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This file contains solution to problems related Data Communication Systems. Mr. Prajin Ahuja assigned task at Birla Institute of Technology and Science. Its main points are: Multiple, Access, Dom, Access, Controlled, Channelization, Reservation, Polling, Token, Passing
Typology: Exercises
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This means that each station can successfully send only 1.35 frames per second.
Data rate = 10 Mbps → minimum frame size = 512 bits Data rate = 100 Mbps → minimum frame size = 5120 bits Data rate = 1 Gbps → minimum frame size = 51,200 bits Data rate = 10 Gbps → minimum frame size = 512,000 bits
Figure 12.1 Solution to Exercise 19
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W 8 =
Frame 4 for all four stations: 4 × [poll + frame + ACK)] Frame 5 for all four stations: 4 × [poll + frame + ACK)] Polling and Sending NAKs Station 1: [poll + NAK] Station 2: [poll + NAK] Station 3: [poll + NAK] Station 4: [poll + NAK] Total Activity: 24 polls + 20 frames + 20 ACKs + 4 NAKs = 21536 bytes We have 1536 bytes of overhead which is 512 bytes more than the case in Exercise