Analytic Functions and Complex Geometry: Homework #3 for Math 534, Assignments of Mathematics

Homework problems for math 534, a course on analytic functions and complex geometry. The problems cover topics such as one-to-one analytic maps, metrics on the complex plane, doubly periodic functions, and singular points of power series.

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Pre 2010

Uploaded on 03/10/2009

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Math 534 Homework #3
Autumn 2008
Let D={z:|z|<1}.
1. Prove that if fis a two-to-two (one-to-one) analytic map of an open set onto f(Ω) and if
znΩ, then f(zn)∂f (Ω), in the sense that f(zn) eventually lies outside each compact
subset of f(Ω). Another way to state the problem is to view the sets as lying on the Riemann
sphere, so that the boundary can include the North Pole (the point at ”).
2. Prove that ϕis a one-to-one analytic map of Donto Dif and only if
ϕ(z) = cza
1¯az ,
for some constants cand a, with |c|= 1, and |a|<1. What is the inverse map?
3. For z, w D, define
ρ(z, w) =
zw
1¯zw
.
a. Suppose fis analytic on Dand maps Dinto D. Show that ρ(f(z), f (w)) = ρ(z, w) if and only
if fis a one-to-one analytic map of Donto D.
b. Show that ρis a metric on D.
c. Prove the “world’s greatest equality”: for z, w D,
1ρ(z, w)2=(1 |z|2)(1 |w|2)
|1¯zw|2,
d. Prove that ρ(|z|,|w|)ρ(z, w)ρ(|z|,−|w|).
4. Suppose fis bounded and analytic in the right half-plane {z: Rez > 0}, and lim supziy |f(z)|
Mfor all iy on the imaginary axis. Prove |f(z)| Mon the right half-plane. Check that f(z) = ez
satisfies all the hypotheses above, except for boundedness, and fails to be bounded in the right
half-plane. Hint: consider f(z)/(1 + εz) for ε > 0 small.
5. A function f(z) on the complex plane is called “doubly periodic” if there are two complex
numbers w1and w2which do not lie on the same line through the origin such that f(z+w1) =
f(z+w2) = f(z) for all complex numbers z. The numbers w1and w2are called “periods” of f.
Prove that the only entire doubly periodic functions are constant.
pf2

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Math 534 Homework # Autumn 2008

Let D = {z : |z| < 1 }.

  1. Prove that if f is a two-to-two (one-to-one) analytic map of an open set Ω onto f (Ω) and if zn ∈ Ω → ∂Ω, then f (zn) → ∂f (Ω), in the sense that f (zn) eventually lies outside each compact subset of f (Ω). Another way to state the problem is to view the sets as lying on the Riemann sphere, so that the boundary can include the North Pole (the point at “∞”).
  2. Prove that ϕ is a one-to-one analytic map of D onto D if and only if

ϕ(z) = c

( (^) z − a 1 − az¯

for some constants c and a, with |c| = 1, and |a| < 1. What is the inverse map?

  1. For z, w ∈ D, define ρ(z, w) =

∣∣^ z^ −^ w 1 − ¯zw

a. Suppose f is analytic on D and maps D into D. Show that ρ(f (z), f (w)) = ρ(z, w) if and only if f is a one-to-one analytic map of D onto D. b. Show that ρ is a metric on D. c. Prove the “world’s greatest equality”: for z, w ∈ D,

1 − ρ(z, w)^2 = (1^ − |z|

(^2) )(1 − |w| (^2) ) | 1 − zw¯ |^2 , d. Prove that ρ(|z|, |w|) ≤ ρ(z, w) ≤ ρ(|z|, −|w|).

  1. Suppose f is bounded and analytic in the right half-plane {z : Rez > 0 }, and lim supz→iy |f (z)| ≤ M for all iy on the imaginary axis. Prove |f (z)| ≤ M on the right half-plane. Check that f (z) = ez satisfies all the hypotheses above, except for boundedness, and fails to be bounded in the right half-plane. Hint: consider f (z)/(1 + εz) for ε > 0 small.
  2. A function f (z) on the complex plane is called “doubly periodic” if there are two complex numbers w 1 and w 2 which do not lie on the same line through the origin such that f (z + w 1 ) = f (z + w 2 ) = f (z) for all complex numbers z. The numbers w 1 and w 2 are called “periods” of f. Prove that the only entire doubly periodic functions are constant.
  1. Suppose f is analytic on D and |f (z)| ≤ 1 on D. Suppose also that f fixes two points in D, i.e. there are points z 1 , z 2 ∈ D such that f (z 1 ) = z 1 and f (z 2 ) = z 2. Prove that f (z) = z for all z ∈ D.
  2. Show that there is a constant C < ∞ so that if f is analytic on D, then

|f ′(z)| ≤ C

D |f (x + iy)|dxdy

for all |z| ≤ 1 /2.

  1. Let f (z) = ∑∞ n=0 anzn^ have radius of convergence 1 and suppose an ≥ 0 for all n. Prove that z = 1 is a singular point of f. That is, there is no function g analytic in a neighborhood U of z = 1 such that f = g on U ∩ D.
  2. Let S = {x + iy : |x| < 1 , |y| < 1 }. Suppose f is analytic on S and continuous on the closure of S. Let the four sides of the square be denoted by S 1 , S 2 , S 3 , S 4. Suppose also that |f | ≤ Mi on Si, for i = 1, 2 , 3 , 4. Prove |f (0)|^4 ≤ M 1 M 2 M 3 M 4.