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OCR GCSE Maths Formulae, Exams of Finance

Chamberlain College of NursingFinance

Difference of two squares - ANS-a² - b² = (a + b)(a - b) The Quadratic Formula – ANS - Gradient of a line - ANS-change in y ÷ change in x Equation of a straight line - ANS-y = mx + c Equation of a circle with centre (0,0) - ANS-x² + y² = r²

Typology: Exams

2024/2025

Available from 04/17/2025

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OCR GCSE Maths Formulae
Difference of two squares - ANS-a² - b² = (a + b)(a - b)
The Quadratic Formula – ANS
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Gradient of a line - ANS-change in y ÷ change in x
Equation of a straight line - ANS-y = mx + c
Equation of a circle with centre (0,0) - ANS-x² + y² = r²
Compound interest - ANS-
Speed, Distance and Time - ANS-speed = distance ÷ time
Density, Mass and Volume - ANS-density = mass ÷ volume
Pressure, Force and Area - ANS-pressure = force ÷ area
Sum of Exterior Angles = - ANS-360°
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OCR GCSE Maths Formulae

Difference of two squares - ANS-a² - b² = (a + b)(a - b) The Quadratic Formula – ANS

Gradient of a line - ANS-change in y ÷ change in x Equation of a straight line - ANS-y = mx + c Equation of a circle with centre (0,0) - ANS-x² + y² = r² Compound interest - ANS- Speed, Distance and Time - ANS-speed = distance ÷ time Density, Mass and Volume - ANS-density = mass ÷ volume Pressure, Force and Area - ANS-pressure = force ÷ area Sum of Exterior Angles = - ANS-360°

Sum of Interior Angles = - ANS-(n - 2) × 180 Exterior Angle = - ANS-360° ÷ n Interior Angle = - ANS-180° - exterior angle Area of a triangle - ANS-½ × b × h Area of a parallelogram - ANS-b × h Area of a trapezium - ANS-½(a + b) × h Area of a circle - ANS-πr² Circumference of a circle - ANS-2πr Area of a circle sector - ANS-(θ ÷ 360) × full area of the circle Length of an arc - ANS-(θ ÷ 360) × full circumference of the circle Surface area of a sphere - ANS-4πr² Surface area of a cone - ANS-πr² + πrl Surface area of a cylinder - ANS-2πr² + 2πrh Volume of a prism - ANS-cross sectional area × length Volume of a cylinder - ANS-πr²h Volume of a sphere - ANS-(4÷3)πr³ Volume of a pyramid - ANS-(1÷3)bh Volume of a cone - ANS-(1÷3)πr²h Pythagoras' Theorem - ANS-a² + b² = c² Volume of a frustum - ANS-volume of original cone - volume of removed cone sin x - ANS-opposite ÷ hypotenuse (SOH) cos x - ANS-adjacent ÷ hypotenuse (CAH) tan x - ANS-opposite ÷ adjacent (TOA)