NUMERİCAL CODES THEİR DİSCRETİZATİON etc., Study Guides, Projects, Research of Numerical Methods in Engineering

THERE ARE SOME CODES FOR NUMERİCAL APPROACH THAT DEFİNES DİSCRETZATİON AND DEVELOPMENT OF THE CODE İT EXPLAİNS HOW THE FOLLOWİNG MATLAB CODES ARE CREATED

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2022/2023

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To develop an explicit scheme to solve the advection-diffusion equation numerically, we can use a
finite difference approximation. Let's start by discretizing the equation in both time and space.
Discretization in Time:
We'll use a forward difference approximation for the time derivative:
𝜕𝑐/𝜕𝑡 ≈ (𝑐ᵢⱼ¹ - 𝑐ᵢⱼ) / Δ𝑡
Discretization in Space:
We'll use a centered difference approximation for the spatial derivatives:
𝜕²𝑐/𝜕𝑥² ≈ (𝑐ᵢ⁺¹ⱼ - 2𝑐ᵢⱼ + 𝑐ᵢ⁻¹ⱼ) / Δ𝑥²
𝜕𝑐/𝜕𝑥 ≈ (𝑐ᵢ⁺¹ⱼ - 𝑐ᵢ⁻¹ⱼ) / (2Δ𝑥)
Now, substitute these approximations into the advection-diffusion equation:
(𝑐ᵢⱼ¹ - 𝑐ᵢⱼ) / Δ𝑡 = 𝐷 (𝑐ᵢ⁺¹ⱼ - 2𝑐ᵢⱼ + 𝑐ᵢ⁻¹ⱼ) / Δ𝑥² - 𝑈 (𝑐ᵢ⁺¹ⱼ - 𝑐ᵢ⁻¹ⱼ) / (2Δ𝑥) - 𝑘𝑐ᵢⱼ
Where i represents the spatial index (along x-axis) and j represents the temporal index (along t-axis).
Now, rearrange the equation to solve for the unknown concentration at the next time step, cᵢⱼ¹:
cᵢⱼ⁺¹ = cᵢⱼ + (Δ𝑡 / Δ𝑥²) * D * (cᵢ⁺¹ⱼ - 2cᵢⱼ + cᵢ⁻¹ⱼ) - (Δ𝑡 / (2Δ𝑥)) * U * (cᵢ⁺¹ⱼ - cᵢ⁻¹ⱼ) - Δ𝑡 * k * cᵢⱼ
Now, we can proceed with the numerical simulation using the given parameters and the derived
explicit scheme.
a) Steady Condition:
In the steady-state condition, the concentration does not change with time. We can solve the
equation iteratively until the solution converges to a steady state. In this case, we'll simulate until the
change in concentration between two consecutive time steps is below a certain threshold.
Initialize parameters and variables:
Length of the tank (L) = 10 m
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To develop an explicit scheme to solve the advection-diffusion equation numerically, we can use a finite difference approximation. Let's start by discretizing the equation in both time and space. Discretization in Time: We'll use a forward difference approximation for the time derivative: 𝜕𝑐/𝜕𝑡 ≈ (𝑐ᵢⱼ⁺¹ - 𝑐ᵢⱼ) / Δ𝑡 Discretization in Space: We'll use a centered difference approximation for the spatial derivatives: 𝜕²𝑐/𝜕𝑥² ≈ (𝑐ᵢ⁺¹ⱼ - 2 𝑐ᵢⱼ + 𝑐ᵢ⁻¹ⱼ) / Δ𝑥² 𝜕𝑐/𝜕𝑥 ≈ (𝑐ᵢ⁺¹ⱼ - 𝑐ᵢ⁻¹ⱼ) / (2Δ𝑥) Now, substitute these approximations into the advection-diffusion equation: (𝑐ᵢⱼ⁺¹ - 𝑐ᵢⱼ) / Δ𝑡 = 𝐷 (𝑐ᵢ⁺¹ⱼ - 2 𝑐ᵢⱼ + 𝑐ᵢ⁻¹ⱼ) / Δ𝑥² - 𝑈 (𝑐ᵢ⁺¹ⱼ - 𝑐ᵢ⁻¹ⱼ) / (2Δ𝑥) - 𝑘𝑐ᵢⱼ Where i represents the spatial index (along x-axis) and j represents the temporal index (along t-axis). Now, rearrange the equation to solve for the unknown concentration at the next time step, cᵢⱼ⁺¹: cᵢⱼ⁺¹ = cᵢⱼ + (Δ𝑡 / Δ𝑥²) * D * (cᵢ⁺¹ⱼ - 2cᵢⱼ + cᵢ⁻¹ⱼ) - (Δ𝑡 / (2Δ𝑥)) * U * (cᵢ⁺¹ⱼ - cᵢ⁻¹ⱼ) - Δ𝑡 * k * cᵢⱼ Now, we can proceed with the numerical simulation using the given parameters and the derived explicit scheme. a) Steady Condition: In the steady-state condition, the concentration does not change with time. We can solve the equation iteratively until the solution converges to a steady state. In this case, we'll simulate until the change in concentration between two consecutive time steps is below a certain threshold. Initialize parameters and variables: Length of the tank (L) = 10 m

Diffusion coefficient (D) = 100 m²/min Velocity in the x-direction (U) = 1 m/min Reaction rate (k) = 0.15 min⁻¹ Inflow concentration (c_inflow) = 100 mg/m³ Initial concentration (c_initial) = 0 mg/m³ Time step size (Δt) = 0.005 min Spatial step size (Δx) = 1 m Threshold for convergence ( User continue ChatGPT Threshold for convergence (convergence_threshold) = 1e-6 mg/m³ Determine the number of spatial and temporal grid points: Number of spatial grid points (N_x) = L / Δx Number of temporal grid points (N_t) = T / Δt, where T = 100 min Initialize the concentration matrix: Create a matrix C of size (N_x + 1) x (N_t + 1) to store concentration values at each grid point. Set the initial concentration values: C[:, 0] = c_initial Perform the explicit time-stepping iteration until convergence: Set the maximum number of iterations (max_iterations) to prevent an infinite loop. Initialize the iteration counter (iteration) to 0. Initialize the change in concentration (delta_c) to a large value (e.g., convergence_threshold + 1). Start the iteration loop:

% Parameters L = 10; % Length of the tank (m) D = 100; % Diffusion coefficient (m^2/min) U = 1; % Velocity in the x-direction (m/min) k = 0.15; % Reaction rate (min^-1) c_inflow = 100; % Inflow concentration (mg/m^3) c_initial = 0; % Initial concentration (mg/m^3) T = 100; % Total simulation time (min) dt = 0.005; % Time step size (min) dx = 1; % Spatial step size (m) % Derived parameters Nx = L / dx; % Number of spatial grid points Nt = T / dt; % Number of temporal grid points % Initialize concentration matrix C = zeros(Nx+1, Nt+1); C(:, 1) = c_initial; % Perform explicit time-stepping iteration convergence_threshold = 1e-6; % Convergence threshold max_iterations = 10000; % Maximum number of iterations delta_c = convergence_threshold + 1; % Initialize change in concentration iteration = 0; % Iteration counter while delta_c > convergence_threshold && iteration < max_iterations delta_c = 0; for j = 1:Nt for i = 2:Nx C(i, j+1) = C(i, j) + (dt / dx^2) * D * (C(i+1, j) - 2 * C(i, j) + C(i-1, j)) ...

  • (dt / (2 * dx)) * U * (C(i+1, j) - C(i-1, j)) - dt * k * C(i, j); delta_c = delta_c + abs(C(i, j+1) - C(i, j)); end end iteration = iteration + 1; end if iteration == max_iterations warning('Convergence not achieved within the specified iterations.'); end % Plot the final resulting concentration versus x x = linspace(0, L, Nx+1); final_concentration = C(:, end); plot(x, final_concentration); xlabel('Distance along the tank''s longitudinal axis (m)'); ylabel('Concentration (mg/m^3)'); title('Final Concentration Distribution'); Make sure to run this code in MATLAB, and it will perform the simulation and plot the final concentration distribution versus the distance along the tank's longitudinal axis.