STAT/MATH 309 Discussion 5: Cumulative Distribution Functions and Change of Variable, Study notes of Mathematical Statistics

Information on the cumulative distribution function (cdf) for both discrete and continuous random variables. It explains the properties of cdf, including the limits as x approaches negative and positive infinity. The document also covers the one-dimensional change of variable formula for transforming random variables. Three examples are given to illustrate the concepts, including calculating probabilities for normal distributions and transforming a normal distribution. Students taking a statistics course, particularly one focused on probability distributions, may find this document useful.

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Pre 2010

Uploaded on 09/02/2009

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STAT/MATH 309 DISCUSSION 5
TA: Jingjiang(Jack) Peng
Office: 1275 MSC, 1300 Universtiy Avenue
Phone: 262-1577
Office Hour: 11:30-1:30 p.m. Tuesday or by appoitment
Websit: www.stat.wisc.edu/peng
1 Cumulative Distribution Function
c.d.f FX(x) = P(Xx)
(i)0 FX(x)1;(ii) FX() = 1, and FX(−∞) = 0; (iii) FX(x) is non-decreasing
For discrete random variables, FX(x) = P(Xx) = PxixP(X=xi)
For continuous random variable, FX(x) = Rx
−∞ fX(t)dt, Where fXis called probability
density function
2 One-dimensional Change of Variable
If X is discrete random variable, Y=h(X), then pY(y) = P(Y=y) = P(h(X) =
x) = P(X=h1(x)) = Pxh1(y)P(X=x)
If X is continous, Y=h(X), then fY(y) = fX(h1(y)
|h(h1(y))|
3 Examples
1: (2.5.4) Let XN(0,1), calculate P(X 5), P (2X7), P (X3)
2: (2.5.5) YN(8,4), calculate P(Y 5), P (2Y7), P (X3)
3: (2.6.3) XN(µ, σ2), Y =cX +d, where c > 0. Prove YN( +d, c2σ2)
4: (2.6.5) Xexp(λ), Y=X3, Compute the density fYof Y.
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STAT/MATH 309 DISCUSSION 5

TA: Jingjiang(Jack) Peng Office: 1275 MSC, 1300 Universtiy Avenue E-mail: [email protected] Phone: 262- Office Hour: 11:30-1:30 p.m. Tuesday or by appoitment Websit: www.stat.wisc.edu/∼ peng

1 Cumulative Distribution Function

  • c.d.f FX (x) = P (X ≤ x)
  • (i)0 ≤ FX (x) ≤ 1;(ii) FX (∞) = 1, and FX (−∞) = 0; (iii) FX (x) is non-decreasing
  • For discrete random variables, FX (x) = P (X ≤ x) =

xi≤x P^ (X^ =^ xi)

  • For continuous random variable, FX (x) =

∫ (^) x −∞ fX^ (t)dt, Where^ fX^ is called probability density function

2 One-dimensional Change of Variable

  • If X is discrete random variable, Y = h(X), then pY (y) = P (Y = y) = P (h(X) = x) = P (X = h−^1 (x)) =

x∈h−^1 (y) P^ (X^ =^ x)

  • If X is continous, Y = h(X), then fY (y) = fX^ (h

− (^1) (y) |h′(h−^1 (y))|

3 Examples

1: (2.5.4) Let X ∼ N(0, 1), calculate P (X ≤ −5), P (− 2 ≤ X ≤ 7), P (X ≥ 3) 2: (2.5.5) Y ∼ N(− 8 , 4), calculate P (Y ≤ −5), P (− 2 ≤ Y ≤ 7), P (X ≥ 3) 3: (2.6.3) X ∼ N(μ, σ^2 ), Y = cX + d, where c > 0. Prove Y ∼ N(cμ + d, c^2 σ^2 ) 4: (2.6.5) X ∼ exp(λ), Y = X^3 , Compute the density fY of Y.