Thevenin's and Norton's Theorems: Simplifying Complex Circuits, Lecture notes of Physics Fundamentals

Thevenin's and norton's theorems, which are used to simplify complex electrical circuits. The theorems allow reducing a network to an equivalent circuit containing a single voltage or current source and resistances. Examples and instructions on how to find thevenin's equivalent circuit and norton's equivalent source.

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LECTURE #
Theveninโ€™s Theorem is a network analysis
procedure meant to simplify the computations of a
complex network (with several sources and
resistances).
It does so by reducing a complex network to simple
equivalent circuit (Theveninโ€™s Equivalent
Circuit) containing a Single Voltage Source in
series with a two Resistances.
Whereby:
The voltage source is the open circuit voltage
measured between terminals where its required
to determine the current
One of the resistors is the Theveninโ€™s
equivalent resistance, measured between
terminals (where its required to compute
current) in a passive circuit
While the other resistance represents the load
resistance (connected between terminals where
its required to find current).
Theveninโ€™
s Theorem
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LECTURE #

Theveninโ€™s Theorem is a network analysis

procedure meant to simplify the computations of a

complex network (with several sources and

resistances).

It does so by reducing a complex network to simple

equivalent circuit (Theveninโ€™s Equivalent

Circuit) containing a Single Voltage Source in

series with a two Resistances.

Whereby:

The voltage source is the open circuit voltage

measured between terminals where its required

to determine the current

One of the resistors is the Theveninโ€™s

equivalent resistance, measured between

terminals (where its required to compute

current) in a passive circuit

While the other resistance represents the load

resistance (connected between terminals where

its required to find current).

Theveninโ€™

s Theorem

Active Network

with linear

Sources and

Resistances

resistance R th

Equivalent Source, then its possible to determine the Load current, i.e.

current between terminals A & B

๐ธ ๐‘กhh โˆ’๐‘‡h๐‘’๐‘ฃ๐‘’๐‘›๐‘– ๐‘›

โ€ฒ ๐‘  ๐‘‰๐‘œ๐‘™๐‘กh๐‘Ž๐‘”๐‘’

๐‘‡h๐‘’๐‘ฃ๐‘’๐‘›๐‘– ๐‘›

โ€ฒ ๐‘  ๐ธ๐‘ž๐‘ข๐‘–๐‘ฃ๐‘Ž๐‘™๐‘’๐‘›๐‘กh ๐‘†๐‘œ๐‘ข๐‘Ÿ๐‘๐‘’

Example # [Prove that I

1

=10A]

E

R 1 R 2

I 1 ?

E

R 1 R 2

A

B

R R 1 2

I L ? I L ?

๐‘ฌ = ๐Ÿ๐Ÿ’ ๐‘ฝ ฮฉ^ ๐‘น^ ๐Ÿ = ๐Ÿ“ ฮฉ^ ๐’“^ = ๐Ÿ ฮฉ

E

A

B

E R 2

A

B

I 2 I ๐‘ฐ= ๐‘ฐ ๐Ÿ

๐’“ (^) R 2

A

B

๐‘น ๐’•๐’‰=

๐’“๐‘น ๐Ÿ

๐’“ + ๐‘น ๐Ÿ

๐‘ฌ ๐’•๐’‰= ๐Ÿ๐ŸŽ ๐‘ฝ

๐‘น ๐’•๐’‰= ๐ŸŽ. ๐Ÿ–๐Ÿ‘๐Ÿ‘ ฮฉ

A

B

๐‘ฐ ๐‘ณ=

๐‘ฌ ๐’•๐’‰

๐‘น ๐’•๐’‰+ ๐‘น๐‘ณ

=๐‘ฐ ๐Ÿ

๐‘ฐ ๐‘ณ=

๐Ÿ๐ŸŽ

๐ŸŽ. ๐Ÿ–๐Ÿ‘๐Ÿ‘ + ๐Ÿ. ๐Ÿ๐Ÿ”๐Ÿ•

= ๐Ÿ๐ŸŽ ๐‘จ

Example #

๐ท๐‘’๐‘กh๐‘’๐‘Ÿ๐‘š๐‘–๐‘›๐‘’ ๐‘๐‘ข๐‘Ÿ๐‘Ÿ๐‘’๐‘›๐‘กh ๐‘กhh๐‘Ÿ๐‘œ๐‘ข๐‘”h ๐‘Ÿ๐‘’๐‘ ๐‘–๐‘ ๐‘กh๐‘Ž๐‘›๐‘๐‘’ ๐‘… 2 ๐‘ข๐‘ ๐‘–๐‘›๐‘” ๐‘‡h๐‘’๐‘ฃ๐‘’๐‘›๐‘–๐‘›

โ€ฒ ๐‘  ๐‘‡h๐‘’๐‘œ๐‘Ÿ๐‘’๐‘š

๐ท๐‘’๐‘กh๐‘’๐‘Ÿ๐‘š๐‘–๐‘›๐‘’ ๐‘๐‘ข๐‘Ÿ๐‘Ÿ๐‘’๐‘›๐‘กh ๐‘กhh๐‘Ÿ๐‘œ๐‘ข๐‘”h ๐‘Ÿ๐‘’๐‘ ๐‘–๐‘ ๐‘กh๐‘Ž๐‘›๐‘๐‘’ ๐‘… 2 ๐‘ข๐‘ ๐‘–๐‘›๐‘” ๐‘‡h๐‘’๐‘ฃ๐‘’๐‘›๐‘–๐‘›

โ€ฒ ๐‘  ๐‘‡h๐‘’๐‘œ๐‘Ÿ๐‘’๐‘š

Example

V 3

=?

R 1

I A

E 1

R 3

R 2

R 4

This implies that any active network of linear sources and resistances can

be represented by a constant current source in parallel with a resistance.

Active Network

with linear

Sources and

Resistances

A current flowing in any portion (between any two terminals) of an active

network of linear sources and resistances can be determined through CDR

as the current from a constant current source in parallel with a resistance.

๐‘ฐ ๐‘บ๐‘ช

- referred to as Nortonโ€™s equivalent resistance is the resistance measured between the

terminals A & B while all voltage sources are replaced by internal resistances or short

circuits and current sources by open circuit.

The constant current source is the short circuit current measured between the terminals

Nortonโ€™s Equivalent Source

๐‘ฐ ๐‘จ๐‘ฉ= ๐‘ฐ ๐‘ณ=

๐‘ฐ ๐’”๐’„ โˆ— ๐‘น๐‘ต

๐‘น ๐‘ต + ๐‘น ๐‘ณ

Example # 2

๐ท๐‘’๐‘กh๐‘’๐‘Ÿ๐‘š๐‘–๐‘›๐‘’ ๐‘๐‘ข๐‘Ÿ๐‘Ÿ๐‘’๐‘›๐‘กh ๐‘กhh๐‘Ÿ๐‘œ๐‘ข๐‘”h ๐‘Ÿ๐‘’๐‘ ๐‘–๐‘ ๐‘กh๐‘Ž๐‘›๐‘๐‘’ ๐‘… 2 ๐‘ข๐‘ ๐‘–๐‘›๐‘” ๐‘๐‘œ๐‘Ÿ๐‘กh๐‘œ ๐‘›

โ€ฒ ๐‘  ๐‘‡h๐‘’๐‘œ๐‘Ÿ๐‘’๐‘š

๐ท๐‘’๐‘กh๐‘’๐‘Ÿ๐‘š๐‘–๐‘›๐‘’ ๐‘๐‘ข๐‘Ÿ๐‘Ÿ๐‘’๐‘›๐‘กh ๐‘กhh๐‘Ÿ๐‘œ๐‘ข๐‘”h ๐‘Ÿ๐‘’๐‘ ๐‘–๐‘ ๐‘กh๐‘Ž๐‘›๐‘๐‘’ ๐‘… 2 ๐‘ข๐‘ ๐‘–๐‘›๐‘” ๐‘๐‘œ๐‘Ÿ๐‘กh๐‘œ ๐‘›

โ€ฒ ๐‘  ๐‘‡h๐‘’๐‘œ๐‘Ÿ๐‘’๐‘š

Example

R 1 R 4

R 3

R 2

E 1

V 4

=?

Example

V 4

=?

R 1

I A

E 1

R 3

R 2

R 4

๐‘ฐ ๐‘จ= ๐Ÿ– ๐‘จ ๐’“^ = ๐Ÿ ฮฉ