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CBSE Worksheet
Class 5 Maths
Chapter 11 - Area and Its Boundary
1. Complete The following table. Length Breadth Area Perimeter 8 m 9 m _________ 34 m 6 m 8 m __________ _________ 15 m ________ 105 m² ___________ 63 m 6 m ________ ____________ 47m ________ _________ 112 2.Which of the following figure has more area? Image: Rectangle Image: Rectangle
3.Find the area of the given figure Image: Rectangle 4.Fill in the blanks: i. The region encompassed within a figure's borders is referred to as its ________. ii. Area of a rectangle = ____ × ____ iii. Area of a square = ____ × ____. iv. The sum of the total length of all the line segments of a simple closed figure is ________. 5.What is the area of a rectangle whose length is 12 m and breadth is 9 m? 6.What is the area of a square whose each side is 10 cm? 7.What is the area of a rectangle whose length is 30 cm and breadth is 6 cm? 8.What has the greater area, a square of side 10 cm or a rectangle of length 5 cm breadth 2 cm? 9.What is the area of the square whose each side is 12 cm? 10.If the perimeter of the square is 60 cm, then what will be each side of the square? 11.In a square room with a side of 6 m, Raju laid a square carpet with a side of 4 m. How much floor space in the room will be left without carpet?
Image: An image of carpet 16.Nehal is constructing a fence around her garden to prevent her favourite dog from escaping. What is the required fence length if the garden is 6 m broad and 9 m long? How much area does the dog have to run about in? Image: An image of a garden 17.Find the perimeter of the square whose side lengths are a) 5 m
b) 6 m c) 7 m d) 12 m 18.Find the length of the side of the square with the following perimeters. a) 32 m b) 40 m c) 44 m d) 20 m 19 .A rectangular garden of length 15 m and breadth 13 m has to be fenced all around. What length of fencing will be required? 20.Mukesh wants to paste a ribbon around a square painting with each side = 20 cm. What length of ribbon will be required? Image: An image of a painting Answers: 1.Length = 8m,Breadth = 9m
6 m 8 m 48 m² 28 m 15 m 7 m 105 m² 44 m 63 m 6 m 378 m² 138 m 47m 9 m 423 m² 112 2.Area of piece A = Length × Breadth = 6 cm × 5 cm = 30 cm² Area of piece B = Length × Breadth = 11 cm × 3 cm = 33 cm² So, piece B has more area. 3.Area = length × breadth = 14 cm × 20 cm = 280 cm² 4.(a) Area (b) Length, Breadth (c) Side, Side (d) Perimeter 5.Area of rectangle = length × breadth = 12 m × 9 m = 108 m²
6.Area of square = (side)² = (10 cm)² = 100 cm² 7.Area of rectangle = length × breadth = 30 cm × 6 cm = 180 cm² 8.Area of square = (side)² = (10 cm)² = 100 cm² Area of rectangle = length × breadth = 5 cm × 2cm = 10 cm² By these results we can say that the square of side 10 cm has a greater area. 9.Area of square = (side)² = (12 cm)² = 144 cm² 10.Perimeter of square = 4 × side 60 = 4 × side Side = 60/ Side = 15 cm 11.Area of square room = (side)²
Area of door = Length × Breadth = 2 m× 1 m = 2 m² Area which should be covered with wallpaper = 36 m²-2m² = 34 m² 15.Area of carpet = Length×Breadth = 7 m × 5 m = 35 m² 16.Fence length required = Perimeter of the garden = 2(Length+Breadth) = 2(6 m+ 9 m) = 2 × 15 m = 30 m Area of garden that dog have to run in = 6 m × 9 m = 54 m²
- (a)Perimeter of square = 4 × Side = 4 × 5m = 20 m (b)Perimeter of square = 4 × Side = 4 × 6 m = 24 m (c)Perimeter of square = 4 × Side = 4 × 7 m = 28 m
(d)Perimeter of square = 4 × Side = 4 × 12 m = 48 m 18.(a) Perimeter of square = 4 × Side 32 = 4 × Side Side = 32/ = 8 m (b) Perimeter of square = 4 × Side 40 = 4 × Side Side = 40/ = 10 m (c)Perimeter of square = 4 × side 44 = 4 × side Side = 44/ = 11 m (d)Perimeter of square = 4 × Side 20 = 4 × Side Side = 20/ = 5 m 19.Length of fencing required = Perimeter of the rectangular garden = 2( Length + Breadth) = 2(15 m+ 13 m) = 2 × 28 m = 56 m
