the chemical equation in question #7, calculate the mass of CO 2 (g) produced from 11.2g C 8 H 18. a) 34.5 g b) 89.6 g c) 17.3 g d) 46.2 g e) 58.9 g 9. In the reaction below, how many moles of Cl 2 (g) are needed to react with 10.9 g of NaOH? 3 Cl 2 (g) + 6 NaOH(aq)  5 NaCl(aq) + NaClO 3 (aq) + 3 H 2 O(l)

Answers (Ch. 9 Review Guide – Stoichiometry)

  1. B
  2. E
  3. C
  4. C
  5. D
  6. C
  7. B
  8. A
  9. 0.136 mol Cl 2
  10. 13.3g NaCl
  11. a. 140g NaClO 3 b. 67% c. 66g NaClO 3
  12. 80.%
  13. a. CaCl 2 b. 0.5g Na 2 CO 3 left c. 0.180 mol NaCl d. 10.5g NaCl e. 65%
  14. a. O 2 b. 2.8g N 2 c. 7.2g NO 2 d. 31%
  15. a. 108g NO 2 produced (O 2 is limiting) b. 100.g NO 2 actually obtained c. 21.3g O 2 needed and 9.32g N 2 needed (30.6g NO 2 is the theoretical yield)