Physics 2211 Solution: Calculating Time and Distance for a Trip with Variable Speeds, Exercises of Physics

The solution to a problem in a physics 2211 recitation, where a student calculates the time and distance for a trip back to tech after break, given that they can drive at different speeds in each half of the trip due to traffic conditions. The given information and the calculations to find the time and distance.

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PHYS 2211 Solution
Recitation 01 Week of January 14
Example
You have a 400 km trip back to Tech after break. You are able to drive at 100 km/hr for
the first half of the time. Traffic gets worse as you approach Atlanta, so you are only able
to drive at 60 km/hr for the second half of the time.
How much time did your trip take?
Let the first half of your trip, at speed v1, cover a distance d1and require time t1. Similarly,
let the second half of your trip, at speed v2, cover a distance d2and require time t2. Let
the total distance be Dand the total time be T.
D=d1+d2=v1t1+v2t2
Since t1and t2are each half the time, t1=t2.
D=v1t2+v2t2= (v1+v2)t2t2=D
v1+v2
=400 km
100 km/hr + 60 km/hr = 2.5 hr
But t2is half the time, so the total time is 5 hr.
pf2

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PHYS 2211 Solution Recitation 01 Week of January 14

Example

You have a 400 km trip back to Tech after break. You are able to drive at 100 km/hr for the first half of the time. Traffic gets worse as you approach Atlanta, so you are only able to drive at 60 km/hr for the second half of the time.

How much time did your trip take?

Let the first half of your trip, at speed v 1 , cover a distance d 1 and require time t 1. Similarly, let the second half of your trip, at speed v 2 , cover a distance d 2 and require time t 2. Let the total distance be D and the total time be T.

D = d 1 + d 2 = v 1 t 1 + v 2 t 2

Since t 1 and t 2 are each half the time, t 1 = t 2.

D = v 1 t 2 + v 2 t 2 = (v 1 + v 2 ) t 2 ⇒ t 2 =

D

v 1 + v 2

400 km 100 km/hr + 60 km/hr

= 2.5 hr

But t 2 is half the time, so the total time is 5 hr.

PHYS 2211 Solution Recitation 01 Week of January 14

Problem

You have a 4 hr trip back to Tech after break. You are able to drive at 100 km/hr for the first half of the distance. Traffic gets worse as you approach Atlanta, so you are only able to drive at 60 km/hr for the second half of the distance.

How much distance did your trip cover?

Let the first half of your trip, at speed v 1 , cover a distance d 1 and require time t 1. Similarly, let the second half of your trip, at speed v 2 , cover a distance d 2 and require time t 2. Let the total distance be D and the total time be T.

T = t 1 + t 2 =

d 1 v 1

d 2 v 2

Since d 1 and d 2 are each half the distance, d 1 = d 2.

T =

d 2 v 1

d 2 v 2

v 1

v 2

d 2 ⇒ d 2 =

T

1 v 1 +^

1 v 2

4 hr 1 100 km/hr +^

1 60 km/hr

= 150 km

But d 2 is half the distance, so the total distance is 300 km.