Ordinary differential equation , Exams of Mathematics

Ordinary differential equation

Typology: Exams

2016/2017

Uploaded on 10/18/2017

OSAMA-ALSATTARI
OSAMA-ALSATTARI 🇵🇸

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Find the general solution for the ODF : ; (x + 1)e* ly! = ~ (y + 2e%e*(2 + x + e*) Solution: dy e* (x +1) x+1 = Qe dy = ax GrDeerarxie) Ft ay. x+1+1-1+e*-e Thus, | (y + 2Z)e” dy = [eee x+2+e*-(1+4+e*) eo ee 1+e Z2+x+e7 Hence,e’(y +1) = [ax — As aconsequence,e*(y +1) =x—In(2+x+e*) +e MR.OSAMA A.A.ALSATTARI _eeEeC Zee