numerical analysis chapter 2 exercises, Assignments of Numerical Methods in Engineering

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Exercise

2 Dfa Tx costonfoD n (^) In bu^ Pu

fee

7 (^0) I

2 0.5 7

3 0.^

I

fat 3cx^ Dlt

E

Lx D

d (^2)

F

0 Fcb

solution (^) is possible

n (^) In bu^ Pu

fee

1 (^2) 1. 0.25 3. 2

3 0.25 0.^

D

N

7 2 19 6 0 FC 2 Toto g (^2) FC D 2860

Solution is^ not^ possible^

because F 2 7040 Ind FL^ D^28 CO d Ez 1

FED 1270

FEDS ICO

I

n (^) In bu^ Pu

fee

1

5

 - 0 I 0.5 0. - 20.5 I 0. - 0. - 30.5 0. - 0. - 0. 

• 90.  - 0.75 0. - 0. 

• 90.625 0.6875 0. - 60.625 0.6562 0. - 8.96
• 70.6906 0. - 0.6789 0.
• 80.6706 0. - 0. - 9.785 - 0. - 0. - 0. - 1 - 6706 0.6925 0.6925 9. - 11 0.6706 0. - 0.6915 2. - 120. - 0. - 0. - 2.

  • 130.  - 0.69225 0. 

    • 140. 1.278mi - 0. - 0.69225

      - I 2 1.5 0. Fa 

  • 21.5 - 1. - 0.

  • 31.  - 1.75 1. - 0. 

    • 1.  - 1.625 1. - 0. 

• 5 1. - 1.5625 1.53129 0. - 1. - 1.53125 1. - 5.

  • 71.  - 1.5156 1.5078 6. 

• 81.  - 1.5156 1. - 6. - 1.5227 1.5156 1.5236 2. g - 101. - 1. - 7.5126 7. - 1.5227 1. - 1.51885 0. 

      • 121.  - 1. - 1. 

      • 131. 1.94g - 1. - 1.5125 5.

  • 141.  - 1. - 1. 

    - 15 1.5121 1. op - 1. 

16 1.5121 (^) 1.5127 1.5122 1 ooh