Multivariable Calculus Notes for Exams | MATH 2224, Study notes of Calculus

section 8.2 Material Type: Notes; Class: Multivariable Calculus; Subject: Mathematics; University: Virginia Polytechnic Institute And State University; Term: Fall 2008;

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Sec 8.2 Series
Part 1
A series is simply the sum of the terms of a sequence.
1234
1n
n
aaa aa
=
=+ + + +
" is called an infinite series where an is the nth term of the series.
Associated with any infinite series is a sequence (list), {sn} = s1, s2, s3, s4, " , of partial sums where :
s1 = a1,
s2 = a1 + a2,
s3 = a1 + a2 + a3,
s4 = a1 + a2 + a3 + a4,
#
s
k = a1 + a2 + a3 + a4 + " + ak
Given a series 1234
1n
n
aaa aa
=
=+ + + +
", let sn denote its nth partial sum: 12
1
...
n
ni n
i
saaa a
=
==+++
Partial Sums Test:
If the sequence {sn} is convergent and lim n
nss
→∞
=
exists as a real number, then the series n
a
is
convergent and we write
1n
n
as
=
=
. The number s is the sum of the series. If the limit does not exist, the
series is divergent.
Telescoping Series: The terms of a series cancel in pairs. Hence the sum collapses into just two terms.
Use the partial sums test and look at the limit of those two terms to determine convergence.
EX 1
1
11
ln( 2) ln( 1)
nnn
=
⎛⎞
⎜⎟
++
⎝⎠
pf3

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Sec 8.2 Series Part 1

A series is simply the sum of the terms of a sequence.

1 2 3 4 1

n n

a a a a a

=

∑ =^ +^ +^ +^ +"^ is called an^ infinite series^ where a^ n^ is the n^ th^ term of the series.

Associated with any infinite series is a sequence (list), {sn } = s 1 , s 2 , s 3 , s 4 , " , of partial sums where :

s 1 = a 1 , s 2 = a 1 + a 2 , s 3 = a 1 + a 2 + a 3 , s 4 = a 1 + a 2 + a 3 + a 4 ,

s (^) k = a 1 + a 2 + a 3 + a 4 + " + a (^) k

Given a series (^) 1 2 3 4 1

n n

a a a a a

=

∑ =^ +^ +^ +^ +"^ ,^ let^ s^ n^ denote its nth partial sum :^1

1

n n i n i

s a a a a

Partial Sums Test:

If the sequence {sn } is convergent and lim (^) n n s s →∞

= exists as a real number, then the series ∑ an is

convergent and we write 1

n n

a s

=

∑ =.^ The number s is the sum of the series. If the limit does not exist, the

series is divergent.

Telescoping Series: The terms of a series cancel in pairs. Hence the sum collapses into just two terms. Use the partial sums test and look at the limit of those two terms to determine convergence.

EX 1

1

n ln(^ n^ 2)^ ln(^ n 1)

=

⎝ +^ + ⎠

Properties of Series:

1

n n

c a

=

∑ ⋅ =^

1

n n

c a

=

∑. If^

1

n n

a

=

∑ diverges, then^

1

n n

c a

=

∑ diverges.

1

n n n

a b

=

∑ ± =^

1

n n

a

=

∑ ±^

1

n n

b

=

∑. If both^

1

n n

a

=

∑ and^

1

n n

b

=

∑ both converge, then^ (^ )

1

n n n

a b

=

∑ ± converges. If

either 1

n n

a

=

∑ or^

1

n n

b

=

∑ converges and the other diverges, then^ (^ )

1

n n n

a b

=

∑ ± diverges. If both^

1

n n

a

=

∑ and

1

n n

b

=

∑ diverge, you can't tell if^ (^ )

1

n n n

a b

=

∑ ± converges or diverges.

Geometric Series: A series of the form^1 1

n n

ar

∞ − =

∑ = a + ar + ar^

(^2) + ar 3 + ar 4 + " , where a and r are real

numbers with a0, is called a geometric series.

Convergence/Divergence of a Geometric Series

The series^1 1

n n

ar

∞ − =

∑ converges to^ 1

ar

if |r| < 1 and diverges if |r|1.

EX 2 Show the following series are geometric series. Then test for convergence. If convergent, find the sum.

A. 2 + 4 +8+ 16 + 32 + "

B.

0

n n n

=

C. 1

n n n

e − =