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The normal distribution and sampling distribution concepts through a lab exercise. It covers topics such as finding probabilities related to the maximum number of push-ups a subject can do, understanding the sampling distribution of sample means, and calculating the probability of a sample mean being greater than a certain value. Step-by-step explanations, formulas, and calculations to help the reader understand these statistical concepts. It is likely intended for use in an introductory statistics or data analysis course at the university level, as it requires familiarity with normal distribution, z-tables, and sampling distribution theory. The document could be useful for students as study notes, lecture notes, or practice problems to prepare for exams in related subjects.
Typology: Lab Reports
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Name: Deep Harshad Prajapati Friday T.A. name/Class time: Yujie Chen, 1:30 – 2:20 PM Lab 5: Normal Distribution and Sampling Distribution SPSS will not be used for this lab. You will need the Normal Table throughout the lab. You may find this table on Brightspace Course Content TABLES z table. Note: These tables in Brightspace are the same tables used in Perdisco and on the exam. Also, 30% points will be deducted for late submission, up to 24 hours.
Z = -0.5 μ= d) (2 points) What is the probability that the maximum number of push-ups a random subject can do in one session is more than 14? Show your work. The correct probability statement is required to get full credit. Round your final answer to 4 decimal places. μ=11 σ= 6 P (X > 14) Z = (14-11)/6 = 0.5 = 0.6915 in z-table P (X > 14) = 1 - 0. = 0. a) e) (3 points) The top 15% of subjects are able to do more than ____ pushups? Show your work. You must start off by writing down the probability statement corresponding to this question, in terms of the variable X. Write your final answer to 2 decimal places. P (X > a) = 0. = 1 – 0. = 0.85 = 1.04 in z-table a – 11/6 = 1. a = (1.04 * 6) + 11 a = 17. f) (2 points) Based on problem (e) above, label the axis in terms of PU , including the values for the cut-off score for the highest 15% and the population mean. Shade the area representing the probability in question and indicate its value. μ=11 X = 17.24, Shaded area =