Objeckves:, Slides of Genetics

Lab: Modeling Color blindness (60). • So that we can… – Use Punneq Squares, Pedigrees and Models to show how sex-linked traits are inherited ...

Typology: Slides

2022/2023

Uploaded on 02/28/2023

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Objec&ves:*
Today*we*will…*
Debrief*Pedigree*Prac&ce*Packet*
Notes*on*sex-linked*traits*(15*min)*
Lab:**Modeling*Color*blindness*(60)*
So*that*we*can…*
Use*PunneM*Squares,*Pedigrees*and*Models*to*
show*how*sex-linked*traits*are*inherited.*
Explain*why*it*is*much*more*likely*for*men*to*be*
color*blind*than*women.*
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Objec&ves:

  • Today we will…
    • Debrief Pedigree Prac&ce Packet
    • Notes on sex-linked traits (15 min)
    • Lab: Modeling Color blindness (60)
  • So that we can…
    • Use PunneM Squares, Pedigrees and Models to show how sex-linked traits are inherited.
    • Explain why it is much more likely for men to be color blind than women.

Bell Work:

Please answer the ques&ons at the top of

your notes sheet.

Gene Linkage:

Dad’s Chromosomes: Dad’s Sperm Cell:

Solve:

1)Is the trait shown

here dominant or

recessive?

2)Identify 1 individual

who provides

evidence of this.

3)What else do you

notice about the

individuals affected?

Could you be color blind?

Look at these pictures and write down the numbers hidden in the dots in your notes!

Color Blindness:

Color Blind = Not able to tell the difference

between certain colors

Normal Vision Color Blind Vision

Color Blindness:

Color blindness is much more common

in men than in women.

It’s a “sex-linked” trait.

Lab: Modeling Color Blindness

Debrief:

It is possible for a woman to be color blind. Describe the possible parent genotypes that would result in a female child who is color blind. (Hint: There is more than 1 possibility.)

Pedigree Prac&ce Problem (A):

The probability that baby Addams has webbed feet is ¼ or 25%

Pedigree Prac&ce Problem (B):

One couple has a son and daughter with normal pigmenta&on and a son that is an albino. Another couple has one son and two daughters with normal pigmenta&on. The daughter from the first couple has three children with the son of the second couple. Their son and one daughter have albinism; their other daughter has normal pigmenta&on.

  1. Individuals II-1, III-1, and III-2 must be homozygous recessive because they have the albinism trait. Individuals II-3 and II-4 must be heterozygous because they have children with albinism. All others must have at least 1 dominant allele because they do not have albinism. However, we cannot determine their other allele.

Pedigree Prac&ce Problem (D):

4. III-

5. 75% because both parents must be

heterozygous

8. The punneM square showing the cross between

Aa and aa represents that couple.

Homework:

  • The completed color blindness lab will be due on

TUESDAY.

  • Friday, we will be looking at a case study –

hemophilia in the royal family