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The properties of normal distributions, including their bell-shaped, symmetrical, and unimodal nature. It discusses central tendency measures like mean, median, and mode, and introduces the concept of standard normal distributions and z-scores. The document also covers the calculation of z-scores and their interpretation in terms of relative position and standard deviations.
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Notes 2: Normal Distribution and Standard Scores
z = SD
s
leftmost column has the z value with an accuracy of tenths and the topmost column adds
- Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0. accuracy to the hundredths. and the proportion of scores below z = 0.67 is .2486 + .50 = .7486 or 74.86%.
Exercise 1 Determine the proportion of scores that:
(1) fall between the mean (z = 0.00) and 1.33; between 0.00 and -.93? (2) are less than or equal to 1.5; less than or equal to -.75? (3) are greater than or equal to 1.4; greater than or equal to -.83? (4) are between -1.0 and 1.5; between 1.0 and 1.3; between -1.3 and -1.1? (5) are greater than 1.96 and less than -1.96; (6) < -2.576 and > 2.576?
For raw scores that are normally distributed, one may convert raw scores into z scores and then find the proportion of scores above or below certain raw scores.
Exercise 2 Assuming that SAT scores are normally distributed with a M = 500 and SD = 100, provide answers to the following:
(1) find the proportion of scores between 627 and the mean; (2) find the proportion of scores between 427 and the mean; (3) find the proportion of scores below 627; (4) find the proportion of scores below 427; (5) find the proportion of scores above 427; (6) find the proportion of scores above 527; (7) find the proportion of scores above 500; (8) find the proportion of scores between 720 and 755; (9) find the proportion of scores between 420 and 380; (10) find the proportion of scores between 540 and 380.
If a set of scores is normally distributed, you may find the percentile rank using a z table after converting the X to z. The formula for PR is:
PR = (proportion below z)
Exercise 3 Determine the appropriate PRs.
(1) What is the PR for z = -0.33?
(2) What is the PR for z = 1.20? (3) What is the PR for z = 0.00? (4) What is the PR for z = -2.00?
For example, the difference in IQ units for PRs of 50 to 55 is 100 to 102āonly two IQ points. However, as one moves further from the IQ mean, the difference of 5 percentile rank points represents a greater difference in IQ points. For instance, a change in PR from 90 to 95 corresponds to a change of IQ points from 119 to 125āa 6 point difference.
Because difference in PR do not represent uniform differences in raw scores, one should not use descriptive and inference statistics on PR that require equal intervals, such as M, s, s^2 , etc..