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The solution to a problem in a physics 2211 recitation, where a student calculates the time and distance for a trip back to tech after break, given that they can drive at different speeds in each half of the trip due to traffic conditions. The given information and the calculations to find the time and distance.
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PHYS 2211 Solution Recitation 01 Week of January 14
Example
You have a 400 km trip back to Tech after break. You are able to drive at 100 km/hr for the first half of the time. Traffic gets worse as you approach Atlanta, so you are only able to drive at 60 km/hr for the second half of the time.
How much time did your trip take?
Let the first half of your trip, at speed v 1 , cover a distance d 1 and require time t 1. Similarly, let the second half of your trip, at speed v 2 , cover a distance d 2 and require time t 2. Let the total distance be D and the total time be T.
D = d 1 + d 2 = v 1 t 1 + v 2 t 2
Since t 1 and t 2 are each half the time, t 1 = t 2.
D = v 1 t 2 + v 2 t 2 = (v 1 + v 2 ) t 2 ⇒ t 2 =
v 1 + v 2
400 km 100 km/hr + 60 km/hr
= 2.5 hr
But t 2 is half the time, so the total time is 5 hr.
PHYS 2211 Solution Recitation 01 Week of January 14
Problem
You have a 4 hr trip back to Tech after break. You are able to drive at 100 km/hr for the first half of the distance. Traffic gets worse as you approach Atlanta, so you are only able to drive at 60 km/hr for the second half of the distance.
How much distance did your trip cover?
Let the first half of your trip, at speed v 1 , cover a distance d 1 and require time t 1. Similarly, let the second half of your trip, at speed v 2 , cover a distance d 2 and require time t 2. Let the total distance be D and the total time be T.
T = t 1 + t 2 =
d 1 v 1
d 2 v 2
Since d 1 and d 2 are each half the distance, d 1 = d 2.
d 2 v 1
d 2 v 2
v 1
v 2
d 2 ⇒ d 2 =
1 v 1 +^
1 v 2
4 hr 1 100 km/hr +^
1 60 km/hr
= 150 km
But d 2 is half the distance, so the total distance is 300 km.