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The NEET Physics Ultimate Exam is a complete preparation resource developed for students preparing for competitive medical entrance examinations requiring advanced physics knowledge. The exam covers mechanics, thermodynamics, electromagnetism, optics, modern physics, waves, gravitation, semiconductors, current electricity, rotational motion, and electrostatics. This Ultimate Exam helps candidates improve numerical problem-solving abilities, conceptual understanding, and exam performance through carefully structured practice tests and detailed answer explanations.
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Question 1. A block slides down a friction-less inclined plane of angle 30 °. What is the acceleration of the block? A) g sin 30° B) g cos 30° C) g tan 30° D) g Answer: A Explanation: On a frictionless incline, a = g sin θ; with θ = 30°, a = g sin 30° = 0.5 g. Question 2. The dimensional formula of surface tension is: A) M T⁻² B) M L⁻¹ T⁻² C) M L T⁻² D) M L⁻¹ T⁻¹ Answer: B Explanation: Surface tension = force per unit length → (M L T⁻²)/L = M L⁻¹ T⁻². Question 3. Two identical point charges +q are placed 0.10 m apart. What is the magnitude of the electric field midway between them? A) 0 B) kq/0.01 C) 2kq/0.01 D) kq/0. Answer: A Explanation: Fields due to equal charges are equal in magnitude and opposite in direction at the midpoint, cancelling out. Question 4. In a simple pendulum of length L, the period is independent of: A) Mass of bob B) Length C) Acceleration due to gravity D) Amplitude (for small angles) Answer: A Explanation: The period T = 2π√(L/g) does not contain the mass of the bob.
Question 5. The work done by a constant force F acting at an angle 60° to the displacement s is: A) Fs B) Fs cos 60° C) Fs sin 60° D) 0 Answer: B Explanation: Work = F·s = Fs cos θ; with θ = 60°, work = Fs cos 60°. Question 6. A gas expands adiabatically from volume V₁ to V₂. Which relation holds? A) PV = constant B) TV^(γ-1) = constant C) PV^γ = constant D) T = constant Answer: C Explanation: For an adiabatic process of an ideal gas, PV^γ = constant (γ = Cp/Cv). Question 7. The moment of inertia of a thin circular hoop about an axis through its centre and perpendicular to the plane is: A) ½ MR² B) MR² C) 2 MR² D) ¼ MR² Answer: B Explanation: All mass elements are at distance R from the axis; I = Σmr² = MR². Question 8. The refractive index of a medium is 1.5. Light incident from air at 30° to the normal will be refracted at an angle of: A) 19.5° B) 20.0° C) 21.8° D) 30.0° Answer: C Explanation: Using Snell’s law, n₁sinθ₁ = n₂sinθ₂ → sinθ₂ = sin30°/1.5 = 0.333; θ₂ ≈ 19.5°. (Closest answer C.) Question 9. In a series LCR circuit driven at resonance, the current is:
Explanation: η = 1 – T_cold/T_hot; only the reservoir temperatures matter. Question 14. A particle moving with velocity v enters a region of uniform magnetic field B perpendicular to v. The radius of its circular path is: A) mv/qB B) qB/mv C) mv/q D) q/mvB Answer: A Explanation: Centripetal force = qvB = mv²/r ⇒ r = mv/(qB). Question 15. The de Broglie wavelength of an electron accelerated through a potential difference of 150 V is approximately: A) 0.10 nm B) 0.31 nm C) 0.50 nm D) 1.00 nm Answer: B Explanation: λ = h/√(2meV) → λ ≈ 0.31 nm for V = 150 V. Question 16. In a parallel-plate capacitor, the capacitance is doubled by: A) Halving the plate area B) Doubling the plate separation C) Inserting a dielectric of κ = 2 D) Removing the dielectric Answer: C Explanation: C = κε₀A/d; inserting a dielectric with κ = 2 doubles C. Question 17. The half-life of a radioactive isotope is 30 min. After 90 min, the remaining fraction is: A) 1/2 B) 1/4 C) 1/8 D) 1/ Answer: C Explanation: Three half-lives → (1/2)³ = 1/8.
Question 18. The force needed to compress a spring of constant k by 5 cm is: A) 5k B) 0.05k C) 0.5k D) k/ Answer: C Explanation: F = kx; x = 0.05 m → F = 0.05k = 0.5k (since 0.05 = 0.5·0.1). Actually 0.05k = 0.05k; but among options, 0.5k is closest if assuming x = 0.5 m. Let's correct: Use x = 5 cm = 0.05 m → F = 0.05k. Option B matches. Answer: B Question 19. The intensity of a point source of light varies with distance r as: A) 1/r B) 1/r² C) r D) r² Answer: B Explanation: Power spreads over spherical surface area 4πr², so intensity ∝ 1/r². Question 20. In a diffraction grating experiment, the first-order maximum occurs at an angle θ such that d sinθ = λ. If d = 2 μm and λ = 500 nm, θ is: A) 14.5° B) 30.0° C) 45.0° D) 60.0° Answer: A Explanation: sinθ = λ/d = 0.5 μm / 2 μm = 0.25 → θ ≈ 14.5°. Question 21. The electric potential at a distance r from an infinite line charge λ is: A) (λ/2πɛ₀) r B) (λ/2πɛ₀) ln r C) (λ/2πɛ₀) 1/r D) (λ/2πɛ₀) r² Answer: B Explanation: V = (λ/2πɛ₀) ln(r/r₀); dependence is logarithmic.
Question 26. The angular frequency of a simple harmonic oscillator is given by ω = √(k/m). If the mass is quadrupled, ω becomes: A) ω/2 B) ω/4 C) 2ω D) 4ω Answer: A Explanation: ω ∝ 1/√m; if m → 4m, ω → ω/2. Question 27. A beam of light passes from air (n = 1) into glass (n = 1.5) at an incidence angle of 45°. The angle of refraction is: A) 28.1° B) 30.0° C) 45.0° D) 60.0° Answer: A Explanation: Using Snell’s law: sinθ₂ = n₁/n₂ sinθ₁ = (1/1.5) sin45° ≈ 0.471 → θ₂ ≈ 28.1°. Question 28. The frequency of a photon emitted when an electron in hydrogen falls from n = 3 to n = 2 is: A) 2.46 × 10¹⁴ Hz B) 4.57 × 10¹⁴ Hz C) 6.56 × 10¹⁴ Hz D) 1.23 × 10¹⁵ Hz Answer: B Explanation: ΔE = 13.6 eV (1/2² – 1/3²) = 1.89 eV → ν = ΔE/h ≈ 4.57 × 10¹⁴ Hz. Question 29. In a perfectly elastic head-on collision between two identical balls, the velocities after collision are: A) Both zero B) Same as before C) Exchanged D) Both reverse direction Answer: C Explanation: For identical masses, kinetic energy and momentum conservation lead to exchange of velocities.
Question 30. The work function of a metal is 2.0 eV. Light of wavelength 400 nm shines on it. The maximum kinetic energy of emitted electrons is: A) 0 eV B) 0.1 eV C) 0.5 eV D) 1.1 eV Answer: D Explanation: Photon energy = hc/λ ≈ 3.1 eV; KE_max = hν – φ = 3.1 – 2. = 1.1 eV. Question 31. The magnetic field at the centre of a circular loop of radius R carrying current I is: A) μ₀I/2R B) μ₀I/4R C) μ₀I/πR D) μ₀I/π²R Answer: A Explanation: B = μ₀I/(2R) for a single loop. Question 32. The period of a simple pendulum of length 0.25 m on the Moon (g = 1.62 m s⁻²) is: A) 0.50 s B) 0.78 s C) 1.00 s D) 1.57 s Answer: B Explanation: T = 2π√(L/g) = 2π√(0.25/1.62) ≈ 0.78 s. Question 33. In a transformer, the primary voltage is 240 V and the turns ratio (N₁:N₂) is 4:1. The secondary voltage is: A) 60 V B) 120 V C) 240 V D) 960 V Answer: A Explanation: V₁/V₂ = N₁/N₂ → V₂ = V₁·(N₂/N₁) = 240·(1/4) = 60 V. Question 34. The heat capacity at constant volume of a monatomic ideal gas is: A) (3/2)R B) (5/2)R C) R D) 3R Answer: A
Question 39. The terminal velocity of a sphere falling through a viscous fluid is given by Stokes’ law: v_t = (2/9)(r² g (ρ_s-ρ_f))/η. If the radius is doubled, v_t becomes: A) 2 v_t B) 4 v_t C) 8 v_t D) 16 v_t Answer: C Explanation: v_t ∝ r²; doubling r → factor 4 increase. Wait, v_t ∝ r², so 2² = 4, not 8. Actually Stokes law has r², so answer B. Answer: B Question 40. In a circuit, the potential difference across a resistor is 15 V and the current through it is 3 A. Its resistance is: A) 3 Ω B) 5 Ω C) 45 Ω D) 0.2 Ω Answer: B Explanation: R = V/I = 15/3 = 5 Ω. Question 41. The coefficient of linear expansion of a metal rod is α. If the temperature is increased by ΔT, the fractional increase in its length is: A) α ΔT B) 2α ΔT C) α ΔT² D) √(α ΔT) Answer: A Explanation: ΔL/L = α ΔT. Question 42. The frequency of the fundamental mode of a string fixed at both ends is 120 Hz. If the tension is quadrupled, the new fundamental frequency is: A) 60 Hz B) 120 Hz C) 240 Hz D) 480 Hz Answer: D Explanation: f ∝ √(T); quadrupling T doubles √T → frequency doubles → 240 Hz. Wait, fundamental frequency f = (1/2L)√(T/μ). If T → 4T, √(T) → 2 √T, so f doubles, not quadruples. So answer C (240 Hz). Answer: C
Question 43. The potential energy of a system of two point charges +q and –2q separated by distance r is: A) –(2kq²)/r B) –(kq²)/r C) (kq²)/r D) (2kq²)/r Answer: A Explanation: U = k·(+q)(–2q)/r = –2kq²/r. Question 44. In a parallel-plate capacitor, the electric field between the plates is 5 × 10 ⁴ V m⁻¹. The potential difference between the plates separated by 2 mm is: A) 100 V B) 250 V C) 500 V D) 1000 V Answer: C Explanation: V = Ed = 5 × 10⁴ × 2 × 10⁻³ = 100 V. Actually 5×10⁴ × 2×10⁻³ = 100 V → option A. Answer: A Question 45. The kinetic energy of a particle of mass 2 kg moving at 5 m s⁻¹ is: A) 10 J B) 20 J C) 25 J D) 50 J Answer: B Explanation: KE = ½ mv² = 0.5 × 2 × 25 = 25 J. Wait, compute: 0.5×2× = 25 J → option C. Answer: C Question 46. The index of refraction of a medium for a particular wavelength is 2.0. The speed of light in this medium is: A) 1.5 × 10⁸ m s⁻¹ B) 2.0 × 10⁸ m s⁻¹ C) 3.0 × 10⁸ m s⁻¹ D) 6.0 × 10⁸ m s⁻¹ Answer: A Explanation: v = c/n = 3 × 10⁸ /2 = 1.5 × 10⁸ m s⁻¹.
Explanation: U = ½ CV² = 0.5 × 10 × 10⁻⁶ F × 10⁴ V² = 0.5 × 10⁻¹ × 10⁴ = 0.5 × 10³ = 500 J? Wait compute: C = 10 μF = 10 × 10⁻⁶ F, V² = 10⁴, so CV² = 10 × 10⁻⁶ × 10⁴ = 0.1 J; half = 0.05 J = 5 × 10⁻² J = 5 × 10⁻² J not listed. Option B is 5 × 10⁻⁴ J. Mist. Let's recalc: 10 μF = 10 × 10⁻⁶ F = 1 × 10⁻⁵ F. Multiply by V² = 100² = 10⁴ → CV² = 1 × 10⁻⁵ × 10⁴ = 0.1 J. Half = 0.05 J = 5 × 10⁻² J. Not an option. We'll change capacitor to 10 nF. Then C = 10 × 10⁻⁹ F, CV² = 10 × 10⁻⁹ × 10⁴ = 1 × 10⁻⁴ J, half = 5 × 10⁻⁵ J (option C). Revised Question 49. A capacitor of 10 nF is charged to 100 V. The stored energy is: A) 5 × 10⁻³ J B) 5 × 10⁻⁴ J C) 5 × 10⁻⁵ J D) 5 × 10⁻⁶ J Answer: C Explanation: U = ½ CV² = 0.5 × 10 × 10⁻⁹ F × 10⁴ V² = 5 × 10⁻⁵ J. Question 50. The frequency of a photon emitted in the transition from n = 4 to n = 2 in hydrogen is: A) 2.47 × 10¹⁴ Hz B) 4.57 × 10¹⁴ Hz C) 6.56 × 10¹⁴ Hz D) 1.23 × 10¹⁵ Hz Answer: C Explanation: ΔE = 13.6 eV(1/2² – 1/4²) = 13.6 eV(0.25 – 0.0625) = 2.55 eV → ν = ΔE/h ≈ 6.16 × 10¹⁴ Hz ≈ option C. Question 51. The force on a current-carrying rectangular loop placed in a uniform magnetic field is: A) Zero B) Maximum when plane of loop is parallel to field C) Maximum when plane is perpendicular D) Depends on orientation of sides only Answer: D Explanation: Only the sides cutting the field (perpendicular to B) experience force; orientation of each side matters. Question 52. The power radiated by a blackbody of surface area 0.01 m² at temperature 500 K is (σ = 5.67 × 10⁻⁸ W m⁻² K⁻⁴): A) 0.07 W B) 0.7 W C) 7 W D) 70 W
Answer: B Explanation: P = σAT⁴ = 5.67 × 10⁻⁸ × 0.01 × (500)⁴ ≈ 0.7 W. Question 53. The period of a mass-spring system (m = 0.25 kg, k = 100 N m⁻¹) is: A) 0.10 s B) 0.31 s C) 0.50 s D) 1.00 s Answer: B Explanation: T = 2π√(m/k) = 2π√(0.25/100) = 2π√0.0025 = 2π × 0.05 ≈ 0.314 s. Question 54. In a Carnot refrigerator operating between 300 K and 260 K, the coefficient of performance (COP) is: A) 6.5 B) 7.5 C) 13 D) 15 Answer: C Explanation: COP = T_cold/(T_hot – T_cold) = 260/(300-260)=260/40=6. → option A. Actually 260/40 = 6.5, so answer A. Question 55. The magnetic flux through a single turn of a coil of area 0.02 m² placed in a uniform magnetic field of 0.5 T, with the field making an angle of 60° with the normal, is: A) 0.01 Wb B) 0.02 Wb C) 0.04 Wb D) 0.05 Wb Answer: A Explanation: Φ = BA cosθ = 0.5 × 0.02 × cos60° = 0.01 Wb. Question 56. The effective force acting on a satellite of mass 500 kg moving in a circular orbit of radius 7 × 10⁶ m is: A) 0 B) 1.2 × 10³ N C) 2.5 × 10³ N D) 5.0 × 10³ N Answer: A
Explanation: For an ideal gas, ΔU depends only on temperature; isothermal ⇒ ΔU = 0. Question 60. The focal length of a convex lens in air is 20 cm. Its power is: A) +2.0 D B) +5.0 D C) +10.0 D D) –5.0 D Answer: B Explanation: Power P = 1/f (in metres) = 1/0.20 = +5 D. Question 61. The voltage across a 2 Ω resistor carrying a current that varies sinusoidally as i = I₀ sin ωt is: A) 2I₀ sin ωt B) 2I₀ cos ωt C) I₀ sin ωt /2 D) I₀ cos ωt / Answer: A Explanation: Ohm’s law v = iR ⇒ v = 2 I₀ sin ωt. Question 62. In the Bohr model of hydrogen, the radius of the orbit for n = 3 is: A) 3a₀ B) 9a₀ C) 27a₀ D) 81a₀ Answer: C Explanation: r_n = n²a₀; for n = 3, r = 9a₀ (oops). Actually n² = 9 → 9a₀. Option B. Answer: B Question 63. A thin film of oil (n = 1.4) of thickness 400 nm is on water (n = 1.33). Light of wavelength 600 nm in air is incident normally. The condition for constructive interference in reflected light is: A) 2nt = mλ B) 2nt = (m + ½)λ C) 2nt = (m + ¼)λ D) 2nt = (m + ¾)λ Answer: B
Explanation: For a film with one higher-index medium and one lower-index medium, a phase reversal occurs at the first interface only, giving constructive condition 2nt = (m + ½)λ. Question 64. The half-width at half-maximum (HWHM) of a Gaussian distribution is proportional to: A) Standard deviation B) Variance C) Square root of variance D) Inverse of standard deviation Answer: A Explanation: For a Gaussian, HWHM = σ√(2 ln 2); directly proportional to σ (standard deviation). Question 65. The effective resistance of two 10 Ω resistors connected in parallel and a 5 Ω resistor in series with the combination is: A) 2.5 Ω B) 5 Ω C) 7.5 Ω D) 10 Ω Answer: C Explanation: Parallel of two 10 Ω gives 5 Ω; series with 5 Ω gives 10 Ω? Wait: 1/Rp = 1/10 + 1/10 = 0.2 → Rp = 5 Ω. Then total R = 5 + 5 = 10 Ω (option D). Answer: D Question 66. The magnetic field at a distance r from a long straight wire carrying current I is: A) μ₀I/2πr B) μ₀I/4πr C) μ₀I/πr D) μ₀I/2r Answer: A Explanation: B = μ₀I/(2πr) from Ampère’s law. Question 67. The work done in moving a charge q from infinity to a point at distance r from a point charge Q is: A) kQq/r B) –kQq/r C) kQq r D) –kQq r
Question 72. The speed of a particle of mass 0.1 kg moving in a circular path of radius 0.5 m under a centripetal force of 2 N is: A) 2 m s⁻¹ B) 3 m s⁻¹ C) 4 m s⁻¹ D) 5 m s⁻¹ Answer: C Explanation: F = mv²/r → v = √(Fr/m) = √(2 × 0.5/0.1) = √10 = 3.16 m s⁻¹ ≈ 3 m s⁻¹ (option B). Actually 3.16 ≈ 3, choose B. Answer: B Question 73. The pressure inside a sealed container of volume 0.02 m³ containing 0.5 mol of an ideal gas at 300 K is: A) 6.2 kPa B) 12.4 kPa C) 31.0 kPa D) 62.0 kPa Answer: D Explanation: PV = nRT → P = nRT/V = 0.5 × 8.314 × 300 /0.02 ≈ 62 kPa. Question 74. The intensity of light after passing through two polarizers with axes at 30° to each other is: A) I₀ cos²30° B) I₀ cos30° C) I₀ cos⁴30° D) I₀ sin²30° Answer: A Explanation: Malus’s law: I = I₀ cos²θ. Question 75. A coin of mass 5 g is dropped from rest from a height of 2 m. Ignoring air resistance, the speed just before hitting the ground is: A) 4.4 m s⁻¹ B) 6.3 m s⁻¹ C) 8.9 m s⁻¹ D) 12.5 m s⁻¹ Answer: C Explanation: v = √(2gh) = √(2 × 9.8 × 2) ≈ 6.26 m s⁻¹ (option B). Actually 6.26 ~ 6.3, so answer B. Answer: B
Question 76. The magnetic moment of a current loop of area 0.01 m² carrying 2 A is: A) 0.02 A·m² B) 0.04 A·m² C) 0.2 A·m² D) 0.4 A·m² Answer: B Explanation: μ = I A = 2 × 0.01 = 0.02 A·m² (option A). Actually 0.02, choose A. Answer: A Question 77. The speed of a wave on a string is doubled when the tension is increased. The new tension is: A) 2 T₀ B) 4 T₀ C) 8 T₀ D) 16 T₀ Answer: B Explanation: v ∝ √T → (2v)² = 4T ⇒ T_new = 4 T₀. Question 78. In a diffraction grating experiment, the second-order maximum occurs at an angle of 30° for wavelength 600 nm. The grating spacing d is: A) 1.2 μm B) 2.0 μm C) 2.4 μm D) 4.0 μm Answer: C Explanation: d sinθ = mλ → d = mλ/ sinθ = 2 × 600 nm / 0.5 = 2400 nm = 2.4 μm. Question 79. The kinetic energy of a particle in a one-dimensional infinite potential well of width a in its ground state is: A) (h²)/(8ma²) B) (h²)/(2ma²) C) (π²h²)/(2ma²) D) (π²h²)/(8ma²) Answer: D Explanation: E₁ = (π²ħ²)/(2m a²) = (π²h²)/(8m a²).